I have created a regular dodecahedron with OpenGL. I wanted to make the faces transparent (as in the image on Wikipedia) but this doesn't always work. After some digging in the OpenGL documentation, is appears that I "need to sort the transparent faces from back to front". Hm. How do I do that?
I mean I call glRotatef() to rotate the coordinate system but the reference coordinates of the faces stay the same; the rotation effect is applied "outside" of my renering code.
If I apply the transformation to the coordinates, then everything else will stop moving.
How can I sort the faces in this case?
[EDIT] I know why this happens. I have no idea what the solution could look like. Can someone please direct me to the correct OpenGL calls or a piece of sample code? I know when the coordinate transform is finished and I have the coordinates of the vertices of the faces. I know how to calculate the center coordinates of the faces. I understand that I need to sort them by Z value. How to I transform a Vector3f by the current view matrix (or whatever this thing is called that rotates my coordinate system)?
Code to rotate the view:
glRotatef(xrot, 1.0f, 0.0f, 0.0f);
glRotatef(yrot, 0.0f, 1.0f, 0.0f);
When the OpenGL documentation says "sort the transparent faces" it means "change the order in which you draw them". You don't transform the geometry of the faces themselves, instead you make sure that you draw the faces in the right order: farthest from the camera first, nearest to the camera last, so that the colour is blended correctly in the frame buffer.
One way to do this is to compute for each transparent face a representative distance from the camera (for example, the distance of its centre from the centre of the camera), and then sort the list of transparent faces on this representative distance.
You need to do this because OpenGL uses the Z-buffering technique.
(I should add that the technique of "sorting by the distance of the centre of the face" is a bit naive, and leads to the wrong result in cases where faces are large or close to the camera. But it's simple and will get you started; there'll be plenty of time later to worry about more sophisticated approaches to Z-sorting.)
Update: Aaron, you clarified the post to indicate that you understand the above, but don't know how to calculate a suitable Z value for each face. Is that right? I would usually do this by measuring the distance from the camera to the face in question. So I guess this means you don't know where the camera is?
If that's a correct statement of the problem you're having, see OpenGL FAQ 8.010:
As far as OpenGL is concerned, there is no camera. More specifically, the camera is always located at the eye space coordinate (0., 0., 0.).
Update: Maybe the problem is that you don't know how to transform a point by the modelview matrix? If that's the problem, see OpenGL FAQ 9.130:
Transform the point into eye-coordinate space by multiplying it by the ModelView matrix. Then simply calculate its distance from the origin.
Use glGetFloatv(GL_MODELVIEW_MATRIX, dst) to get the modelview matrix as a list of 16 floats. I think you'll have to do the multiplication yourself: as far as I know OpenGL doesn't provide an API for this.
For reference, here is the code (using lwjgl 2.0.1). I define my model by using an array of float arrays for the coordinates:
float one = 1f * scale;
// Cube of size 2*scale
float[][] coords = new float[][] {
{ one, one, one }, // 0
{ -one, one, one },
{ one, -one, one },
{ -one, -one, one },
{ one, one, -one },
{ -one, one, -one },
{ one, -one, -one },
{ -one, -one, -one }, // 7
};
Faces are defined in an array of int arrays. The items in the inner array are indices of vertices:
int[][] faces = new int[][] {
{ 0, 2, 3, 1, },
{ 0, 4, 6, 2, },
{ 0, 1, 5, 4, },
{ 4, 5, 7, 6, },
{ 5, 1, 3, 7, },
{ 4, 5, 1, 0, },
};
These lines load the Model/View matrix:
Matrix4f matrix = new Matrix4f ();
FloatBuffer params = FloatBuffer.allocate (16);
GL11.glGetFloat (GL11.GL_MODELVIEW_MATRIX, params );
matrix.load (params);
I store some information of each face in a Face class:
public static class Face
{
public int id;
public Vector3f center;
#Override
public String toString ()
{
return String.format ("%d %.2f", id, center.z);
}
}
This comparator is then used to sort the faces by Z depth:
public static final Comparator<Face> FACE_DEPTH_COMPARATOR = new Comparator<Face> ()
{
#Override
public int compare (Face o1, Face o2)
{
float d = o1.center.z - o2.center.z;
return d < 0f ? -1 : (d == 0 ? 0 : 1);
}
};
