We have XML file like below...
<?xml version='1.0'?>
<T0020 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.safersys.org/namespaces/T0020V1 T0020V1.xsd"
xmlns="http://www.safersys.org/namespaces/T0020V1">
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>1213561</IRP_CARRIER_ID_NUMBER>
<IRP_BASE_COUNTRY>US</IRP_BASE_COUNTRY>
<IRP_BASE_STATE>AL</IRP_BASE_STATE>
<IRP_ACCOUNT_NUMBER>15485</IRP_ACCOUNT_NUMBER>
<IRP_ACCOUNT_TYPE>I</IRP_ACCOUNT_TYPE>
<IRP_STATUS_CODE>0</IRP_STATUS_CODE>
<IRP_STATUS_DATE>2004-02-23</IRP_STATUS_DATE>
<IRP_UPDATE_DATE>2007-03-09</IRP_UPDATE_DATE>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>WILLIAMS TODD</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
<STREET_LINE_1>P O BOX 1210</STREET_LINE_1>
<STREET_LINE_2/>
<CITY>MARION</CITY>
<STATE>AL</STATE>
<ZIP_CODE>36756</ZIP_CODE>
<COUNTY/>
<COLONIA/>
<COUNTRY>US</COUNTRY>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
</T0020>
In order to Insert this XML data to database ,we have used two XSLT.
First XSLT will remove name space from XML file and convert this XML to some intermediate
XML(say Process.xml) file on some temporary location.
then we were taking that intermediate xml(without namespace lines) and applied another XSL
to map xml field to Database.
Then we have found solution and we have used only one XSLT which does bode [1] Remove namespace and [2] Mapping XML field to Database to insert data.
Our final style sheet contain following lines
xmlns:t="http://www.safersys.org/namespaces/T0020V1">
and we used following to map field to Database
<xsl:template match="/">
<xsl:element name="T0020">
<xsl:apply-templates select="t:T0020/t:IRP_ACCOUNT" />
</xsl:element>
</xsl:template>
how did our problem solved with this approach ?Any consequences with using this ?
I have searched about this but not getting the functionality.
Thanks in Advance..
I don't see any problems with your approach.
XSLT mandates a fully qualified name for a correct matching, so using a prefixed namespace in your XSLT is the right solution; this is why you solved your problem.
Related
I have a snippet of code I've inherited and I'm trying to get it to work on multiples of the match pattern and set a tag from looking up a value from a table using another tag. What happens is that, for every item, the same lookup is performed and not the relative one for the node. I can't work out the syntax to work thru all entries and substitute the correct one. It's got to be simple it's just that I am simpler :)
My source xml contains this (within an outer /oomsdoc document node not shown):
<item>
<lineqty> 1</lineqty>
<linesku>BNLP5008 </linesku>
<linecustprod>xxxxxxxxxxxxxxx</linecustprod>
<linedesc>London Pride (Bot500mlx8) </linedesc>
</item>
<item>
<lineqty> 1</lineqty>
<linesku>BNBL5008 </linesku>
<linecustprod>xxxxxxxxxxxxxxx</linecustprod>
<linedesc>Bengal Lancer (Bot500mlx8) </linedesc>
</item>
I want to substitute the xxxxxxxxxxxxxxx in each linecustprod tag with the material from the lookup table using the value of the linesku tag.
This is my lookup table:
<Materials>
<product sku='BNLP5008 ' material='LONDON PRIDE'/>
<product sku='BNBL5008 ' material='BENGAL LANCER'/>
</Materials>
and this is my xslt code.
<xsl:variable name="SkuList" select="document('d:\test\transforms\catalogue.xml')/Materials"/>
<xsl:template match="/oomsdoc/item/linecustprod">
<xsl:variable name="MySku" select="/oomsdoc/item/linesku"/>
<linecustprod>
<xsl:value-of select="$SkuList/product[#sku=$MySku]/#material"/>
</linecustprod>
</xsl:template>
I'm guessing some kind of xsl foreach would work but just can't find a usable example to crib :)
Your guidance again would be appreciated at this point in my frustration :)
Thanks,
Brian.
