What i'm trying to do is create a template array class that will store values of a data type into an array. I have it working fine with int values, however working with string objects things start to break down.
I've taken out the block of code and tried it on it's own and I do get the same error. I'm sure I've learnt this, and I'm almost positive that the answer is something simple, trying to wrap my head around the pace in which we're learning c++ is a little crazy at times!
My best guess right now, is that I would need to tokenize the string and look for spaces. I tend to over think things though which lead to more confusion - thus me seeking out a answer here!
The code:
// Test String: Hello World this is a String Object
int stringSize = 7;
int count = 0;
string s[stringSize];
cout << "\nEnter " << stringSize << " one-word string values:\n";
while (count < stringSize) {
string tmpVal;
cin >> tmpVal;
s[count] = tmpVal;
count ++;
}
string s[stringSize]; is illegal because stringSize is not a constant. You must either use dynamic memory (i.e. string* s = new string [stringSize];), include stringsize as a template argument (don't do this, it doesn't actually solve the problem), use a fixed size value, or use an existing structure (I'd suggest vector, as in Bill's answer). The code below works fine on my compiler:
int main(int argc, char *argv[]) {
int stringSize = 7;
int count = 0;
string* s = new string [stringSize];
cout << "\nEnter " << stringSize << " one-word string values:\n";
while (count < stringSize) {
string tmpVal;
cin >> tmpVal;
s[count] = tmpVal;
count ++;
}
delete[] s;
}
I am a little confused as to exactly what you're looking for, but I suggest looking into the standard library.
Perhaps something like:
list<string> s;
and then, in the loop use push_back.
I am also confused what is your actual question, because your code works. However, FWIW, I would suggest the following. The changes are: (1) use of const (already suggested by others), (2) use of size_t, (3) change of variable name stringSize to numStrings (because of this I was confused at first glance), and (4) avoiding string copy.
#include <iostream>
#include <string>
using namespace std;
int main()
{
const size_t numStrings = 7;
size_t count = 0;
string s[ numStrings ];
cout << "\nEnter " << numStrings << " one-word string values:\n";
while (count < numStrings) {
cin >> s[ count ];
count++;
}
return 0;
}
Why not read in the entire line, then find all spaces and using the substr method, split the string?
You will need the following methods:
getline()
find_first_of()
substr()
Also, searching around this site for splitting strings in c++ will give you a lot of tips.
First of all, the size of your array should be constant:
const int stringSize = 7;
Secondly, as dbrien said, you should use std::vector unless you're doing this for the learning experience:
std::string tmpVal;
std::vector<std::string> s;
cout << "\nEnter " << stringSize << " one-word string values:\n";
while (cin >> tmpVal)
{
s.push_back(tmpVal);
}
First, the array dimension must be constant, so it should be const int stringsize = 7; Also, I would suggest using std::vector rather than std::list, additionally What was the error?
Not sure what error you're getting, but this is wrong because you need to use a constant integral value to allocate arrays on the stack.. Change:
int stringSize = 7;
int count = 0;
string s[stringSize];
... to:
const int stringSize = 7;
int count = 0;
string s[stringSize];
You can and probably should also use a vector instead of using C-style arrays, or trying to hand roll your own templated array class:
vector<string> s;
const int stringSize = 7;
cout << "\nEnter " << stringSize << " one-word string values:\n";
while (s.size() < stringSize) {
string tmpVal;
cin >> tmpVal;
s.push_back(tmpVal);
}
So it turns out it was the compiler. I was using xCode and getting:
cin_cout(7307) malloc: *** error for object 0x1000072c0: pointer being freed was not allocated
*** set a breakpoint in malloc_error_break to debug
Running the same block in Visual c++ seemed to be ok... Sorry for my stupidity and thanks kindly for all the quick feedback!
Related
This kind of explains it all I really don't know why this is happening, can you guys help? I even made the length constant because I though that could be the problem, but it still happens so I really don't know.
So the problem is that I define length1 as 4, but then after a few times in the for loop, the value just randomly changes...
#include <iostream>
#include <string>
using namespace std;
int uppercase[26] = {65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90};
int lowercase[26] = {97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120,121,122};
string test;
int entered_text[] = {};
int length = 0;
int length1 = 0;
int main() {
cout << "Enter Text:" << endl;
getline (cin, test);
length = test.size();
length1 = 4;
cout << test<< endl;
for (int i = 0; i < length1; i++){
entered_text[i] = test[i];
}
cout << entered_text[0] << endl;
return 0;
}
By looking at your code, it seems you're approaching this problem as if you were coding in JavaScript and using objects. Obviously, C++ does not approach objects the same way as JavaScript (nowhere near the same).