getCenter() returns the center of a face:
public static Vector3f getCenter (float[][] coords, int[] face)
{
Vector3f center = new Vector3f ();
for (int vertice = 0; vertice < face.length; vertice ++)
{
float[] c = coords[face[vertice]];
center.x += c[0];
center.y += c[1];
center.z += c[2];
}
float N = face.length;
center.x /= N;
center.y /= N;
center.z /= N;
return center;
}
Now I need to set up the face array:
Face[] faceArray = new Face[faces.length];
Vector4f v = new Vector4f ();
for (int f = 0; f < faces.length; f ++)
{
Face face = faceArray[f] = new Face ();
face.id = f;
face.center = getCenter (coords, faces[f]);
v.x = face.center.x;
v.y = face.center.y;
v.z = face.center.z;
v.w = 0f;
Matrix4f.transform (matrix, v, v);
face.center.x = v.x;
face.center.y = v.y;
face.center.z = v.z;
}
After this loop, I have the transformed center vectors in faceArray and I can sort them by Z value:
Arrays.sort (faceArray, FACE_DEPTH_COMPARATOR);
//System.out.println (Arrays.toString (faceArray));
Rendering happens in another nested loop:
float[] faceColor = new float[] { .3f, .7f, .9f, .3f };
for (Face f: faceArray)
{
int[] face = faces[f.id];
glColor4fv(faceColor);
GL11.glBegin(GL11.GL_TRIANGLE_FAN);
for (int vertice = 0; vertice < face.length; vertice ++)
{
glVertex3fv (coords[face[vertice]]);
}
GL11.glEnd();
}
Have you tried just drawing each face, in relation to regular world coordinates from back to front? Often it seems like the wording in some of the OpenGL docs is weird. I think if you get the drawing in the right order with out worrying about rotation, it might automatically work when you add rotation. OpenGL might take care of the reordering of faces when rotating the matrix.
Alternatively you can grab the current matrix as you draw ( glGetMatrix() ) and reorder your drawing algorithm depending on which faces are going to be the rotated back/front.
That quote says it all - you need to sort the faces.
When drawing such a simple object you can just render the back faces first and the front faces second using the z-buffer (by rendering twice with different z-buffer comparison functions).
But usually, you just want to transform the object, then sort the faces. You transform just your representation of the object in memory, then determine the drawing order by sorting, then draw in that order with the original coordinates, using transformations as needed (need to be consistent with the sorting you've done). In a real application, you would probably do the transformation implicitly, eg. by storing the scene as a BSP- or Quad- or R- or whatever-tree and simply traversing the tree from various directions.
Note that the sorting part can be tricky, because the function "is-obsucred-by" which is the function you want to compare the faces by (because you need to draw the obscured faces first) is not an ordering, eg. there can be cycles (face A obscures B && face B obscures A). In this case, you would probably split one of the faces to break the loop.
EDIT:
You get the z-coordinate of a vertex by taking the coordinates you pass to glVertex3f(), make it 4D (homogenous coordinates) by appending 1, transform it with the modelview matrix, then transform it with the projection matrix, then do the perspective division. The details are in the OpenGL specs in Chapter 2, section Coordinate transformations.
However, there isn't any API for you to actually do the transformation. The only thing OpenGL lets you do is to draw the primitives, and tell the renderer how to draw them (eg. how to transform them). It doesn't let you easily transform coordinates or anything else (although there IIUC are ways to tell OpenGL to write transformed coordinates to a buffer, this is not that easy). If you want some library to help you manipulate actual objects, coordinates etc., consider using some sort of scenegraph library (OpenInventor or something)
Related
So I've implemented Frustum Culling in my game engine and I'm experiencing a strange bug. I am rendering a building that is segmented into chunks and I'm only rendering the chunks which are in the frustum. My camera starts at around (-.033, 11.65, 2.2) and everything looks fine. I start moving around and there is no flickering. When I set a breakpoint in the frustum culling code I can see that it is indeed culling some of the meshes. Everything seems great. Then when I reach the center of the building, around (3.9, 4.17, 2.23) meshes start to disappear that are in view. The same is true on the other side as well. I can't figure out why this bug could exist.
