Write a program that reads 12 integers into a 2D integer array with 4 rows and 3 columns. The program then outputs the 2D array in reverse order according to both rows and columns.
Ex: If the input is:
5 7 3
6 4 3
5 6 9
5 2 8
then the output is:
8 2 5
9 6 5
3 4 6
3 7 5
For coding simplicity, output a space after every integer, including the last one on each row.
#include <iostream>
using namespace std;
int main() {
const int ROWS = 4;
const int COLS = 3;
int arr[ROWS][COLS];
int i, j;
for(i = 0; i < ROWS; i++){
for(j = 0; j < COLS; j++){
cin>>arr[i][j];
}
}
cout << arr[3][2] << " " << arr[3][1] << " " << arr[3][0] << " " << endl;
cout << arr[2][2] << " " << arr[2][1] << " " << arr[2][0] << " "<< endl;
cout << arr[1][2] << " " << arr[1][1] << " " << arr[1][0] << " "<< endl;
cout << arr[0][2] << " " << arr[0][1] << " " << arr[0][0] << " "<< endl;
return 0;
}
I ended up having to hardcode this question because I couldnt find a way to reverse the 2D array with a loop and get it to be outputted in the form of a graph. Is there a way i could reverse the 2D array using for loops and would it be possible to be able to change the amount of rows and columns and still output the corresponding graph of values?
try this:
#include <iostream>
using namespace std;
int main() {
const int ROWS = 4;
const int COLS = 3;
int arr[ROWS][COLS];
int i, j;
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
cin >> arr[i][j];
}
}
// output the reversed array
for (int i = ROWS - 1; i >= 0; i--) {
for (int j = COLS - 1; j >= 0; j--) {
cout << arr[i][j] << " ";
}
cout << endl;
}
return 0;
}
You can reverse a 2D array using nested for loops, try
#include <iostream>
using namespace std;
int main() {
const int ROWS = 4;
const int COLS = 3;
int arr[ROWS][COLS];
int i, j;
// Input the values into the 2D array
for(i = 0; i < ROWS; i++) {
for(j = 0; j < COLS; j++) {
cin >> arr[i][j];
}
}
// Reverse the rows and columns of the 2D array
for(i = ROWS - 1; i >= 0; i--) {
for(j = COLS - 1; j >= 0; j--) {
cout << arr[i][j] << " ";
}
cout << endl;
}
return 0;
}
As mentioned in comments below if you don't know ROWS and COLS size at compile time dynamically allocate the memory for 2D array(arr) in C++ using new operator.
There is very little point reading the data into a 2D array for this program. A std::vector would do the trick, sized with ROWS * COLS values. You then have the benefit of being able to read those dimensions from the user, which addresses the second part of your question.
size_t size = ROWS * COLS;
// Read data
std::vector<int> data;
data.reserve(size);
for (int value; std::cin >> value; )
{
data.push_back(value);
}
// Validate data
if (data.size() != size)
{
std::cerr << "Unexpected end of input!\n";
return EXIT_FAILURE;
}
When outputting, you can use a reverse iterator through the vector, and simply write a newline every COLS values.
// Output in reverse
int col = 0;
for (auto it = data.rbegin(); it != data.rend(); it++)
{
std::cout << *it << " ";
if (++col == COLS)
{
std::cout << "\n";
col = 0;
}
}
You can even easily fix the "space at the end of the line" problem by adjusting your output loop as follows:
// Output in reverse
int col = 0;
for (auto it = data.rbegin(); it != data.rend(); it++)
{
std::cout << *it;
if (++col == COLS)
{
std::cout << "\n";
col = 0;
}
else
{
std::cout << " ";
}
}
I am trying to write a program that takes user input for the number of hours worked by 6 employees of a company to store in a two-dimensional array and prints the output in the following format:
Employee Number Hours
01 a
02 b
03 c
04 d
05 e
06 f
where a-f would be the user entered integer values.
I have experimented with several methods but am unable to get my desired output. I am attaching the recent attempt:
#include <iostream>
using namespace std;
int main()
{
int array[6][2]; // 6 by 2 matrix to store employee name and hours worked
int i, j;
cout << "Enter the number of hours worked by 6 employees: " << endl;
for (int i = 0; i < 6; i++)
{
for (int j = 0; j < 2; j++)
{
cin >> array[i][j];
cout << array[i][j] << "\t" << endl;
break;
}
cout << endl;
}
}
What changes should I make to get the required output?
You should take the input first. Then in order to print with column name you should first print those column names and then print the values.
