in django admin the views that show the register's just have
a link to "edit", but what happen if a need an extra(S) links to
another views?
for example:
i have view that show the list of registered People, the nick is
linking to the Edit page (the normal way of Django), but i need
another links that will show me the "articles" of the people and
another the "comments" of the people.
how ill make this with django admin?
Thanks
(I'm assuming some field names from your models to answer)
Make the author field from "comment" searchable:
class CommentAdmin(admin.ModelAdmin):
search_fields = ("=author",)
Use list_display and HTML to control what's displayed on the people's list admin page:
def comments(obj):
return ('comments' % obj.name)
comments.short_description = 'comments'
comments.allow_tags = True
class PeopleAdmin(admin.ModelAdmin):
list_display = ("name", comments,)
And change /admin/pathto/comments/ to whatever your comment's admin list page is.
Basically you're going to direct your users to the comments search result page.
Related
I am having trouble with some django admin functionalities
what I want to do is to have 2 fields in an admin page
and I want to achieve this
field_A
field_B
if field_A == "specific value":
exclude = ("field_B",)
else:
fields = ("field_A","field_B")
Please Help
at last I gave up with django manipulating the DOM (which I think it cant do on real time) and made it with a Jquery Script
So i work in a company and we constantly need to add view fields for the user, I would like to know if there is a way to make this option available to the end user, for example a dropdown with the options that the model admin where he is allowing.
Today we use the django way of doing admin, for example:
list_display = (
'course',
'class',
'discipline',
'teacher',
'start_date',
'end_date'
)
I don't know if this what you are looking for, but give a try: How can I dynamically specify the "list_display" attribute of a django ModelAdmin class?
A kind regard
Emilio
In the classical example of Articles/Publications, when I create a Publication record in Admin page, I would like to be able to add existing Articles to that Publication. How can I do that?
I tried following:
class PublicationAdmin(admin.ModelAdmin):
articles = Article.objects.all()
admin.site.register(Publication, PublicationAdmin)
though I do not see any articles to select at all.
I can do the other way around, when I add a new article, I can select a publication by adding
class ArticleAdmin(admin.ModelAdmin):
fieldsets =[('Publications', {'fields': ['publications']})]
You need to define an InlineModelAdmin on the through model, in your case the through model is Publication.article_set.through. See the docs.
I am building out a restaurant website and using Wagtail CMS Snippets for the owner to manage menu items. The list of menu items are getting rather long and I was wondering if there is any way to add a search input field to the Snippets admin window? Below is an annotated screenshot for visual reference. Thank you.
This can easily be solved by using Wagtail's ModelAdmin module (http://docs.wagtail.io/en/v1.8.1/reference/contrib/modeladmin/), all you need is to add this piece of code to your wagtail_hooks.py file:
from wagtail.contrib.modeladmin.options import (
ModelAdmin, modeladmin_register)
from .models import Product
class ProductAdmin(ModelAdmin):
model = Product
menu_label = 'Product' # ditch this to use verbose_name_plural from model
menu_icon = 'date' # change as required
menu_order = 200 # will put in 3rd place (000 being 1st, 100 2nd)
add_to_settings_menu = False # or True to add your model to the Settings sub-menu
exclude_from_explorer = False # or True to exclude pages of this type from Wagtail's explorer view
list_display = ('title', 'example_field2', 'example_field3', 'live')
list_filter = ('live', 'example_field2', 'example_field3')
search_fields = ('title',)
# Now you just need to register your customised ModelAdmin class with Wagtail
modeladmin_register(ProductAdmin)
It'll create a separate menu entry for your Products model that's customisable much like default Django Admin listing. Which means you can easily add different filters and sorters to a listing.
This is a very powerful feature and I myself don't show clients the "Snippets" section at all; it's just too simple and ugly. Instead, I create a separate ModelAdmin per snippet and this gives me the power of customisation.
The search bar will appear automatically once you set up your model to be indexed with the search system. You can do this by inheriting from the wagtail.wagtailsearch.index.Indexed class and defining a search_fields list on your model, as described here: http://docs.wagtail.io/en/v1.8.1/topics/search/indexing.html#wagtailsearch-indexing-models
(Note that if you're using Elasticsearch, you'll also need to run ./manage.py update_index to add the items to the search index.)
If you are on the django admin page for the model Group. You don't know that there is a reverse relation to user.
Some people (not me) have difficulties with it.
Is there a way to show all reverse relations, so that you can jump to the matching admin pages?
Example:
On admin page for Group I want a link to User (and all other models which refer to it).
This should happen by code, not by hand with templates.
This method doesn't automatically add links to all related models of a Group, but does for all Users related to a Group (so for one related model at a time). With this you'll get an inline view in your Group with the related Users.
You could probably extend this technique to make it automatically work for all related fields.
class UserInline(admin.StackedInline):
model = User
extra = 0
readonly_fields = ('change',)
def change(self, instance):
if instance.id:
# Django's admin URLs are automatically constructed
# based on your Django app and model's name.
change_url = urlresolvers.reverse(
'admin:djangoapp_usermodel_change', args=(instance.id,)
)
return '<a class="changelink" href="{}">Change</a>'.format(change_url)
else:
return 'Save the group first before editing the user.'
change.allow_tags = True
class GroupAdmin(admin.ModelAdmin):
list_display = ('name',)
inlines = (UserInline,)
You might also be interested in this extension I created for Django admin pages to link to related objects:
https://github.com/gitaarik/django-admin-relation-links
It's quite easy to use and makes the admin a lot more convenient to use :).