xsl:variable contains nodeset. How to output nth node of variable? - xslt

I am transforming an XML document. There is an attribute #prettydate that is a string similar to "Friday, May 7, 2010". I want to split that string and add links to the month and the year. I am using the exslt:strings module and I can add any other necessary EXSLT module.
This is my code so far:
<xsl:template match="//calendar">
<xsl:variable name="prettyparts">
<xsl:value-of select="str:split(#prettydate,', ')"/>
</xsl:variable>
<table class='day'>
<thead>
<caption><xsl:value-of select="$prettyparts[1]"/>,
<a>
<xsl:attribute name='href'><xsl:value-of select="$baseref"/>?date=<xsl:value-of select="#highlight"/>&per=m</xsl:attribute>
<xsl:value-of select='$prettyparts[2]'/>
</a>
<xsl:value-of select='$prettyparts[3]'/>,
<a>
<xsl:attribute name='href'><xsl:value-of select="$baseref"/>?date=<xsl:value-of select="#highlight"/>&per=y</xsl:attribute>
<xsl:value-of select='$prettyparts[4]'/>
</a>
</caption>
<!--etcetera-->
I have verified, by running $prettyparts through a <xml:for-each/> that I am getting the expected nodeset:
<token>Friday</token>
<token>May</token>
<token>7</token>
<token>2010</token>
But no matter which way I attempt to refer to a particular <token> directly (not in a foreach) I get nothing or various errors to do with invalid types. Here's some of the syntax I've tried:
<xsl:value-of select="$prettyparts[2]"/>
<xsl:value-of select="$prettyparts/token[2]"/>
<xsl:value-of select="exsl:node-set($prettyparts/token[2])"/>
<xsl:value-of select="exsl:node-set($prettyparts/token)[2]"/>
Any idea what the expression ought to be?
ETA: Thanks to #DevNull's suggestion, the correct expression is:
<xsl:value-of select="exsl:node-set($prettyparts)[position()=2]"/>
and, I have to set the variable this way:
<xsl:variable name="prettyparts" select="str:split(#prettydate,', ')" />

Try using [position()=2] instead of [2] in your predicates.
Example:
<xsl:value-of select="$prettyparts[position()=2]"/>