I implement frustum culling by using the extraction method listed here Extracting View Frustum Planes (Gribb & Hartmann method). I had to use glm::inverse() rather than transpose as it suggested and I think the matrix math was given for row-major matrices so I flipped that. All in all my frustum plane calculation looks like
std::vector<Mesh*> render_meshes;
auto comboMatrix = proj * glm::inverse(view * model);
glm::vec4 p_planes[6];
p_planes[0] = comboMatrix[3] + comboMatrix[0]; //left
p_planes[1] = comboMatrix[3] - comboMatrix[0]; //right
p_planes[2] = comboMatrix[3] + comboMatrix[1]; //bottom
p_planes[3] = comboMatrix[3] - comboMatrix[1]; //top
p_planes[4] = comboMatrix[3] + comboMatrix[2]; //near
p_planes[5] = comboMatrix[3] - comboMatrix[2]; //far
for (int i = 0; i < 6; i++){
p_planes[i] = glm::normalize(p_planes[i]);
}
for (auto mesh : meshes) {
if (!frustum_cull(mesh, p_planes)) {
render_meshes.emplace_back(mesh);
}
}
I then decide to cull each mesh based on its bounding box (as calculated by ASSIMP with the aiProcess_GenBoundingBoxes flag) as follows (returning true means culled)
glm::vec3 vmin, vmax;
for (int i = 0; i < 6; i++) {
// X axis
if (p_planes[i].x > 0) {
vmin.x = m->getBBoxMin().x;
vmax.x = m->getBBoxMax().x;
}
else {
vmin.x = m->getBBoxMax().x;
vmax.x = m->getBBoxMin().x;
}
// Y axis
if (p_planes[i].y > 0) {
vmin.y = m->getBBoxMin().y;
vmax.y = m->getBBoxMax().y;
}
else {
vmin.y = m->getBBoxMax().y;
vmax.y = m->getBBoxMin().y;
}
// Z axis
if (p_planes[i].z > 0) {
vmin.z = m->getBBoxMin().z;
vmax.z = m->getBBoxMax().z;
}
else {
vmin.z = m->getBBoxMax().z;
vmax.z = m->getBBoxMin().z;
}
if (glm::dot(glm::vec3(p_planes[i]), vmin) + p_planes[i][3] > 0)
return true;
}
return false;
Any guidance?
Update 1: Normalizing the full vec4 representing the plane is incorrect as only the vec3 represents the normal of the plane. Further, normalization is not necessary for this instance as we only care about the sign of the distance (not the magnitude).
It is also important to note that I should be using the rows of the matrix not the columns. I am achieving this by replacing
p_planes[0] = comboMatrix[3] + comboMatrix[0];
with
p_planes[0] = glm::row(comboMatrix, 3) + glm::row(comboMatrix, 0);
in all instances.
You are using GLM incorrectly. As per the paper of Gribb and Hartmann, you can extract the plane equations as a sum or difference of different rows of the matrix, but in glm, mat4 foo; foo[n] will yield the n-th column (similiar to how GLSL is designed).
This here
for (int i = 0; i < 6; i++){
p_planes[i] = glm::normalize(p_planes[i]);
}
also doesn't make sense, since glm::normalize(vec4) will simply normalize a 4D vector. This will result in the plane to be shifted around along its normal direction. Only thexyz components must be brought to unit length, and w must be scaled accordingly. It is even explained in details in the paper itself. However, since you only need to know on which half-space a point lies, normalizing the plane equation is a waste of cycles, you only care about the sign, not the maginitude of the value anyway.