Here is a rough example of what you could do instead. I don't understand what you're trying to do, but I believe you can implement dynamic arrays and pointers to tackle the problem you have. Read up on using C++ pointers and C++ dynamic arrays. Here is some "rough" code that will hopefully get you on your way:
int main() {
cout << "Enter Text:" << endl;
getline (cin, test);
cout << test<< endl;
length = test.size();
// Create dynamic array and have this array the size of your string.
// Also, initialize a pointer to point to the address of your new array
int *enteredText;
enteredText = new char [length];
int *save = enteredText;
// Iterate over the array “entered_text” and assign it values
for (int i = 0; i < length; i++){
*entered_text = test[i];
entered_text++;
}
// now print chars
for (int i = 0; i < length; i++){
cout << *save << endl;
save++;
}
return 0;
don't make every variable you use global, its better to keep them local if there's no strong reason to do otherwise, and in c++ you have to tell your compiler the size of your array, or use allocation, but I would suggest to use std::vector<int>
I need some kind of error handler if I enter a string larger than the set size.
cout << "Enter long of the string" << endl;
cin >> N;
char* st = new char[N];
char* st1 = new char[N];
for (int i = 0; i < N; ++i) {
*(st1 + i) = ' ';
}
cout << "Enter string in the end put 0,without whitespace in the end." << endl;
cin.getline(st, N, '0');
First some comments.
Do not use C-Style arrays in C++ (like char data[N])
Always use std::string for strings
Never use char arrays for strings
Never ever use raw pointers for owned memory in C++
Neally never use new in C++
Avoid using pointer arithmetic with raw pointers pointing to owned memory
So, you should rethink your design. Start doing it correctly in the first place.
To answer you concrete question: If you read the documentation of the getline, then you can see that
count-1 characters have been extracted (in which case setstate(failbit) is executed).
So, the failbit will be set. You can check this with
if (std::cin.rdstate() == std::ios_base::failbit)
But as you can also read in the documentation
Extracts characters from stream until end of line or the specified delimiter delim.
So, it will not work, as you expect, It will try to read until 0 has been read. I think it will not work for you.
You also need to delete the newed memory. Otherwise, you are creating a memory hole. Look at you example again and try it:
#include <iostream>
int main() {
size_t N;
std::cout << "Enter maximum length of the string\n";
std::cin >> N;
char* st = new char[N];
char* st1 = new char[N];
for (size_t i = 0U; i < N; ++i) {
*(st1 + i) = ' ';
}
std::cout << "Enter string in the end put 0, without whitespace in the end.\n";
std::cin.getline(st, N, '0');
if (std::cin.rdstate() == std::ios_base::failbit) {
std::cin.clear();
std::cout << "\nError: Wrong string entered\n\n";
}
delete[] st;
delete[] st1;
return 0;
}
Solution for all your problems: Use std::string and std::getline
this script is supposed to output array values that were inputted by the user into array "store." I am trying to store all the char array values into string temp. I get the error on line 12: "[Error] invalid conversion from 'char*' to 'char' [-fpermissive]." Would appreciate any help!
Edit: so I fixed the declaration and now at least it compiles, but the answer I get on my cmd is all jumbled up. Why is this so? The cmd only correctly couts the first string but after the space, it messes up.
#include <iostream>
#include <cstdlib>
using namespace std;
void coutArray(char[], int);
int main()
{
char store[50];
cout << "enter text: " << endl;
cin >> store;
coutArray(store, 50);
system("pause");
return 0;
}
void coutArray(char store[], int max)
{
string temp = "";
int i = 0;
while (i < max)
{
temp += store[i];
i++;
}
cout << temp << endl;
}
Using input from all answerers I finally got the fixed code:
#include <iostream>
#include <cstdlib>
#include <string>
using namespace std;
void coutArray(char[], int);
int main()
{
char store[50] = {0};
cout << "enter text: " << endl;
cin.getline(store, 50);
coutArray(store, 50);
system("pause");
return 0;
}
void coutArray(char store[], int max)
{
string temp = "";
int i = 0;
while (i < max && store[i]!=0)
{
temp += store[i];
i++;
}
cout << temp << endl;
}
Thanks everyone. i learned a lot!!!
When you get an input using "cin" your input automatically ends with 0 (NULL).
