I'm new to Python and currently learning Regular Expressions.
The code I made is:
import re
text = ('Batmobile lost a wheel. At least Batcopter is still okay.')
batRegex = re.compile(r'Bat(man|mobile|copter|bat')
mo = batRegex.findall(text)
print(mo)
When I run this, I get this:
['mobile', 'copter']
But I want to get something like:
['Batmobile', 'Batcopter']
So I re-coded according to the comment,
and changing
batRegex = re.compile(r'Bat(man|mobile|copter|bat')
to
batRegex = re.compile(r'Bat(?:man|mobile|copter|bat)')
yields the desired result of:
['Batmobile', 'Batcopter']
That solves the problem!
Related
I'm trying to write a script to update a text file by replacing instances of certain characters, (i.e. 'a', 'w') with a word (i.e. 'airplane', 'worm').
If a single line of the text was something like this:
a.function(); a.CallMethod(w); E.aa(w);
I'd want it to become this:
airplane.function(); airplane.CallMethod(worm); E.aa(worm);
The difference is subtle but important, I'm only changing 'a' and 'w' where it's used as a variable, not just another character in some other word. And there's many lines like this in the file. Here's what I've done so far:
original = open('original.js', 'r')
modified = open('modified.js', 'w')
# iterate through each line of the file
for line in original:
# Search for the character 'a' when not part of a word of some sort
line = re.sub(r'\W(a)\W', 'airplane', line)
modified.write(line)
original.close()
modified.close()
I think my RE pattern is wrong, and I think i'm using the re.sub() method incorrectly as well. Any help would be greatly appreciated.
If you're concerned about the semantic meaning of the text you're changing with a regular expression, then you'd likely be better served by parsing it instead. Luckily python has two good modules to help you with parsing Python. Look at the Abstract Syntax Tree and the Parser modules. There's probably others for JavaScript if that's what you're doing; like slimit.
Future reference on Regular Expression questions, there's a lot of helpful information here:
https://stackoverflow.com/tags/regex/info
Reference - What does this regex mean?
And it took me 30 minutes from never having used this JavaScript parser in Python (replete with installation issues: please note the right ply version) to writing a basic solution given your example. You can too.
# Note: sudo pip3 install ply==3.4 && sudo pip3 install slimit
from slimit import ast
from slimit.parser import Parser
from slimit.visitors import nodevisitor
data = 'a.funktion(); a.CallMethod(w); E.aa(w);'
tree = Parser().parse(data)
for node in nodevisitor.visit(tree):
if isinstance(node, ast.Identifier):
if node.value == 'a':
node.value = 'airplaine'
elif node.value == 'w':
node.value = 'worm'
print(tree.to_ecma())
It runs to give this output:
$ python3 src/python_renames_js_test.py
airplaine.funktion();
airplaine.CallMethod(worm);
E.aa(worm);
Caveats:
function is a reserved word, I used funktion
the to_ecma method pretty prints; there is likely another way to output it closer to the original input.
line = re.sub(r'\ba\b', 'airplane', line)
should get you closer. However, note that you will also be replacing a.CallMethod("That is a house") into airplane("That is airplane house"), and open("file.txt", "a") into open("file.txt", "airplane"). Getting it right in a complex syntax environment using RegExp is hard-to-impossible.
I have a CSV file containing user (tweetid, tweets, userid).
396124436476092416,"Think about the life you livin but don't think so hard it hurts Life is truly a gift, but at the same it is a curse",Obey_Jony09
396124436740317184,"“#BleacherReport: Halloween has given us this amazing Derrick Rose photo (via #amandakaschube, #ScottStrazzante) http://t.co/tM0wEugZR1” yes",Colten_stamkos
396124436845178880,"When's 12.4k gonna roll around",Matty_T_03
Now I need to write a Pig Query that returns all the tweets that include the word 'favorite', ordered by tweet id.
For this I have the following code:
A = load '/user/pig/tweets' as (line);
B = FOREACH A GENERATE FLATTEN(REGEX_EXTRACT_ALL(line,'(.*)[,”:-](.*)[“,:-](.*)')) AS (tweetid:long,msg:chararray,userid:chararray);
C = filter B by msg matches '.*favorite.*';
D = order C by tweetid;
How does the regular expression work here in splitting the output in desired way?
