Here is a table I have created. I just want to make it stand out a little bit.
I have figured out how to make rows different colours. I know how to make an entire row or column bold (column_spec(5:7, bold = T)) but I would like specific cells only based on highest value...so for example in my table, I would like 147 in bold under number, 2.36 under mean....etc
Is there a way of doing this? Using conditional logic would be even better if that was possible - but I can't find how it is done?
Thanks
I figured it out - pretty simple:
test.attempt[1, 5] <- cell_spec(test.attempt[1, 5], "latex", bold = T)
Related
I want this formula to calculate a date based on input from two other dates. I first wrote it for a single cell and it gives the expected results but when I try to use ARRAYFORMULA it returns the wrong results.
I first use two if statements specifycing what should happen if either one of the inputs is missing. Then the final if statement calculates the date if both are present based on two conditions. This seems to work perfectly if I write the formula for one cell and drag it down.
=IF( (LEN(G19)=0);(U19+456);(IF((LEN(U19)=0) ;(G19);(IF((AND((G19<(U19+456));(G19>(U19+273)) ));(G19);(U19+456))))))
However, when I want to use arrayformula to apply it to the entire column, it always returns the value_if_false if neither cell is empty, regardless of whether the conditions in the if statement are actually met or not. I am specifically talking about the last part of the formula that calculates the date if both input values are present, it always returns the result of U19:U+456 even when the result should be G19:G. Here is how I tried to write the ARRAYFORMULA:
={"Date deadline";ARRAYFORMULA(IF((LEN(G19:G400)=0);(U19:U400+456);(IF((LEN(U19:U400)=0);
(G19:G400);(IF((AND((G19:G400<(U19:U400+456));(G19:G400>(U19:U400+273)) ));(G19:G400);(U19:U400+456)))))))}
I am a complete beginner who only learned to write formulas two weeks ago, so any help or tips would be greatly appreciated!
AND and OR are not compatible with ARRAYFORMULA
Replace them by * or +
Try
={"Date deadline";ARRAYFORMULA(
IF((LEN(G19:G400)=0),(U19:U400+456),
(IF((LEN(U19:U400)=0), (G19:G400),
(IF((((G19:G400<(U19:U400+456))*(G19:G400>(U19:U400+273)) )),(G19:G400),
(U19:U400+456)))
))
)
)}
Keep in mind you cannot use AND, OR operators in an arrayformula, so you must find an alternative method such as multiplying the values together and checking them for 0 or 1 (true*true=1)
I am gathering based on your formula's and work that you want to have the following:
If G19 is blank show U19 + 456
If U19 is blank show G19
If G19 is less than U19 + 456 but greater than U19 + 273 show G19
Otherwise show U19 + 456
I'm not too sure what you want to happen when both columns G and U are empty. Based on your current formula you are returning an empty cell + 456... but with this formula it returns an empty cell rather than Column U + 456
Formula
={"Date deadline";ARRAYFORMULA(TO_DATE(ARRAYFORMULA(IFS((($G19:$G400="")*($U19:$U400=""))>0,"",$G19:$G400="",$U19:$U400+456,$U19:$U400="",$G19:$G400,(($G19:$G400<$U19:$U400+456)*($G19:$G400>$U19:$U400+273))>0,$G19:$G400,TRUE,$U19:$U400+456))))}
in my Google sheet table I have the first list with summary of invoices which are then separated to 4 lists according to parameters (manually). I need to know about all invoices from the first list, on which category/list they are.
So for example - lists: Alphabet, abc, def, mno, xyz. In Alphabet is column "list".
How to write function which found invoice on another list according to ID (column B) from Alphabet and write name of the correct list to column "list". I tried to write this function using IF, match, etc. But I still don't have solution. Can you help me please? Sorry for my English :-)
So here is an example which you could adapt. In columns E:H on the first sheet (and I could hide these columns later, starting in row2 and dragging down as needed, I put the following formulas:
=IF(LEN(iferror(query(abc!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"abc","")
=IF(LEN(iferror(query(def!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"def","")
=IF(LEN(iferror(query(mno!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"mno","")
=IF(LEN(iferror(query(xyz!$A$2:$A,"select A where A='" & $A2 &"'"),""))>0,"xyz","")
Probably I could have simplified a little by putting the sheet names in E1:H1, but you get the idea.