You just need to add one little piece of code to your while statement.
instead of this :
while (i < max)
use this :
while (i < max && store[i]!=0)
Now it will stop when the input string is finished and won't print any garbage existed in the array beforehand.
To show that cin does add terminating zero, i initialized the array to 46, and put a breakpoint after the cin
so I fixed the declaration and now at least it compiles, but the answer I get on my cmd is all jumbled up. Why is this so?
Not sure what you mean by jumbled up. But since you did not tell us what you typed its hard to know it looks like it worked to me:
> ./a.out
enter text:
Plop
Plop�ȏU�
Notice that since my input is only 4 characters long. This means that a lot of the characters in the array still have undefined (ie random values). This is why I am seeing junk. To get past this initialize the array to have all 0 values.
char store[50] = {0};
Even bettern use a C++ object than handles longer strings.
std::string store;
std::getline(std::cin, store);
Note: passing arrays to functions by value is not a good idea. On the other end they have decayed to pointers and thus do not act like arrays anymore (they act like pointers whose semantics are similar but not identical).
If you must pass an array pass it by reference. But I would use a C++ container and pass that by reference (it is much safer than using C constructs). Have a look at std::string
The declaration of the function is wrong. Should be void coutArray(char *, int);
Look at the Implicit Conversion rules to understand what the compiler can do and what it cannot to do for you.
The issue with your program was that you were probably entering in less characters than the maximum size of the buffer. Then when you passed the maximum size as the parameter to coutArray, you assigned unfilled slots in the char array to temp. These unfilled slots could contain anything, as you have not filled them up to that point.
Your program is still correct, but what would be better would be to use read so that the number of bytes you specify is the minimum number of bytes that can be entered:
std::cin.read(store, 50);
Even better solution would be to use std::string:
std::string store;
std::cin >> store;
// or for the entire line
std::getline(std::cin, store);
It also follows that your coutArray should be changed to:
void coutArray(std::string);
// ...
void coutArray(std::string str)
{
std::cout << str << std::endl;
}
Look at this way
template<typename T, size_t N>
void MyMethod(T (&myArray)[N])
{
//N is number of elements, myArray is the array
std::cout<<"array elements number = "<<N<<endl;
//put your code
string temp;
temp.resize(N+1);//this is for performance not to copy it each time you use += operator
int i = 0;
while (i < max)
{
temp += store[i];
i++;
}
cout << temp << endl;
}
//call it like this
char arr[] = "hello world";
MyMethod(arr);
First off, this is a "homework" question so vector libraries and string libraries are off limits. I'm trying to get to the basics of c++.
My intention with this code is to make and use an array of string arrays. A list of words in other words.
When I run this code I get a bunch of nonsense.
If there is a better way to make a list of words in c++, I would love to hear about it.
const int cart_length = 50;
const int word_length = 50;
int main()
{
char cart_of_names[cart_length][word_length];
float cart_of_costs[cart_length];
char name[word_length];
cout << "enter the name of the first item: ";
cin >> name;
for(int i=0; i<word_length; i++)
{
cart_of_names[0][i] = name[i];
}
cout << endl;
cout << "that is: ";
for(int x=0; x<word_length; x++)
{
cout << cart_of_names[0][x];
}
cout << endl;
return 0;
}
If the string entered is not 50 characters long (cart_length), then less than 50 characters will be valid in the name. You should have an if(cart_of_names[0][x]==0) break; in your second loop.
I don't exactly understand what you are looking for. Following code will help you to read and print a list of 50 words. Hope this would help you.
const int cart_length = 50;
const int word_length = 50;
int main()
{
char cart_of_names[cart_length][word_length];
float cart_of_costs[cart_length];
for(int i=0; i<cart_length; i++)
{
cout << "enter the name of the " << i + 1 << "th item: ";
cin >> cart_of_names[i];
}
cout << "that is: ";
for(int x=0; x < cart_length; x++)
{
cout << cart_of_names[x] << endl;
}
return 0;
}
Check out STLSoft's fixed_array_2d (and it's higher order siblings). There's a detailed discussion of how they're implemented for maximum performance in Matthew Wilson's Imperfect C++.
If you can't use std::string, at least look at the functions like strncpy() from C for your name copying. Also, you're forgetting that c-style strings are null terminated.
Unless you're forbidden to use STL (which would be just mean), just use std::list<std::string>. www.cplusplus.com has detailed descriptions and examples for those classes.
