Getting in error while performing Nested STRUCT in C++ - c++

Question

I am solving a question of Nested structure in C++ but
I am getting an error in accessing the member function of struct Date i.e: void showdata()
First I have made a Data struct then in it I have added member function called void showdata which will show data of my another Struct Employee. However I can't access this member function in my main program.
ERROR :
Error C2660 'Date::showdata': function does not take 0 arguments
so basically getting an error in the last line of code that is:
d.showdata()
Here's my code:
struct Date
{
int year, month, date;
void showdata(int empid, string name, double salary, int year, int month,int date)
{
cout << "\t\tEmployee's Data:\n";
cout << "Employee ID --> " << empid << endl;
cout << "Employee Name --> " << name << endl;
cout << "Salary --> " << salary << endl;
cout << "Joining Date -- >" << date << "-" << month << "-" << year << endl;
}
};
struct Employee
{
int empid;
string name;
double salary;
Date joiningdate;
};
int main()
{
//Q3
Employee e;
Date d;
cout << "Enter Employee ID = ";
cin >> e.empid;
cout << "Enter Employee Name = ";
cin >> e.name;
cout << "Enter Salary = ";
cin >> e.salary;
cout << "Enter Employee joining year = ";
cin >> e.joiningdate.year;
cout << "Enter Employee joining month = ";
cin >> e.joiningdate.month;
cout << "Enter Employee joining date = ";
cin >> e.joiningdate.date;
d.showdata();
}

Answer 1

Did you mean to move the member function into the Employee class?
struct Date
{
int year, month, date;
};
struct Employee
{
int empid;
string name;
double salary;
Date joiningdate;
void showdata()
{
cout << "\t\tEmployee's Data:\n";
cout << "Employee ID --> " << empid << endl;
cout << "Employee Name --> " << name << endl;
cout << "Salary --> " << salary << endl;
cout << "Joining Date -- >" << joiningdate.date << "-" << joiningdate.month << "-" << joiningdate.year << endl;
}
};
int main()
{
//Q3
Employee e;
cout << "Enter Employee ID = ";
cin >> e.empid;
cout << "Enter Employee Name = ";
cin >> e.name;
cout << "Enter Salary = ";
cin >> e.salary;
cout << "Enter Employee joining year = ";
cin >> e.joiningdate.year;
cout << "Enter Employee joining month = ";
cin >> e.joiningdate.month;
cout << "Enter Employee joining date = ";
cin >> e.joiningdate.date;
e.showdata();
}

Answer 2

You defined the showdata method inside the Date struct to take 6 arguments, yet when invoking the method in main you are supplying 0 arguments. To correctly invoke the showdata method you need to supply it with the correct set of parameters:
d.showdata(e.empid, e.name, e.salary, e.joiningdate.year, e.joiningdate.month, e.joiningdate.date);
Also be sure to check that the parameter types that you are passing in match the argument types that you defined the method to accept.