Related

confusing error thown while trying to match templates

I've the below XML line of code.
<entry colname="col3" align="left" valign="top"><para>grandchild, cousin, <content-style font-style="italic">etc</content-style>., shall be described as “lawful” and “one of the next-of-kin” or “only next-of-kin”.</para></entry>
and below XSL
<xsl:template match="entry" name="entry">
<xsl:choose>
<xsl:when test="./#namest">
<xsl:variable name="namest" select="#namest" />
<xsl:variable name="nameend" select="#nameend" />
<xsl:variable name="namestPos" select="count(ancestor::tgroup/colspec[#colname=$namest]/preceding-sibling::colspec)" />
<xsl:variable name="nameendPos" select="count(ancestor::tgroup/colspec[#colname=$nameend]/preceding-sibling::colspec)" />
<td colspan="{$nameendPos - $namestPos + 1}" align="{#align}">
<xsl:apply-templates select="child::node()[not(self::page)]" />
</td>
</xsl:when>
<xsl:otherwise>
<td>
<xsl:if test="./#morerows">
<xsl:attribute name="rowspan">
<xsl:value-of select="number(./#morerows)+1" />
</xsl:attribute>
</xsl:if>
<xsl:if test="./#align">
<xsl:attribute name="align">
<xsl:value-of select="#align" />
</xsl:attribute>
</xsl:if>
<xsl:if test="./#valign">
<xsl:attribute name="valign">
<xsl:value-of select="#valign" />
</xsl:attribute>
</xsl:if>
<xsl:for-each select="para">
<div class="para">
<xsl:choose>
<xsl:when test="../#colname='col3' and contains(./text(),'.')">
<xsl:variable name="strl">
<xsl:value-of select="fn:string-length(fn:substring-before(.,'.'))" />
</xsl:variable>
<xsl:choose>
<xsl:when test="$strl < '6'">
<a href="{concat('er:#SCP_ORD_',//chapter/#num,'/','P',translate(./text(),'.','-'))}">
<xsl:value-of select="./text()" />
</a>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates />
</xsl:otherwise>
</xsl:choose>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates />
</xsl:otherwise>
</xsl:choose>
</div>
</xsl:for-each>
</td>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
and when i run this on my XML in the above mentioned line(the XML given in the sample), it is throwing me an error. and the error is as below.
Wrong occurrence to match required sequence type - Details: - XPTY0004: The supplied sequence ('2' item(s)) has the wrong occurrence to match the sequence type xs:string ('zero or one')
here what i actually was trying to achieve is, i have another table(which is basically a TOC), where in there is some linking needed, and below is such sample entries.
<entry colname="col3" align="right" valign="top"><para>A.1</para></entry>
<entry colname="col3" align="right" valign="top"><para>A.2</para></entry>
here i'm searching if the colname is col3 and if this has a . in it, and the above two cases mentioned are passing and are getting linked successfully, where in the case mentioned in the top is throwing the error, can anyone please suggest some better method to differentiate these two cases, and i use XSLT 2.0.
Thanks
The problem is
contains(./text(),'.')
./text() is not "the text of the current element" but rather the sequence of all text node children of the current element. In the case of
<para>grandchild, cousin, <content-style font-style="italic">etc</content-style>., shall be described as “lawful” and “one of the next-of-kin” or “only next-of-kin”.</para>
there are two such nodes, one containing everything between the <para> and <content-style> tags ("grandchild, cousin, " including the trailing space) and the other containing everything between the </content-style> and the </para>. But the contains function expects its first argument to be a single string, not a sequence of two nodes.
Instead of testing ./text() you probably just need to test .:
contains(., '.')
which is interpreted as the string value of the whole para element, i.e. a single string consisting of the concatenation of all the descendant text nodes (so the whole text "grandchild, cousin, etc., shall be described...").

XSL transformation with link in variable name

I have the following XSL which I render into my HTML:
<xsl:for-each select="user">
<xsl:variable name="exampleurl">
<xsl:choose>
<xsl:when test="objecttype='2'">
Check this out: 
<strong><a class="link" href="http://www.example.com/beinspired">Inspiration</a></strong>.
</xsl:when>
</xsl:choose>
</xsl:variable>
<xsl:value-of select="$exampleurl" />
</xsl:for-each>
However, when I print the variable $exampleurl only the text "Check this out: Inspiration." is printed. But the word "Inspiration" is not a clickable URL like I would want.
How to fix this?
value-of creates a text node, you want
<xsl:copy-of select="$exampleurl" />
(or of course in this case you don't need a variable at all, but I assume that's just the small example?