Otherwise, you're stuck with an array of char arrays: in that case, be prepared for a lot of buffer overflow errors. Look around on the above site for the char[] management functions (strncpy() and the like), they'll make your life a bit easier (but not a lot).
In C, the best way I found to conceptualize what you are trying to do is using an array of char*. Same effect, but if you start to work with it I believe you may find it is easier on the brain.
It looks pretty close to me. Strings in C are null-terminated, which means that the end of the string is indicated by a null character. In a sense, a string in C is really just an array of bytes.
When you do:
cout << "enter the name of the first item: ";
cin >> name;
If I enter the string "Book", in memory it'll look like something like:
|0|1|2|3|4|5..49|
|B|o|o|k|0|*HERE BE DRAGONS*
Well, really it will contain the ASCII values corresponding to those letters, but for our purposes, it contains those letters. There here be dragons is memory that that you didn't initialize, so it contains whatever garbage your platform sets it to.
So when you copy your string, you need to instead look for that 0 byte at the end of the string.
for(int i=0; name[i]!=0; i++)
{
cart_of_names[0][i] = name[i];
}
Then when you output it, you don't actually need to do it a character at a time. You can just do cout<<cart_of_names[0]. cout knows where the string ends because of that terminating null character.
If you use strcpy() instead of
cart_of_names[0][i] = name[i];
it may work better but I cringe just looking at all that code.
"If there is a better way to make a list of words in c++, I would love to hear about it."
Include #include <string> and use std::string. The std::string type is part of the C++ specification, I think.
#include <iostream>
#include <string>
int main(void) {
std::string list[7];
list[0] = "In C++";
list[1] = "you can use";
list[2] = "the `std::string` type.";
list[3] = "It removes";
list[4] = "many of the problems";
list[5] = "introduced by";
list[6] = "C-style strings.";
for (int k=0; k<7; k++) std::cout << list[k] << ' ';
std::cout << '\n';
return 0;
}
#include<iostream>
using namespace std;
int main()
{
char arr[200];
while(1) {
cin >> arr;
int i = sizeof(arr);
cout << "The arr input is "<< arr
<< " and the size of the array is "<< i << endl;
}
return 0;
}
For the input of 34,
This code outputs :The arr input is 34 and the size of the array is 200
while I want it to get the size of the used space of the array . So for The last input i want it to output :The arr input is 34 and the size of the array is 2
Can someone tell me how?
Maybe you want strlen(arr) here. It must be null terminated, otherwise the cout << arr would not have worked.
You would need to #include <cstring>
There's no automatic way to do what you want in the general case - you'll need to keep track somehow, either with your own counter, or by seeding the array with an 'invalid' value (that you define) and search for to find the end of the used elements (that's what the '\0' terminator character in a C-style string is).
In the example code you posted, the array should receive a null terminated C-style string, you can use that knowledge to count the number of valid elements.
If you're using C++ or some other library that has some more advanced data structures, you may be able to use one that keeps track of this kind of thing for you (like std::vector<>).
the size of the used space of the array
There is no such thing. If you have an array of 200 chars, then you have 200 chars. Arrays have no concept of "used" and "unused" space. It only works with C-strings because of the convention that those are terminated by a 0 character. But then again, the array itself cannot know if it is holding a C-string.
in a less involved manner, you can just count through each character till you hit a null with just a while loop. It will do the exact same thing strlen() does. Also, in practice, you should do type checking with cin, but i'll assume this was just a test.
#include <iostream>
using namespace std;
int main()
{
char arr[200];
int i;
while(1) {
cin >> arr;
i=0;
while (arr[i] != '\0' && i<sizeof(arr))
i++;
cout << "The arr input is "<< arr
<< " and the size of the array is "<< i << endl;
}
return 0;
}
Just for completeness, here is a much more C++ like solution that is using std::string instead of a raw char array.
#include <iostream>
#include <string>
int
main()
{
while (std::cin.good()) {
std::string s;
if (std::cin >> s) {
std::cout
<< "The input is " << s
<< " and the size is " << s.length()
<< std::endl;
}
}
return 0;
}
It doesn't use an array, but it is the preferable solution for this kind of problem. In general, you should try to replace raw arrays with std::string and std::vector as appropriate, raw pointers with shared_ptr (scoped_ptr, or shared_array, whatever is most appropriate), and snprintf with std::stringstream. This is the first step to simply writing better C++. You will thank yourself in the future. I wish that I had followed this advice a few years ago.
Try it
template < typename T, unsigned N >
unsigned sizeOfArray( T const (&array)[ N ] )
{
return N;
}