After following #derhass solution for normalizing the planes correctly for intersection tests you would do as follows
For bounding box plane intersection after projecting your box onto that plane which we call p and after calculating the midpoint of the box say m and after calculating the distance of that mid point from the plane say d to check for intersection we do
d<=p
But for frustum culling we just don't want our box to NOT intersect wih our frustum plane but we want it to be at -p distance from our plane and only then we know for sure that NO PART of our box is intersecting our plane that is
if(d<=-p)//then our box is fully not intersecting our plane so we don't draw it or cull it[d will be negative if the midpoint lies on the other side of our plane]
Similarly for triangles we have check if the distance of ALL 3 points of the triangle from the plane are negative.
To project a box onto a plane we take the 3 axises[x,y,z UNIT VECTORS] of the box,scale them by the boxes respective HALF width,height,depth and find the sum of each of their dot products[Take only the positive magnitude of each dot product NO SIGNED DISTANCE] with the planes normal which will be your 'p'
Not with the above approach for an AABB you can also cull against OOBB's with the same approach cause only the axises will change.
EDIT:
how to project a bounding box onto a plane?
Let's consider an AABB for our example
It has the following parameters
Lower extent Min(x,y,z)
Upper extent Max(x,y,z)
Up Vector U=(0,1,0)
Left Vector. L=(1,0,0)
Front Vector. F=(0,0,1)
Step 1: calculate half dimensions
half_width=(Max.x-Min.x)/2;
half_height=(Max.y-Min.y)/2;
half_depth=(Max.z-Min.z)/2;
Step 2: Project each individual axis of the box onto the plane normal,take only the positive magnitude of each dot product scaled by each half dimension and find the total sum. make sure both the box axis and the plane normal are unit vectors.
float p=(abs(dot(L,N))*half_width)+
(abs(dot(U,N))*half_height)+
(abs(dot(F,N))*half_depth);
abs() returns absolute magnitude we want it to be positive
because we are dealing with distances
Where N is the planes normal unit vector
Step 3: compute mid point of box
M=(Min+Max)/2;
Step 4: compute distance of the mid point from plane
d=dot(M,N)+plane.w
Step 5: do the check
d<=-p //return true i.e don't render or do culling
U can see how to use his for OOBB where the U,F,L vectors are the axises of the OOBB and the centre(mid point) and half dimensions are parameters you pass in manually
For an sphere as well you would calculate the distance of the spheres center from the plane (called d) but do the check
d<=-r //radius of the sphere
Put this in an function called outside(Plane,Bounds) which returns true if the bounds is fully outside the plane then for each of the 6 planes
bool is_inside_frustum()
{
for(Plane plane:frustum_planes)
{
if(outside(plane,AABB))
{
return false
}
}
return true;
}
I'm having difficulty getting the right orientation from my objects within a scene. The objects are defined in standard Cartesian coordinates in the same units as I define the scene.
I then define my scenes matrix with the following code:
void SVIS_SetLookAt (double eyePos[3], double center[3], double up[3])
{
// Determine the new n
double vN[3] = {eyePos[0] - center[0], eyePos[1] - center[1], eyePos[2] - center[2]};
// Don't I need to normalize the above?
// Determine the new up by crossing witht he Up Vector.
double vU[3];
MATH_crossproduct(up, vN, vU);
MATH_NormalizeVector(vN);
MATH_NormalizeVector(vU);
// Determine V by crossing n and u...
double vV[3];
MATH_crossproduct(vN, vU, vV);
MATH_NormalizeVector(vV);
// Create the model view matrix.
double modelView[16] = {
vU[0], vV[0], vN[0], 0,
vU[1], vV[1], vN[1], 0,
vU[2], vV[2], vN[2], 0,
// -MATH_Dotd(eyePos, vU), -MATH_Dotd(eyePos, vV), -MATH_Dotd(eyePos, vN), 1
0, 0, 0, 1
};
// Load the modelview matrix. The model view matrix shoudl already be active.