I tried using REGEX_EXTRACT instead of REGEX_EXTRACT_ALL as I find that much more simpler, but couldn't get the code working except for extracting just the tweets:
B = FOREACH A GENERATE FLATTEN(REGEX_EXTRACT(line,'[,”:-](.*)[“,:-]',1)) AS (msg:chararray);
the above alias gets me the tweets, but if I use REGEX_EXTRACT to get the tweet_id, I do not get the desired o/p: B = FOREACH A GENERATE FLATTEN(REGEX_EXTRACT(line,'(.*)[,”:-]',1)) AS (tweetid:long);
(396124554353197056,"Just saw #samantha0wen and #DakotaFears at the drake concert #waddup")
(396124554172432384,"#Yutika_Diwadkar I'm just so bright 😁")
(396124554609033216,"#TB23GMODE i don't know, i'm just saying, why you in GA though? that's where you from?")
(396124554805776385,"#MichaelThe_Lion me too 😒")
(396124552540852226,"Happy Halloween from us 2 #maddow & #Rev_AlSharpton :) http://t.co/uC35lDFQYn")
grunt>
Please help.
Can't comment, but from looking at this and testing it out, it looks like your quotes in the regex are different from those in the csv.
" in the csv
” in the regex code.
To get the tweetid try this:
B = FOREACH A GENERATE FLATTEN(REGEX_EXTRACT(line,'.*(,")',1)) AS (tweetid:long);
I am trying to capture image url's from inside tweets.
REGISTER 'hdfs:///user/cloudera/elephant-bird-pig-4.1.jar';
REGISTER 'hdfs:///user/cloudera/elephant-bird-core-4.1.jar';
REGISTER 'hdfs:///user/cloudera/elephant-bird-hadoop-compat-4.1.jar';
--Load Json
loadJson = LOAD '/user/cloudera/tweetwall' USING com.twitter.elephantbird.pig.load.JsonLoader('-nestedLoad') AS (json:map []);
B = FOREACH loadJson GENERATE flatten(json#'tweets') as (m:map[]);
tweetText = FOREACH B GENERATE FLATTEN(m#'text') as (str:chararray);
intermediate date looks like this:
(#somenameontwitter your nan makes me laugh with some of the things she comes out with like http://somepics.com/my.jpg)
then I try to do the following to get only the image url back :
x = foreach tweetText generate REGEX_EXTRACT_ALL(str, '((http)(.*)(.jpg|.bmp|.png))');
dump x;
but that doesn't seem to work. I have also been trying with filter to no avail.
Even when trying the above with .* it returns empty results () or (())
I'm not good with regex and pretty new to Pig so it could be that I'm missing something simple here that I'm just not seeing.
update
example input data
{"tweets":[{"created_at":"Sat Nov 01 23:15:45 +0000 2014","id":5286804225,"id_str":"5286864225","text":"#Beace_ your nan makes me laugh with some of the things she comes out with blabla http://t.co/b7hjMWNg is an url, but not a valid one http://www.something.com/this.jpg should be a valid url","source":"\u003ca href=\"http:\/\/twitter.com\/download\/iphone\" rel=\"nofollow\"\u003eTwitter for iPhone\u003c\/a\u003e","truncated":false,"in_reply_to_status_id":52812992878592,"in_reply_to_status_id_str":"522","in_reply_to_user_id":398098,"in_reply_to_user_id_str":"3","in_reply_to_screen_name":"Be_","user":{"id":425,"id_str":"42433395","name":"SAINS","screen_name":"sa3","location":"Lincoln","profile_location":null,"description":"","url":null,"entities":{"description":{"urls":[]}},"protected":false,"followers_count":92,"friends_count":526,"listed_count":0,"created_at":"Mon May 25 16:18:05 +0000 2009","favourites_count":6,"utc_offset":0,"time_zone":"London","geo_enabled":true,"verified":false,"statuses_count":19,"lang":"en","contributors_enabled":false,"is_translator":false,"is_translation_enabled":false,"profile_background_color":"EDECE9","profile_background_image_url":"http:\/\/abs.twimg.com\/images\/themes\/theme3\/bg.gif","profile_background_image_url_https":"https:\/\/abs.twimg.com\/images\/themes\/theme3\/bg.gif","profile_background_tile":false,"profile_image_url":"http:\/\/pbs.twimg.com\/profile_images\/52016\/DGDCj67z_normal.jpeg","profile_image_url_https":"https:\/\/pbs.twimg.com\/profile_images\/526\/DGDCj67z_normal.jpeg","profile_banner_url":"https:\/\/pbs.twimg.com\/profile_banners\/424395\/13743515","profile_link_color":"088253","profile_sidebar_border_color":"D3D2CF","profile_sidebar_fill_color":"E3E2DE","profile_text_color":"634047","profile_use_background_image":true,"default_profile":false,"default_profile_image":false,"following":false,"follow_request_sent":false,"notifications":false},"geo":null,"coordinates":null,"place":null,"contributors":null,"retweet_count":0,"favorite_count":1,"entities":{"hashtags":[],"symbols":[],"user_mentions":[{"screen_name":"e_","name":"\u2601\ufe0f effy","id":3998,"id_str":"398","indices":[0,15]}],"urls":[]},"favorited":false,"retweeted":false,"lang":"en"}]}
Try this and let me know if this works
x = foreach tweetText generate REGEX_EXTRACT(str,'.*(http://.*.[jpg|bmp|png])',1);
DUMP x;
I managed to get it working (though I doubt it is totally optimal)
x = foreach tweetText generate REGEX_EXTRACT(str,'(http://.*(.jpg|.bmp|.png))',1) as image;
filtered = FILTER x BY $0 is not null;
dump filtered;
so the initial problem was just the regex (and my lack of knowledge on the subject).