Each of these looks for the ID. If the query succeeds, it returns the name of the sheet. If it fails, it returns the empty string.
Now in column B where I actually want the results, I put this formula in B2 and drag to copy as needed.
=if(E2&F2&G2&H2="","nowhere",E2&F2&G2&H2)
It says put those strings together, and if there is nothing there say nowhere, otherwise say the list. If it appears on more than one, and that can really happen, you could use JOIN instead.
So im making a spreadsheet for fun but I need some help because it would be generous to say my experience is amateur level.
I want to change the color of the cell to the same color if they contain one of a range of different values (all string text)
Example: If cell contains "XXX" or "YYY" or "ZZZ" then colorchange =true, else color = white
I don't really want to have to make separate rules for each string because theres about 80 of them in total
use custom formula:
=REGEXMATCH(A1, "XXX|YYY|ZZZ")
note its case sensitive so to turn off the sensitivity do:
=REGEXMATCH(UPPER(A1), "XXX|YYY|ZZZ")
you can also put your 80 values in a column and use:
=REGEXMATCH(A1, TEXTJOIN("|", 1, Z:Z))
where Z:Z contains all your values
if you want to put those values on a different sheet use:
=REGEXMATCH(A1, TEXTJOIN("|", 1, INDIRECT("Sheet2!Z:Z")))
I have a spreadsheet set up with tv program titles in column B, the next 20 or so columns are tracking different information about that title. I need to count the number of blank cells in column R relating to the range in column B that contains titles (ie, up to the first blank row in column B.)
I can easily set up a formula to count the number of empty cells in a given range in column R, the problem is as I add more titles to the sheet I would have to keep updating the range in the formula [a simple =COUNTIF(R3:R1108, "")]. I've done a little googling of the problem but haven't quite found anything that fits the situation. I thought I would be able to get the following to work but I didn't fully understand what was going on with them and they weren't giving the expected results.
I've tried these formulas:
=ArrayFormula(sum(MIN("B3:B"&MIN(IF((R3:R)>"",ROW(B3:B)-1)))))
=ArrayFormula(sum(INDIRECT("B3:B"&MIN(IF((R3:R)>"",ROW(B3:B)-1)))))
And
=if(SUM(B3:B)="","",SUM(R3:R))
All of the above formulas give "0" as the result. Based on the COUNTIF formula I have set up it should be 840, which is a number I would expect. Currently, there are 1106 rows containing data and 840 is a reasonable number to expect in this situation.
Is this what you're looking for?
=COUNTBLANK(INDIRECT(CONCATENATE("R",3,":R",(3+COUNTA(B3:B)))))
This counts the number of non-blank rows in the B column (starting at B3), and uses that to determine the rows to perform COUNTBLANK in, in column R (starting at R3). CONCATENATE is a way to give it a range by adding strings together, and the INDIRECT allows for the range reference to be a string.
a proper way would be:
=ARRAYFORMULA(COUNTBLANK(INDIRECT(ADDRESS(3, 18, 4)&":"&
ADDRESS(MAX(IF(B3:B<>"", ROW(B3:B), )), 18, 4)))
or shorter:
=ARRAYFORMULA(COUNTBLANK(INDIRECT("R3:"&
ADDRESS(MAX(IF(B3:B<>"", ROW(B3:B), )), 18, 4))))
or shorter:
=ARRAYFORMULA(COUNTBLANK(INDIRECT("R3:R"&MAX(IF(B3:B<>"", ROW(B3:B), ))))
I appreciate that what I'm trying to do will sound silly, but please bear with me. I want to insert an existing image (a PNG) of a table into an RMarkdown document that will be turned into a pdf. Is there any way I can do this and have the image treated as a table for numbering purposes? That is, obviously I could do
but the problem is that it will be numbered as e.g. Figure X, not Table Y. I would like it to be named/numbered as a table.
Thank you for any advice.
Looks like I got to a way to do it with kable with some inspiration...this still has two horizontal lines but that's ok for the moment:
```{r echo=F, warning=F}
temp.df = data.frame(image="")
temp.mat <- as.matrix(temp.df)
colnames(temp.mat) <- NULL
knitr::kable(temp.mat, caption="This is my caption")
```
Edit: as suggested by #HoneyBuddha, when using Bookdown, you must add the flag format="pandoc", i.e. knitr::kable(temp.mat, caption="This is my caption", format="pandoc")