glLoadMatrixd(modelView);
}
I am attempting to display n-1 objects such that each object is facing the object in front of it, excluding the first object which is not displayed. So for each object, I define the up, right, and forward vectors as such:
lal_to_ecef(curcen, pHits->u); // up vector is our position normalized
MATH_subtractVec3D((SVN_VEC3D*) prevcenter, (SVN_VEC3D*) curcen, (SVN_VEC3D*) pHits->f);
MATH_NormalizeVector(pHits->u);
MATH_NormalizeVector(pHits->f);
MATH_crossproduct(pHits->u, pHits->f, pHits->r);
MATH_NormalizeVector(pHits->r);
MATH_crossproduct(pHits->f, pHits->r, pHits->u);
MATH_NormalizeVector(pHits->u);
I then go on to display each object with the following code:
double p[3] = {pHits->cen[0] - position[0],
pHits->cen[1] - position[1],
pHits->cen[2] - position[2]};
glPushMatrix();
SVIS_LookAt(pHits->u, pHits->f, pHits->r, p);
glCallList(G_svisHitsListId);
glPopMatrix();
void SVIS_LookAt (double u[3], double f[3], double l[3], double pos[3])
{
double model[16] = {
l[0], u[0], f[0], 0,
l[1], u[1], f[1], 0,
l[2], u[2], f[2], 0,
pos[0], pos[1], pos[2], 1
};
glMultMatrixd(model);
}
I would expect this to work for any object such that the output would be whatever was defined in the Cartesian coordinate system would be present at the given point oriented such that it was pointed at the proceeding object with 0,1,0 and 0,-1,0 from the defined object would be aligned vertically on the screen. What I am seeing instead (by using simple rectangle as the object to be displayed) is that the objects are consistently rotated about the forward axis.
Can anyone point out what I am doing wrong here?
[Edit]
I've displayed an axis grid without translating by taking the three vectors multiplying a scalar and adding/subtracting it to the centre point. Doing this, the axis align up as I would expect. Overlaying the object described above shows the object to not be aligned the same way. Is there a relationship between the object space forward, right, and up vectors and the desired world-space vectors that I am missing? Am I simply completely off the mark with regards to my rotation translation matrix?
You are conflicted here; part of that matrix is transposed and part of
it is correct... you have the 4th column correct but your top-left 3x3
matrix is transposed. Each column of the 3x3 matrix (row in that array
of 16 double) is supposed to be one of your axes. It should be:
l[0],l[1],l[2],0, u[0],u[1],u[2],0, f[0],f[1],f[2],0,
pos[0],pos[1],pos[2],1. – Andon M. Coleman
This was dead on. Thanks Andon.
Building an entirely new modelview matrix from scratch using a 'lookat' implementation for each object is, frankly, crazy (or will at least drive you crazy). What you're doing is tantamount to trying to build a scene by having set of objects which are always in a fixed location, and constantly repositioning a camera to catch them from different angles.
A lookat style function should be called once to set up the camera (the view portion of the modelview matrix) position, and subsequently you should be using the matrix stack to position objects within the scene (the model portion of the modelview matrix). That's why it's called the modelview matrix, and not just the view matrix.
In code terms, it would look something like this
// Set up camera position
SVIS_LookAt(....);
for (int i = 0; i < n; ++i) {
glPushMatrix();
// move the object to it's location relative to the world coordinate system
glTranslate(...);
// rotate the object to have the correct orientation
glRotate(...);
// render the geometry
glCallList(...);
glPopMatrix();
}
Of course this assumes that everything has it's position defined in world coordinates. If you have a hierarchy of objects, then you would need to descend into an objects children between the glCallList and glPopMatrix in order to have their locations applied relative to their parent object.
I needed to implement 'choosing an object' in a 3D environment. So instead of going with robust, accurate approach, such as raycasting, I decided to take the easy way out. First, I transform the objects world position onto screen coordinates:
glm::mat4 modelView, projection, accum;
glGetFloatv(GL_PROJECTION_MATRIX, (GLfloat*)&projection);
glGetFloatv(GL_MODELVIEW_MATRIX, (GLfloat*)&modelView);
accum = projection * modelView;
glm::mat4 transformed = accum * glm::vec4(objectLocation, 1);
Followed by some trivial code to transform the opengl coordinate system to normal window coordinates, and do a simple distance from the mouse check. BUT that doesn't quite work. In order to translate from world space to screen space, I need one more calculation added on to the end of the function shown above:
transformed.x /= transformed.z;
transformed.y /= transformed.z;
I don't understand why I have to do this. I was under the impression that, once one multiplied your vertex by the accumulated modelViewProjection matrix, you had your screen coordinates. But I have to divide by Z to get it to work properly. In my openGL 3.3 shaders, I never have to divide by Z. Why is this?