Changing the variable definition to
<xsl:variable name="MySku" select="../linesku"/>
should be sufficient, this will pull out the linesku that is a sibling to the linecustprod you're currently looking at. As currently defined the variable will contain a node set of all the linesku elements in the document, so the value-of will give you the first entry from $SkuList that matches any entry in the main input file.
In addition to Ian Roberts' answer, please change
<xsl:variable name="SkuList" select="document('d:\test\transforms\catalogue.xml')/Materials"/>
to
<xsl:variable name="SkuList" select="document('/d:\test\transforms\catalogue.xml')/Materials"/>
for some reason, the first throws an error (malformed URL).
Is it possible to transform the xsd namespace to something different in the result?
the input namespace of the xsl:stylesheet element looks like:
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
and the output namespace of the output root element should look like:
xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
I tried to manually asssign the second namespace to the root element of my output, however then the XSLT transformation does not recognize the elements prefixed with "xsd" anymore, as it seems to overwrite the original namespace.
Changing the prefix and making an alias is also not an option: also in the output (RDF/XML) the prefix of the element should be called "xsd".
Thank you for helping.
EDIT:
here are the relevant parts of the two files:
Input File (XSD):
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
should become
Output File (RDF/XML):
<rdf:RDF xmlns:xsd="http://www.w3.org/2001/XMLSchema#">
If you want to transform all elements in the namespace http://www.w3.org/2001/XMLSchema to be in the namespace http://www.w3.org/2001/XMLSchema# then use
<xsl:template match="xsd:*">
<xsl:element name="{name()}" namespace="http://www.w3.org/2001/XMLSchema#">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
If that does not help then please show us a sample of the input XML you have and the corresponding output sample you want to create.
ANSWER:
It took me some hours but eventually I figured out a solution on my own:
I firstly had to exclude the prefix of the stylesheet from the results file:
<xsl:stylesheet version="2.0" xmlns:xsd="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xsd">
Then I created a new XSD namespace for the root element of the output:
<xsl:namespace name="xsd" select="'http://www.w3.org/2001/XMLSchema#'"/>
Anyway, thank you for helping.
I have a large collection of XML files which I need to transform using XSLT. The problem is that many of these files were hand-written by different people and they do not use consistent names to refer to the schemas. For example, one file might use:
xmlns:itemType="http://example.com/ItemType/XSD"
where another might use the prefix "it" instead of "itemType":
xmlns:it="http://example.com/ItemType/XSD"
If that's not bad enough, there are several files which use two or three synonyms for the same thing!
<?xml version="1.0"?>
<Document
xmlns:it="http://example.com/ItemType/XSD"
xmlns:itemType="http://example.com/ItemType/XSD"
xmlns:ItemType="http://example.com/ItemType/XSD"
...
(there's clearly been a lot of cutting and pasting going on)
Now, because the pattern matching in the XSLT file appears to work on the namespace prefix (as opposed to the schema it relates to) the pattern only matches one of the variants. So if I write something like:
<xsl:template match="SomeNode[#xsi:type='itemType:SomeType']">
...
</xsl:template>
Then it only matches a subset of the cases that I want it to.
Question 1: Is there any way to get the XSLT to match all the variants?
Question 2: Is there any way to remove the duplicates so all the output files use consistent naming?
I naïvely tried using "namespace-alias" but I guess I've misunderstood what that does because I can't get it to do anything at all - either match all the variants or affect the output XML.
<?xsl:stylesheet
version="1.0"
...
xmlns:it="http://example.com/ItemType/XSD"
xmlns:itemType="http://example.com/ItemType/XSD"
xmlns:ItemType="http://example.com/ItemType/XSD"
...