avoid mismatched tags outputting HTML with XSLT

I'm new to XSLT, and there's one specific thing I don't know how to do, despite hours of searching for the answer.
I'm outputting blocks of HTML (result sets), and sometimes the result is a hyperlink, sometimes it is not.
The simple flow looks like this:
<a...> if #url
some HTML code
</a> if #url
But if I do:
when #url
<a...>
/when
some HTML code
when #url
</a>
/when
... I'm told that I have mismatched tags.
I was using CDATA text for the anchor set, but a lot of messages say that this is a "hack" approach.
I'm trying to avoid having to repeat the entire HTML code block only to include the anchors on only one of them.
How do I do this?
-------edit / additional info-----------
Does this make more sense?
<xsl:template match="Row">
<xsl:choose>
<xsl:when test="#url!=''">
<a><xsl:attribute name="href"><xsl:value-of select="#url" /></xsl:attribute>
</xsl:when>
</xsl:choose>
<img />
<xsl:choose>
<xsl:when test="#url!=''">
</a>
</xsl:when>
</xsl:choose>
</xsl:template>
In XSLT, your output is a tree of nodes. Writing an element node is a single atomic operation; it can't be split into separate operations of writing a start tag and writing an end tag. You can't create half a node.
If you do try to treat <a> and </a> as separate and separable operations, you will get this error, because the stylesheet must be well-formed XML.
So, stand back and explain what you are trying to achieve, and then we can tell you how to achieve it properly in XSLT.
One way to refactor the XSLT to conditionally apply the hyperlink and not repeat the logic to produce the <img/> (or whatever more complex logic you are trying to avoid repeating) is to extract that logic out into a different template(s) as either a named template or a template with a #mode.
For instance:
<xsl:template match="Row">
<xsl:choose>
<xsl:when test="#url!=''">
<a>
<xsl:attribute name="href">
<xsl:value-of select="#url"/>
</xsl:attribute>
<xsl:apply-templates select="." mode="image"/>
</a>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="." mode="image"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<!--The "common" logic to produce an image element, whether or not it will be surrounded by an anchor linking to the #url -->
<xsl:template match="Row" mode="image">
<img/>
</xsl:template>
An alternative way of accomplishing the same thing, but using templates instead of <xsl:choose>:
<xsl:template match="Row[#url]">
<a href="#url">
<xsl:apply-templates select="." mode="image"/>
</a>
</xsl:template>
<xsl:template match="Row">
<xsl:apply-templates select="." mode="image"/>
</xsl:template>
<xsl:template match="Row" mode="image">
<img/>
</xsl:template>

xslt assigning variable value to string literal

I have
<xsl:for-each select="ancestor-or-self::*">
<xsl:variable name="expression" select="name()" ></xsl:variable>
</xsl:for-each>
below I have href and i want to set the value this expression variable in href #######
Delete
I also tried with :
Delete
None of them worked.
Can Anybody help me out how to do that?
Basically my task is to find the expression for current node and send the expression for the same in href?
Adding More Info :
<br/><xsl:for-each select="ancestor-or-self::*">
<xsl:variable name="expression" select="name()" />
</xsl:for-each>
<b>Click Me</b>
when above xsl code is transformed it is giving below error:
Variable or parameter 'expression' is undefined.
In XSLT1.0, you could try setting the variable like so:
<xsl:variable name="expression">
<xsl:for-each select="ancestor-or-self::*">
<xsl:text>/</xsl:text>
<xsl:variable name="name" select="name()"/>
<xsl:value-of select="$name"/>
</xsl:for-each>
</xsl:variable>
So, assuming the following XML structure
<As>
<a>
<Bs>
<b>5</b>
</Bs>
</a>
<a>
<Bs>
<b>9</b>
</Bs>
</a>
<a/>
<a>
<Bs>
<b>12</b>
<b>14</b>
<b>15</b>
</Bs>
</a>
</As>
If you were positioned on the b element with the value of 14, then expression would be set to /As/a/Bs/b
However, this does not take into account multiple nodes with the same name, and so would not be sufficient if you wanted accurate XPath to select the node.
Instead, you could try the following:
<xsl:variable name="expression">
<xsl:for-each select="ancestor-or-self::*">
<xsl:text>/</xsl:text>
<xsl:variable name="name" select="name()"/>
<xsl:value-of select="$name"/>
<xsl:text>[</xsl:text>
<xsl:value-of select="count(preceding-sibling::*[name() = $name]) + 1"/>
<xsl:text>]</xsl:text>
</xsl:for-each>
</xsl:variable>
This would return /As[1]/a[4]/Bs[1]/b[2], which may be what you want.
Very simply, variables are scoped in XSL and exist only within the containing tag. Thus the variable named expression exists only within the for-each block. Also, variables can only be set once. Attempting to set a variable value a second time has no effect.
Therfore you have to declare the variable at or above the level where you want to use it, and put all the code to generate the value inside the variable declaration. If you can use XSLT2, the following will do what you want:
string-join(for $n in ancestor-or-self::* return name($n), '/')
I know it can also be done in XSLT 1 with a recursive template, but I don't have an example handy.