Your code should be like this -
#include <iostream>
using namespace std;
int main()
{
int array[6][2]; // 6 by 2 matrix to store employee name and hours worked
int i, j;
cout << "Enter the number of hours worked by 6 employees: " << endl;
for (int i = 0; i < 6; i++)
{
for (int j = 0; j < 2; j++)
{
cin >> array[i][j];
}
}
cout << "Employee Number \t Hours" << endl;
for (int i = 0; i < 6; i++)
{
for (int j = 0; j < 2; j++)
{
cout << array[i][j] << "\t\t\t ";
}
cout << endl;
}
}
Output:
Edit:
For your requirement from the comment, new code will be
int main()
{
int array[6][2]; // 6 by 2 matrix to store employee name and hours worked
int i, j;
cout << "Enter the number of hours worked by 6 employees: " << endl;
cout << "Employee Number \t Hours" << endl;
for (int i = 0; i < 6; i++)
{
for (int j = 0; j < 2; j++)
{
cin >> array[i][j];
cout << array[i][j] << "\t\t\t ";
}
cout << endl;
}
}
So I'm trying to create an array that contains some user inputted names, and then associate those names with letter grades from tests (ex: A, B, C, D, F). My question is, how would I use an array to accept the user inputted names?
EDIT:
Sorry this is a bit long, I don't know what part to put that would help out. Totally new to C++ and I can't seem to find anything online regarding the matter, lol.
Here is some code. This program currently asks the user for test scores, then displays and drops the lowest test score, and finally, calculates the average of the scores without the lowest one. The end goal is to ask the user for 5 students names, and 4 scores for each student, then dropping the lowest score for each student and calculating the averages of ALL scores inputted regardless of student.
#include <iostream>
#include <string>
using namespace std;
void getScore(int &);
int findLowest(int [], int);
void calcAverage(int [], int);
int main () {
const int NUM_SCORES = 5;
int scores[NUM_SCORES];
cout << "Welcome to test averages." << endl;
cout << "Please enter scores for " << NUM_SCORES << " students." << endl;
cout << endl;
for (int i = 0; i < NUM_SCORES; i++) {
getScore(scores[i]);
}
for (int i = 0; i < NUM_SCORES; i++) {
cout << "Score " << (i + 1) << ": " << scores[i] << endl;
}
cout << endl;
cout << "The lowest of these scores is " << findLowest(scores, NUM_SCORES) << endl;
calcAverage(scores, NUM_SCORES);
return 0;
}
void getScore(int & s) {
s = -1;
cout << "Please enter a test score: ";
cin >> s;
while (s < 0 || s > 100) {
cout << "Score range must be from 0-100" << endl;
cout << "Please re-enter a score: ";
cin >> s;
}
}
int findLowest(int theArray [], int theArraySize) {
int lowest = theArray[0];
for (int i = 1; i < theArraySize; i++) {
if (theArray[i] < lowest) {
lowest = theArray[i];
}
}
return lowest;
}
void calcAverage(int theArray [], int theArraySize) {
int sum = 0;
for (int i = 0; i < theArraySize; i++) {
sum += theArray[i];
}
double average = (sum - findLowest(theArray, theArraySize)) / (theArraySize - 1.0);
cout << "The average is " << average << endl;
}
Try getline from #include <string>
std::string names[5];
for (int i = 0; i < 5; ++i){
getline(std::cin, names[i]);
}
I am Having Problem with Passing a 2D array to a c++ Function. The function is supposed to print the value of 2D array. But getting errors.
In function void showAttributeUsage(int)
Invalid types for int(int) for array subscript.
I know the problem is with the syntax in which I am passing the particular array to function but I don't know how to have this particular problem solved.
Code:
#include <iostream>
using namespace std;
void showAttributeUsage(int);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
int attVal[qN][aN];
cout << "\nEnter Attribute Usage Values" << endl;
for(int n = 0; n < qN; n++) { //for looping in queries
cout << "\n\n***************** COLUMN " << n + 1 << " *******************\n\n";
for(int i = 0; i < aN; i++) { //for looping in Attributes
LOOP1:
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if((attVal[n][i] > 1) || (attVal[n][i] < 0)) {
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
goto LOOP1; //if wrong input value
}
}
}
showAttributeUsage(attVal[qN][aN]);
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
getch();
return 0;
}
void showAttributeUsage(int att)
{
int n = 0, i = 0;
while(n != '\0') {
while(i != '\0') {
cout << att[n][i] << " ";
i++;
}
cout << endl;
n++;
}
}
I really suggest to use std::vector : live example
void showAttributeUsage(const std::vector<std::vector<int>>& att)
{
for (std::size_t n = 0; n != att.size(); ++n) {
for (std::size_t i = 0; i != att.size(); ++i) {
cout << att[n][i] << " ";
}
cout << endl;
}
}
And call it that way:
showAttributeUsage(attVal);
Looking at your code, I see no reason why you can't use std::vector.