<xsl:output method="xml" indent="yes"/>
<xsl:namespace-alias stylesheet-prefix="it" result-prefix="ItemType"/>
<xsl:namespace-alias stylesheet-prefix="itemType" result-prefix="ItemType"/>
Attribute values or text nodes won't be cast to QName unless you explicitly say so. Although this is only posible in XSLT/XPath 2.0
In XSLT/XPath 1.0 you must do this "manually":
<xsl:template match="SomeNode">
<xsl:variable name="vPrefix" select="substring-before(#xsi:type,':')"/>
<xsl:variable name="vNCName"
select="translate(substring-after(#xsi:type,$vPrefix),':','')"/>
<xsl:if test="namespace::*[
name()=$vPrefix
] = 'http://example.com/ItemType/XSD'
and
$vNCName = 'SomeType'">
<!-- Content Template -->
<xsl:if>
</xsl:template>
Edit: All in one pattern (less readable, maybe):
<xsl:template match="SomeNode[
namespace::*[
name()=substring-before(../#xsi:type,':')
] = 'http://example.com/ItemType/XSD'
and
substring(
concat(':',#xsi:type),
string-length(#xsi:type) - 7
) = ':SomeType'
]">
<!-- Content Template -->
</xsl:template>
In XSLT 2.0 (whether or not you use schema-awareness) you can write the predicate as [#xsi:type=xs:QName('it:SomeType')] where "it" is the prefix declared in the stylesheet for this namespace. It doesn't have to be the same as the prefix used in the source document.
Of course matching of element and attribute names (as distinct from QName-valued content) uses namespace URIs rather than prefixes in both XSLT 1.0 and XSLT 2.0.
I have a xsl file for html output. the xsl handles an old format of xml whixh I want to renew now. Therefore I need to rename the old elements names to the new names I'm using the new names in the following xsl code. How can I do this?
I tried
<xsl:template match="OldName">
<NewName><xsl:value-of select="."/></NewName>
</xsl:template>
<xsl:template match="/">
some code... </xsl:template>
and then I tried to access
<xsl:value-of select="NewName"/>
but got nothing while when using the OldName I got the value
If you're using XSLT2, you can use a two-phase transformation.
<xsl:value-of select="NewName"/> looks at the input, not the output. And in the input, there is no NewName. To make use of the NewName, you would have to parse it twice; once renewing the names, and once doing formatting.
I've read with interest the techniques available on the web to extract a unique list of items from a XML file containing duplicates using XSL.
These range into 2 categories:
1) The Muenchian method (example: http://www.jenitennison.com/xslt/grouping/)
2) Or the previous-sibling look-up
These both rely on an XPath expression to select the data to group by.
However, in the XML file that I'm trying to work out, the data is not present "natively" in the XML file. I am using a xsl:template to compute some aggregated data from my elements. And I would like to group based on the aggregated data.
For example I have:
<filmsreview>
<record><data name='movie'>Star Wars</data><data name='ratings'>John:Good, Mary:Good</data></record>
<record><data name='movie'>Indiana Jones</data><data name='ratings'>John:Good, Mary:Bad, Helen:Average</data></record>
<record><data name='movie'>Titanic</data><data name='ratings'>John:Bad, Helen:Good</data></record>
</filmsreview>
I know that the structuration of data is not perfect and that by creating sub-elements I could do something easier, but I cannot change the data source easily, so let's take this as a challenge.
And I would like to build a recap where I have John's distinct ratings:
John's ratings:
Good
Bad
I have a xsl:template that can take a record element and return John's rating for this record:
Example:
<xsl:template name="get_rating">
<xsl:param name="reviewer" />
<!-- I use some string manipulation, and xsl:value-of to return the review for John-->
</xsl:template>
I can just call it under a xsl:for-each to get the exhaustive list of John's review. But I cannot combine this call with any of the methods to get unique values.
Do I have to use an intermediary XSL to convert my XML file to a more structured way? Or can I do in a single step?
Many thanks
Gerard
Hmm... This should be possible using xslt variables and the nodeset method, perhaps something like this:
<xsl:variable name="_johnsRatings">
<xsl:apply-templates select="/" mode="johnsRatings" />
</xsl:variable>
<xsl:variable name="johnsRatings" select="msxsl:node-set($_johnsRatings)" />
<xsl:template match="/" mode="johnsRatings">
<Ratings>
<xsl:for-each select="/filmsReview/record/data[#name='ratings']">
<Rating><xsl:call-template name="get_rating" /></Rating>
</xsl:for-each>
</Ratings>
</xsl:template>
At this point, it should be possible to query the $johnsRatings variable using standard XPath queries, and you can use either of the two methods you mentioned above to retrieve unique values from it...
Hope that helps
EDIT:
I don't know what XSLT engine you are using, I assumed you have access to the msxsl:node-set() function. However, most XSLT processors have similar methods, so you might have to search around for an equivalent method in your processor