As usual, regular expressions are causing my head to hurt.
I have the following strings (as examples) which I would like to parse:
Client: {Path=ClientName}, Balance: {Path=Balance, StringFormat='{0:0.00}'}
Client: {Path=ClientName}, Balance: {Path=Balance, StringFormat='Your balance is {0:0.00}.'}
I am looking for a regular expression (or any other method) which could split the strings as follows and then get the individual key/value values of each. (The idea is to resolve each one of these to a XAML binding)
String 1: {Path=ClientName}
Path = ClientName
String 2: {Path=Balance, StringFormat='{0:0.00}'}
Path = Balance
StringFormat = {0:0.00}
At the moment I have the following regular expression to split the strings but this gets confused by the value of StringFormat due to the '}' in the value.
(?<!'){(.+?)}(?!')
Any idea how I can achieve this?
Thanks!
It gets really tiring solving this same problem over and over, but here you go:
Technically, you're doing it wrong, you should use a parser, regular expressions aren't built to deal with nested matching parenthesis, blah blah blah. We can hack this one together, though, so why not?
/(?<!'){([^'}]|'[^']+')+}(?!')/
The meat of that - {([^'}]+|'[^']+')} - looks for two things: a) anything that's not a } or a ' character ([^'}]), and b) anything that looks like a string ('[^']+'). It assumes a string is a quote, a bunch of non-quote text, and another quote. Given your examples, this should work.
It will, however, fail to match 'This is a string with \'quotes\' in it', because it isn't designed for escaped quotation marks. Adding this is simple, and involves applying the principles we just applied, so I'll leave that to you to figure out if you can. You seem to be pretty good with regular expressions, and you at least made a start on this before you asked it, so I think you can figure out how to make it match \' in a string.
EDIT: You're using 's instead of "s. Sorry about that.
Related
At the moment, I have a PHP function that gets the contents of a CSV file and puts it into a multi-dimensional array, which contains text that I print out in various places, using the indexes.
an example of use would be:
$localText[index][pageText][conceptQualityText][$lang];
The first index, [index], would be the name of the page. The second index [pageText] would indicate what it is (text for the page). The third index, [conceptQualityText] indicates what the actual text is. The last index, [$lang] gets the text in the desired language.
so:
->page location
->what is it
->the content
->what language it should be displayed in.
This all worked fine in the previous PHP versions. However, upgrading to 7.2, PHP seems to be a bit more strict. I was a bit more green ~2 years ago when I first made this solution, and now know that since these indexes aren't defined as strings e.g. encapsulated in single quotes like so: ['index'], they fit the notation of a superglobal (DEFINE). I didn't give it much thought back then, but now PHP seems to interpret them as so (superglobals), and so I get thrown the error that x word is an undefined superglobal.
My initial thought is to make a search and replace on my example string:
$localText[index][pageText][conceptQualityText][$lang];
using the regular expression functionality in Notepad++.
However, the example is just one of many, the notation of the array indexing is basically:
$localText[index][index2][index3][$lang];
So my question is:
How can I make use of the Notepad++ search and replace, using a regular expression, so that my index pointers become strings, instead of acting as superglobal variables?
e.g. make:
$localText[index][index2][index3][$lang];
into:
$localText['index']['index2']['index3'][$lang];
I will need some sort of logic that checks for whatever is inside the brackets and encapsulates them with single quotes, except for the last index, [$lang].
I tried to give as much information as possible, let me know if anything needs to be elaborated.
I tried to refer to these docs without much luck.
I found a solution using
this:
find: \b(localText\[)([a-zA-z0-9_\-]+)(\]\[)([a-zA-z0-9_\-]+)(\]\[)([a-zA-z0-9_\-]+)
replace: $1'$2'$3'$4'$5'$6'
and it works like a charm. Thanks for everyone who took their time to help.
You can use the following regex to match:
\[[^'](\w+)[^']\]
The regex matches a Word between Square brackets unless it quoted.
Replace with:
['$1']
The regex will not match the last brackets because it contains a '$' sign.
Regular Expressions are incredible. I'm in my regex infancy so help solving the following would be greatly appreciated.