EDIT: The code to transform from from opengl coordinate system to screen coordinates is this:
int screenX = (int)((trans.x + 1.f)*640.f); //640 = 1280/2
int screenY = (int)((-trans.y + 1.f)*360.f); //360 = 720/2
And then I test if the mouse is near that point by doing:
float length = glm::distance(glm::vec2(screenX, screenY), glm::vec2(mouseX, mouseY));
if(length < 50) {//you can guess the rest
EDIT #2
This method is called upon a mouse click event:
glm::mat4 modelView;
glm::mat4 projection;
glm::mat4 accum;
glGetFloatv(GL_PROJECTION_MATRIX, (GLfloat*)&projection);
glGetFloatv(GL_MODELVIEW_MATRIX, (GLfloat*)&modelView);
accum = projection * modelView;
float nearestDistance = 1000.f;
gameObject* nearest = NULL;
for(uint i = 0; i < objects.size(); i++) {
gameObject* o = objects[i];
o->selected = false;
glm::vec4 trans = accum * glm::vec4(o->location,1);
trans.x /= trans.z;
trans.y /= trans.z;
int clipX = (int)((trans.x+1.f)*640.f);
int clipY = (int)((-trans.y+1.f)*360.f);
float length = glm::distance(glm::vec2(clipX,clipY), glm::vec2(mouseX, mouseY));
if(length<50) {
nearestDistance = trans.z;
nearest = o;
}
}
if(nearest) {
nearest->selected = true;
}
mouseRightPressed = true;
The code as a whole is incomplete, but the parts relevant to my question works fine. The 'objects' vector contains only one element for my tests, so the loop doesn't get in the way at all.
I've figured it out. As Mr David Lively pointed out,
Typically in this case you'd divide by .w instead of .z to get something useful, though.
My .w values were very close to my .z values, so in my code I change the statement:
transformed.x /= transformed.z;
transformed.y /= transformed.z;
to:
transformed.x /= transformed.w;
transformed.y /= transformed.w;
And it still worked just as before.
https://stackoverflow.com/a/10354368/2159051 explains that division by w will be done later in the pipeline. Obviously, because my code simply multiplies the matrices together, there is no 'later pipeline'. I was just getting lucky in a sense, because my .z value was so close to my .w value, there was the illusion that it was working.
The divide-by-Z step effectively applies the perspective transformation. Without it, you'd have an iso view. Imagine two view-space vertices: A(-1,0,1) and B(-1,0,100).
Without the divide by Z step, the screen coordinates are equal (-1,0).
With the divide-by-Z, they are different: A(-1,0) and B(-0.01,0). So, things farther away from the view-space origin (camera) are smaller in screen space than things that are closer. IE, perspective.
That said: if your projection matrix (and matrix multiplication code) is correct, this should already be happening, as the projection matrix will contain 1/Z scaling components which do this. So, some questions:
Are you really using the output of a projection transform, or just the view transform?
Are you doing this in a pixel/fragment shader? Screen coordinates there are normalized (-1,-1) to (+1,+1), not pixel coordinates, with the origin at the middle of the viewport. Typically in this case you'd divide by .w instead of .z to get something useful, though.
If you're doing this on the CPU, how are you getting this information back to the host?
I guess it is because you are going from 3 dimensions to 2 dimensions, so you are normalizing the 3 dimension world to a 2 dimensional coordinates.
P = (X,Y,Z) in 3D will be q = (x,y) in 2D where x=X/Z and y = Y/Z
So a circle in 3D will not be circle in 2D.
You can check this video out:
https://www.youtube.com/watch?v=fVJeJMWZcq8
I hope I understand your question correctly.
I am doing a program to test sphere-frustum intersection and being able to determine the sphere's visibility. I am extracting the frustum's clipping planes into camera space and checking for intersection. It works perfectly for all planes except the far plane and I cannot figure out why. I keep pulling the camera back but my program still claims the sphere is visible, despite it having been clipped long ago. If I go far enough it eventually determines that it is not visible, but this is some distance after it has exited the frustum.