First, your code uses a non-standard C++ extension, namely Variable Length Arrays (VLA). If your goal is to write standard C++ code, what you wrote is not valid standard C++.
Second, your initial attempt of passing an int is wrong, but if you were to use vector, your attempt at passing an int will look almost identical if you used vector.
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
typedef std::vector<int> IntArray;
typedef std::vector<IntArray> IntArray2D;
using namespace std;
void showAttributeUsage(const IntArray2D&);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
IntArray2D attVal(qN, IntArray(aN));
//... Input left out ...
showAttributeUsage(attVal);
return 0;
}
void showAttributeUsage(const IntArray2D& att)
{
for_each(att.begin(), att.end(),
[](const IntArray& ia) {std::copy(ia.begin(), ia.end(), ostream_iterator<int>(cout, " ")); cout << endl;});
}
I left out the input part of the code. The vector uses [] just like a regular array, so no code has to be rewritten once you declare the vector. You can use the code given to you in the other answer by molbdnilo for inputing the data (without using the goto).
Second, just to throw it into the mix, the showAttributeUsage function uses the copy algorithm to output the information. The for_each goes throw each row of the vector, calling std::copy for the row of elements. If you are using a C++11 compliant compiler, the above should compile.
You should declare the function like this.
void array_function(int m, int n, float a[m][n])
{
for (int i = 0; i < m; i++)
for (int j = 0; j < n; j++)
a[i][j] = 0.0;
}
where you pass in the dimensions of array.
This question has already been answered here. You need to use pointers or templates. Other solutions exists too.
In short do something like this:
template <size_t rows, size_t cols>
void showAttributeUsage(int (&array)[rows][cols])
{
for (size_t i = 0; i < rows; ++i)
{
std::cout << i << ": ";
for (size_t j = 0; j < cols; ++j)
std::cout << array[i][j] << '\t';
std::cout << std::endl;
}
}
You're using a compiler extension that lets you declare arrays with a size determined at runtime.
There is no way to pass a 2D array with such dimensions to a function, since all but one dimension for an array as a function parameter must be known at compile time.
You can use fixed dimensions and use the values read as limits that you pass to the function:
const int max_queries = 100;
const int max_attributes = 100;
void showAttributeUsage(int array[max_queries][max_attributes], int queries, int attributes);
int main()
{
int attVal[max_queries][max_attributes];
int qN = 0;
int aN = 0;
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
cout << "\nEnter Attribute Usage Values" << endl;
for (int n = 0; n < qN; n++)
{
cout << "\n\n***************** COLUMN " << n + 1 <<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad_input = true;
while (bad_input)
{
bad_input = false; // Assume that input will be correct this time.
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad_input = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal, qN, aN);
getch();
return 0;
}
void showAttributeUsage(int att[max_queries][max_attributes], int queries, int attributes)
{
for (int i = 0; i < queries; i++)
{
for (int j = 0; j < attributes; j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
For comparison, the same program using std::vector, which is almost identical but with no size limitations:
void showAttributeUsage(vector<vector<int> > att);
int main()
{
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
vector<vector<int> > attVal(qN, vector<int>(aN));
cout << "\nEnter Attribute Usage Values"<<endl;
for (int n = 0; n < qN; n++)
{
cout<<"\n\n***************** COLUMN "<<n+1<<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad = true;
while (bad)
{
bad = false;
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal);
getch();
return 0;
}
void showAttributeUsage(vector<vector<int> > att);
{
for (int i = 0; i < att.size(); i++)
{
for (int j = 0; j < att[i].size(); j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
The Particular Logic worked for me. At last found it. :-)
int** create2dArray(int rows, int cols) {
int** array = new int*[rows];
for (int row=0; row<rows; row++) {
array[row] = new int[cols];
}
return array;
}
void delete2dArray(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
delete [] ar[row];
}
delete [] ar;
}
void loadDefault(int **ar, int rows, int cols) {
int a = 0;
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
ar[row][col] = a++;
}
}
}
void print(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
cout << " | " << ar[row][col];
}
cout << " | " << endl;
}
}
int main () {
int rows = 0;
int cols = 0;
cout<<"ENTER NUMBER OF ROWS:\t";cin>>rows;
cout<<"\nENTER NUMBER OF COLUMNS:\t";cin>>cols;
cout<<"\n\n";
int** a = create2dArray(rows, cols);
loadDefault(a, rows, cols);
print(a, rows, cols);
delete2dArray(a, rows, cols);
getch();
return 0;
}
if its c++ then you can use a templete that would work with any number of dimensions
template<typename T>
void func(T& v)
{
// code here
}
int main()
{
int arr[][7] = {
{1,2,3,4,5,6,7},
{1,2,3,4,5,6,7}
};
func(arr);
char triplestring[][2][5] = {
{
"str1",
"str2"
},
{
"str3",
"str4"
}
};
func(triplestring);
return 0;
}
I'm having trouble generating and inserting numbers inside the Board. Here is what I have so far:
enter code here
#include <iostream>
#include <string>
#include <cstring>
#include <vector>
using namespace std;
bool Valid_Set(int line[])
{
bool found = true;
for (int t = 1; (t <= 9 && found); ++t)
{
found = false;
for (int i = 0; i < 9; ++i)
if (line[i] == t) found = true;
}
return found; // returns true if all value 1-9 are in array.