Display different xsl:attribute depending on the ending of a string

I have the following xsl code in an xsl document
<A target="_blank" style="text-decoration=none">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline</xsl:attribute>
<xsl:attribute name="prefix"><xsl:value-of select="FileName"/>: </xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</A>
and in the code-behind I am doing this
newItemNode = xmlDocument.CreateElement("URLFilePath")
newItemNode.InnerText = correctedPath
xmlItemNode.ParentNode.AppendChild(newItemNode)
Now that works fine for word documents. However I need a way in code to check the extension of the file, and display the correct Image and xsl:attribute depending on the If statement.
So the If statement will be like this:-
If correctedPath.ToLower.Contains(".doc") Then
//display the word icon and attributes
Else
//display the excel icon and attributes
End If
Can you please give me some tips and help on how I can achieve this?
Thanks
Just using contains() may generally produce the wrong results (see the test XML document).
What is necessary is a ends-with() function, which is standard in XPath 2.0 and can be implemented in XSLT 1.0 as in the following transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="URLFilePath">
<xsl:variable name="visDoc">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.doc'"/>
</xsl:call-template>
</xsl:variable>
<xsl:variable name="visXls">
<xsl:call-template name="ends-with">
<xsl:with-param name="pEnding" select="'.xls'"/>
</xsl:call-template>
</xsl:variable>
<xsl:choose>
<xsl:when test="$visDoc=1">word_small.gif</xsl:when>
<xsl:when test="$visXls=1">xls_small.gif</xsl:when>
<xsl:otherwise>unknown_small.gif</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template name="ends-with">
<xsl:param name="pEnding"/>
<xsl:value-of select=
"number(substring(.,
string-length() -string-length($pEnding) +1
)
=
$pEnding
)
"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the following test XML document:
<files>
<URLFilePath>myFile.doc</URLFilePath>
<URLFilePath>myFile.xls</URLFilePath>
<URLFilePath>myFile.xls.doc</URLFilePath>
<URLFilePath>myFile.doc.xls</URLFilePath>
</files>
the correct result is produced:
word_small.gif
xls_small.gif
word_small.gif
xls_small.gif
Do note that just using contains() produces incorrect results.
I managed to come up with a solution! Sorry for the late reply but had to work on something else
Here is the code:-
<A target="_blank" style="text-decoration=none">
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<xsl:attribute name="href">viewxls.aspx?doc=<xsl:value-of select="URLFilePath"/>&mode=inline
</xsl:attribute>
<xsl:attribute name="prefix">
<xsl:value-of select="FileName"/>:
</xsl:attribute>
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
</A>
Thanks for all your help guys, really very much appreciated!
A late reply but I hit to two answers that deal with matching end of string with XSLT 1.0 and are very elegant:
https://stackoverflow.com/a/3081205/520567
https://stackoverflow.com/a/3081866/520567
go give them +1
This can be done purely in your XSLT document if you require. For displaying the image, you could use a xsl:choose statement, that tests the URLFilePath element
<xsl:choose>
<xsl:when test="contains(., '.doc')">
<IMG src="images/word_small.gif" border="0"/>
</xsl:when>
<xsl:when test="contains(., '.xls')">
<IMG src="images/excel_small.gif" border="0"/>
</xsl:when>
</xsl:choose>
If you wanted to do this check in the code behind, you could always add extra attributes to your URLFilePath element.
imageAttr = xmlDocument.CreateAttr("image")
If correctedPath.ToLower.Contains(".doc") Then
imageAttr.value = "images/word_small.gif"
Else
imageAttr.value = "images/excel_small.gif"
End If
newItemNode.AppendChild(imageAttr)
And then, in your xls, you can simply use this attribute to set the source attribute of the image
<IMG border="0">
<xsl:attribute name="src"><xsl:value-of select='#image' /></xsl:attribute>
</IMG>