I am using a unit sphere at the origin for the test. I am using the OpenGL Mathematics (GLM) library for vector and matrix data structures and for its built in math functions. Here is my code for the visibility function:
void visibilityTest(const struct MVP *mvp) {
static bool visLastTime = true;
bool visThisTime;
const glm::vec4 modelCenter_worldSpace = glm::vec4(0,0,0,1); //at origin
const int negRadius = -1; //unit sphere
//Get cam space model center
glm::vec4 modelCenter_cameraSpace = mvp->view * mvp->model * modelCenter_worldSpace;
//---------Get Frustum Planes--------
//extract projection matrix row vectors
//NOTE: since glm stores their mats in column-major order, we extract columns
glm::vec4 rowVec[4];
for(int i = 0; i < 4; i++) {
rowVec[i] = glm::vec4( mvp->projection[0][i], mvp->projection[1][i], mvp->projection[2][i], mvp->projection[3][i] );
}
//determine frustum clipping planes (in camera space)
glm::vec4 plane[6];
//NOTE: recall that indices start at zero. So M4 + M3 will be rowVec[3] + rowVec[2]
plane[0] = rowVec[3] + rowVec[2]; //near
plane[1] = rowVec[3] - rowVec[2]; //far
plane[2] = rowVec[3] + rowVec[0]; //left
plane[3] = rowVec[3] - rowVec[0]; //right
plane[4] = rowVec[3] + rowVec[1]; //bottom
plane[5] = rowVec[3] - rowVec[1]; //top
//extend view frustum by 1 all directions; near/far along local z, left/right among local x, bottom/top along local y
// -Ax' -By' -Cz' + D = D'
plane[0][3] -= plane[0][2]; // <x',y',z'> = <0,0,1>
plane[1][3] += plane[1][2]; // <0,0,-1>
plane[2][3] += plane[2][0]; // <-1,0,0>
plane[3][3] -= plane[3][0]; // <1,0,0>
plane[4][3] += plane[4][1]; // <0,-1,0>
plane[5][3] -= plane[5][1]; // <0,1,0>
//----------Determine Frustum-Sphere intersection--------
//if any of the dot products between model center and frustum plane is less than -r, then the object falls outside the view frustum
visThisTime = true;
for(int i = 0; i < 6; i++) {
if( glm::dot(plane[i], modelCenter_cameraSpace) < static_cast<float>(negRadius) ) {
visThisTime = false;
}
}
if(visThisTime != visLastTime) {
printf("Sphere is %s visible\n", (visThisTime) ? "" : "NOT " );
visLastTime = visThisTime;
}
}
The polygons appear to be clipped by the far plane properly so it seems that the projection matrix is set up properly, but the calculations make it seem like the plane is way far out. Perhaps I am not calculating something correctly or have a fundamental misunderstanding of the calculations that are required?
The calculations that deal specifically with the far clipping plane are:
plane[1] = rowVec[3] - rowVec[2]; //far
and
plane[1][3] += plane[1][2]; // <0,0,-1>
I'm setting the plane to be equal to the 4th row (or in this case column) of the projection matrix - the 3rd row of the projection matrix. Then I'm extending the far plane one unit further (due to the sphere's radius of one; D' = D - C(-1) )
I've looked over this code many times and I can't see why it shouldn't work. Any help is appreciated.
EDIT:
I can't answer my own question as I don't have the rep, so I will post it here.
The problem was that I wasn't normalizing the plane equations. This didn't seem to make much of a difference for any of the clip planes besides the far one, so I hadn't even considered it (but that didn't make it any less wrong). After normalization everything works properly.
I'm having an issue with drawing a model and rotating it using the mouse,
I'm pretty sure there's a problem with the mathematics but not sure .
The object just rotates in a weird way.