}
bool Valid_Matrix(int sud[9][9])
{
int i, j, check[9];
bool valid = true;
// check each row
for (j = 0; (j < 9) && valid; ++j)
{
for (i = 0; i < 9; ++i)
check[i] = sud[i][j];
valid = Valid_Set(check);
}
// check each column
for (j = 0; (j < 9) && valid; ++j)
{
for (i = 0; i < 9; ++i)
check[i] = sud[j][i];
valid = Valid_Set(check);
}
// check 3x3 area
for (i = 0; (i < 9) && valid; i += 3)
{
for (j = 0; (j < 9) && valid; j += 3)
{
int t = 0;
for (int x = 0; x < 3; ++x)
for (int y = 0; y < 3; ++y)
check[t++] = sud[x + i][y + j];
valid = Valid_Set(check);
}
}
return valid;
}
void numGenerator(int A[]){
for (int i=0; i<9; i++){
A[i]=(1+rand()%9);
}
}
bool check_for_validity(int A[]){
int counter=0;
while (counter!=9){
numGenerator(A);
counter++;
}
for (int i=0; i<9; i++)
for (int j=0; j<9; j++){
if(A[j]==A[i])
numGenerator(A);
}
return true;
}
void main (){
//Descriptions and genral ideas
cout << "WELCOME TO SUDOKU " << endl;
cout << endl;
cout << "RULES: "<< endl;
cout << endl;
cout << "->You'll be given a 9x9 board with some numbers depending on which level of difficulty you choose to play."<< endl;
cout << endl;
cout << "->You have to arrange numbers from 1 to 9 so that a number shows up once in one row, one column and in a 3x3 box." << endl;
cout << endl;
cout << "So, let's get started" << endl;
cout << endl;
cout <<endl;
char dash[9][9];
for (int array=0; array<9; array++) {
for (int array2=0; array2<9; array2++) {
dash[array][array2]='_';
}
}
char row[9];
char column[9];
int num[81];
int num2[9][9];
int length;
length=strlen(row);
//Replaces the _'s in the specified rows/columns and replaces them with the integer the user specified.
for (int i=0; i<length; i++) {
dash[row[i]][column[i]]=num[i]+'0';
}
//Builds the Sudoko board and outputs the full 9x9 array.
cout << " 0 1 2 3 4 5 6 7 8 " << endl;
cout << "-----------------------------------------" << endl;
int i=0;
for (int count=0; count<3; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << i << endl;
i++;
}
cout << "-----------------------------------------" << endl;
int j=3;
for (int count=3; count<6; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << j << endl;
j++;
}
cout <<"-----------------------------------------" << endl;
int z=6;
for (int count=6; count<9; count++) {
for (int count2=0; count2<3; count2++) {
cout << "||_" << dash[count][count2*3] << "_|_" << dash[count][count2*3+1] << "_|_" << dash[count][count2*3+2] << "_";
}
cout << "||" << z << endl;
z++;
}
cout << "-----------------------------------------" << endl;
for (int row = 0; row < 9; row++) {
cout << "Enter values for row " << row + 1 << " : ";
for (int col = 0; col < 9; col++)
cin >> dash[row][col];
cout << endl << endl;
}
system("pause");
}
This whole section is wrong
char row[9];
char column[9];
int num[81];
int num2[9][9];
int length;
length=strlen(row);
//Replaces the _'s in the specified rows/columns and replaces them with the integer the user specified.
for (int i=0; i<length; i++) {
dash[row[i]][column[i]]=num[i]+'0';
}
You are using row and column even though they haven't got any values. Most likely this will crash your program.
Hard to know what you expected this to do. Perhaps you could explain?
Here's a suggestion for inputing values. Maybe you'll find it useful
// get the user's values
int row, column, value;
cout << "Enter a row number, column number, and value. All numbers should be between 1 and 9\n";
cin >> row >> column >> value;
// put the value in the board, add '0' to convert the integer to a digit
dash[row][column] = value + '0';