I have to search through a string to match for a P character that's not surrounded by operators, power or negative signs. I then have to insert a multiplication sign. Case examples are:
33+16*55P would become 33+16*55*P
2P would become 2*P
P( 33*sin(45) ) would become P*(33*sin(45))
I have written some regex that I think handles this although I don't know how using regex I can insert a character:
The reg is I've written is:
[^\^\+\-\/\*]?P+[^\^\+\-\/\*]
The language where the RegEx will be used is ActionScript 3.
A live example of the regex can be seen at:
http://www.regexr.com/39pkv
I would be massively grateful if someone could show me how I insert a multiplication sign in middle of the match ie P2, becomes P*2, 22.5P becomes 22.5P
ActionScript 3 has search, match and replace functions that all utilise regular expressions. I'm unsure how I'd use string.replace( expression, replaceText ) in this context.
Many thanks in advance
Welcome to the wonder (and inevitable frustration that will lead to tearing your hair out) that is regular expressions. You should probably read over the documentation on using regular expressions in ActionScript, as well as this similar question.
You'll need to combine RegExp.test() with the String.replace() function. I don't know ActionScript, so I don't know if it will work as is, but based on the documentation linked above, the below should be a good start for testing and getting an idea of what the form of your solution might look like. I think #Vall3y is right. To get the replace right, you'd want to first check for anything leading up to a P, then for anything after a P. So two functions is probably easier to get right without getting too fancy with the Regex:
private function multiplyBeforeP(str:String):String {
var pattern:RegExp = new RegExp("([^\^\+\-\/\*]?)P", "i");
return str.replace(pattern, "$1*P");
}
private function multiplyAfterP(str:String):String {
var pattern:RegExp = new RegExp("P([^\^\+\-\/\*])", "i");
return str.replace(pattern, "P*$1");
}
Regex is used to find patterns in strings. It cannot be used to manipulate them. You will need to use action script for that.
Many programming languages have a string.replace method that accepts a regex pattern. Since you have two cases (inserting after and before the P), a simple solution would be to split your regex into two ([^\^\+\-\/\*]?P+ and P+[^\^\+\-\/\*] for example, this might need adjustment), and switch each pattern with the matching string ("*P" and "P*")
I need to build a RegEx expression which gets its text strings from the Title field of my Database. I.e. the complete strings being searched are: Mr. or Ms. or Dr. or Sr. etc.
Unfortunately this field was a free field and anything could be written into it. e.g.: M. ; A ; CFO etc.
The expression needs to match on everything except: Mr. ; Ms. ; Dr. ; Sr. (NOTE: The list is a bit longer but for simplicity I keep it short.)
WHAT I HAVE TRIED SO FAR:
This is what I am using successfully on on another field:
^(?!(VIP)$).* (This will match every string except "VIP")
I rewrote that expression to look like this:
^(?!(Mr.|Ms.|Dr.|Sr.)$).*
Unfortunately this did not work. I assume this is because because of the "." (dot) is a reserved symbol in RegEx and needs special handling.
I also tried:
^(?!(Mr\.|Ms\.|Dr\.|Sr\.)$).*
But no luck as well.
I looked around in the forum and tested some other solutions but could not find any which works for me.
I would like to know how I can build my formula to search the complete (short) string and matches everything except "Mr." etc. Any help is appreciated!
Note: My Question might seem unusual and seems to have many open ends and possible errors. However the rest of my application is handling those open ends. Please trust me with this.
If you want your string simply to not start with one of those prefixes, then do this:
^(?!([MDS]r|Ms)\.).*$
The above simply ensures that the beginning of the string (^) is not followed by one of your listed prefixes. (You shouldn't even need the .*$ but this is in case you're using some engine that requires a complete match.)
If you want your string to not have those prefixes anywhere, then do:
^(.(?!([MDS]r|Ms)\.))*$
The above ensures that every character (.) is not followed by one of your listed prefixes, to the end (so the $ is necessary in this one).