I want the object to start rotating each click from its current spot and not reset because of the
vectors are now changed and the calculation starts all over again.
void DrawHandler::drawModel(Model * model){
unsigned int l_index;
glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
glMatrixMode(GL_MODELVIEW); // Modeling transformation
glLoadIdentity();
Point tempCross;
crossProduct(tempCross,model->getBeginRotate(),model->getCurrRotate());
float tempInner= innerProduct(model->getBeginRotate(),model->getCurrRotate());
float tempNormA =normProduct(model->getBeginRotate());
float tempNormB=normProduct(model->getCurrRotate());
glTranslatef(0.0,0.0,-250.0);
glRotatef(acos (tempInner/(tempNormA*tempNormB)) * 180.0 / M_PI,tempCross.getX(),tempCross.getY(),tempCross.getZ());
glColor3d(1,1,1);
glBegin(GL_TRIANGLES);
for (l_index=0;l_index < model->getTrianglesDequeSize() ;l_index++)
{
Triangle t = model->getTriangleByPosition(l_index);
Vertex a1 = model->getVertexByPosition(t.getA());
Vertex a2 = model->getVertexByPosition(t.getB());
Vertex a3 = model->getVertexByPosition(t.getC());
glVertex3f( a1.getX(),a1.getY(),a1.getZ());
glVertex3f( a2.getX(),a2.getY(),a2.getZ());
glVertex3f( a3.getX(),a3.getY(),a3.getZ());
}
glEnd();
}
This is the mouse function which saves the beginning vector of the rotating formula
void Controller::mouse(int btn, int state, int x, int y)
{
x=x-WINSIZEX/2;
y=y-WINSIZEY/2;
if (btn==GLUT_LEFT_BUTTON){
switch(state){
case(GLUT_DOWN):
if(!_rotating){
_model->setBeginRotate(Point(float(x),float(y),
(-float(x)*x - y*y + SPHERERADIUS*SPHERERADIUS < 0)? 0:float(sqrt(-float(x)*x - y*y + SPHERERADIUS*SPHERERADIUS))));
_rotating=true;
}
break;
case(GLUT_UP):
_rotating=false;
break;
}
}
}
and finally the following function which holds the current vector.
(the beginning vector is where the mouse was clicked at
and the curr vector is where the mouse position at the moment )
void Controller::getMousePosition(int x,int y){
x=x-WINSIZEX/2;
y=y-WINSIZEY/2;
if(_rotating){
_model->setCurrRotate(Point(float(x),float(y),
(-float(x)*x - y*y + SPHERERADIUS*SPHERERADIUS < 0)? 0:float(sqrt(-float(x)*x - y*y + SPHERERADIUS*SPHERERADIUS))));
}
}
where sphereradius is the sphere radius O_O of 70 degress
is any calculation wrong ? cant seem to find the problem...
thanks
Why so complicated? Either you change the view matrix or you change the model matrix of your focused object. If you choose to change the model matrix and your object is centered in (0,0,0) of the world coordinate system, computing the rotation around a sphere illusion is trivial - you just rotate into the opposite direction. If you want to change the view matrix (which is actually done when you change the position of the camera) you have to approximate the surface points on the chosen sphere. Therefore, you could introduce two parameters specifying two angles. Everytime you click move your mouse, you update the params and compute the new locations on the sphere. There are some useful equations in [http://en.wikipedia.org/wiki/Sphere].
Without knowing what library (or libraries) you're using your code is rather difficult to read. It seems you're setting up your camera at (0, 0, -250), looking towards the origin, then rotating around the origin by the angle between two vectors, model->getCurrRotate() and model->getBeginRotate().
The problem seems to be that in "mouse down" events you explicitly set BeginRotate to the point on the sphere under the mouse, then in "mouse move" events you set CurrRotate to the point under the mouse, so every time you click somewhere else, you lose the previous state of rotation because BeginRotate and CurrRotate are simply overwritten.
Combining multiple rotations around arbitrary different axes is not a trivially simple task. The proper way to do it is to use quaternions. You may find this primer on quaternions and other 3D math concepts useful.
You might also want a more robust algorithm for converting screen coordinates to model coordinates on the sphere. The one you are using is assuming the sphere appears 70 pixels in radius on the screen and that the projection matrix is orthographic.