I just read that your list of prefixes may be longer, so let me expand for you to add:
^(.(?!(Mr|Ms|Dr|Sr)\.))*$
You say entirely of the prefixes? Then just do this:
^(?!Mr|Ms|Dr|Sr)\.$
And if you want to make the dot conditional:
^(?!Mr|Ms|Dr|Sr)\.?$
^
Through this | we can define any number prefix pattern which we gonna match with string.
var pattern = /^(Mrs.|Mr.|Ms.|Dr.|Er.).?[A-z]$/;
var str = "Mrs.Panchal";
console.log(str.match(pattern));
this may do it
/(?!.*?(?:^|\W)(?:(?:Dr|Mr|Mrs|Ms|Sr|Jr)\.?|Miss|Phd|\+|&)(?:\W|$))^.*$/i
from that page I mentioned
Rather than trying to construct a regex that matches anything except Mr., Ms., etc., it would be easier (if your application allows it) to write a regex that matches only those strings:
/^(Mr|Ms|Dr|Sr)\.$/
and just swap the logic for handling matching vs non-matching strings.
re.sub(r'^([MmDdSs][RSrs]{1,2}|[Mm]iss)\.{0,1} ','',name)
I would like to remove hundreds on onmouseover events from my code. the evt all pass different variables and I want to be able to use dreamwaever to find and replace all the strings with nothing.
Here is an example
onmouseover="parent.mv_mapTipOver(evt,'Wilson');"
onmouseover="parent.mv_mapTipOver(evt,'Harris');"
onmouseover="parent.mv_mapTipOver(evt,'Walker');"
I want to run a search that will identify all of these and replace/remove them.
I have tried seemingly infinite permutations of things like:
onmouseover="parent.mv_mapTipOver(evt,'[^']');"
or
onmouseover="parent.mv_mapTipOver(evt,'[^']);"
or
onmouseover="parent.mv_mapTipOver(evt,[^']);"
or
onmouseover="parent.mv_mapTipOver(evt,'[^']+');"
And many more. I cannot find the regular expression that will work.
Any/all help would be appreciated.
Thanks a ton!
"." and "(" have special meaning in regular expressions, so you need to escape them:
onmouseover="parent\.mv_mapTipOver\(evt,'[^']+'\);"
I'm not sure if this is correct dreamweaver regex syntax, but this stuff is standard enough.
Try this one:
onmouseover="parent\.mv_mapTipOver\(evt,'.+?'\);"
And see it in action here.
When using reg expressions you have to be very careful about how you handle white space. For example the following piece of code will not get caught by most of the reg expressions mentioned so far because of the space after the comma and equals sign, despite the fact that it is most likely valid syntax in the language you are using.
onmouseover= "parent.mv_mapTipOver(evt, 'Walker');"
In order to create regexp that ignore white space you must insert /s* everywhere in the regexp that white space might occur.
The following regexp should work even if there is additional white space in your code.
onmouseover\s*=\s*"parent\.mv_mapTipOver\(\s*evt\s*,\s*'[A-Za-z]+'\s*\);"
Is it possible to concatenate the results of Regex Pattern Matching using only Regex syntax?
The specific instance is a program is allowing regex syntax to pull info from a file, but I would like it to pull from several portions and concatenate the results.
For instance:
Input string: 1234567890
Desired result string: 2389
Regex Pattern match: (?<=1).+(?=4)%%(?<=7).+(?=0)
Where %% represents some form of concatenation syntax. Using starting and ending with syntax is important since I know the field names but not the values of the field.
Does a keyword that functions like %% exist? Is there a more clever way to do this? Must the code be changed to allow multiple regex inputs, automatically concatenating?
Again, the pieces to be concatenated may be far apart with unknown characters in between. All that is known is the information surrounding the substrings.
2011-08-08 edit: The program is written in C#, but changing the code is a major undertaking compared to finding a regex-based solution.
Without knowing exactly what you want to match and what language you're using, it's impossible to give you an exact answer. However, the usual way to approach something like this is to use grouping.
In C#:
string pattern = #"(?<=1)(.+)(?=4).+(?<=7)(.+)(?=0)";
Match m = Regex.Match(input, pattern);
string result = m.Groups[0] + m.Groups[1];
The same approach can be applied to many other languages as well.
Edit
If you are not able to change the code, then there's no way to accomplish what you want. The reason is that in C#, the regex string itself doesn't have any power over the output. To change the result, you'd have to either change the called method of the Regex class or do some additional work afterwards. As it is, the method called most likely just returns either a Match object or a list of matching objects, neither of which will do what you want, regardless of the input regex string.