Thanks for the assistance sivasakthi jayaraman!
I have an xml file that i need to find, multiply (e.g. by 1.25) and replace all prices.
Price tag looks like that:
<price><![CDATA[15.9]]></price>
The price tag should look like that after the operation:
<price><![CDATA[19.875]]></price>
Can this be done in Notepad++ or PowerGrep using a regular expression?
Thanks in advance.
As far as I know you can't use either program to preform the math but you can build a simple program in most any language of your choice to take a file use regex to find the number. Cast that string as a double do the math and put it back into the string. Later on today I could probably build something in c# but it should be relatively straight forward in most languages. You may even be able to build a shell script and use grep if you're not in a windows environment or use Powershell for windows but I have less experience with Powershell.
Edit: There is an easier way to do this http://msdn.microsoft.com/en-us/library/hcebdtae(v=vs.110).aspx
this is essentially what you want to do using the xmldocument object.
Edit2: I did this even though I couldn't get a hold of the original poster I thought someone might be able to use the info and I learned a lot. I can add the source code to github if anyone is interested.
public static void ChangePricesWork(string filepath, double multiply)
{
var document = new XmlDocument();
document.Load(filepath);
XmlNodeList nodeList = document.GetElementsByTagName("price");
foreach (XmlNode node in nodeList)
{
if (!string.IsNullOrEmpty(node.InnerText))
{
node.InnerText = Convert.ToString(multiplyPrice(multiply, node.InnerText));
}
}
string newFilePath = string.Format(#"{0}\{1}_updated.xml", Path.GetDirectoryName(filepath), Path.GetFileNameWithoutExtension(filepath));
document.Save(newFilePath);
}
private static double multiplyPrice(double multiply, string oldPrice)
{
var newPrice = new double();
if (Double.TryParse(oldPrice, out newPrice))
{
newPrice = newPrice * multiply;
}
return newPrice;
}
Notepad++ has a Pythonscript plugin that allows you to create quick Python scripts that have access to your document and Notepad++ itself.
The install and setup is described in this answer.
The API has moved on a little bit since then, you do a regular expression replace with Editor.rereplace now.
# Start a sequence of actions that is undone and redone as a unit. May be nested.
editor.beginUndoAction()
# multiply_price_cdata
from decimal import *
TWOPLACES = Decimal(10) ** -2
def multiply_price_cdata( m ):
price = Decimal( m.group(2) ) * Decimal( 1.25 )
return m.group(1) + str(price.quantize(TWOPLACES)) + m.group(3)
def cdata( m ):
return "CDATA"
# npp++ search/replace
re_price = r'(<price><!\[CDATA\[)(\d+\.\d+|\d+)(\]\]></price>)'
editor.rereplace( re_price , multiply_price_cdata )
# end the undo sequence
editor.endUndoAction()
Hi so I'm trying to use find and replace in notepad++ with regular expression to do the following:
I have two set of lines
first set:
[c][eu][e]I37ANKCB[/e]
[c][eu][e]OIL8ZEPW[/e]
[c][eu][e]4OOEL75O[/e]
[c][eu][e]PPNW5FN4[/e]
[c][eu][e]E2BXCWUO[/e]
[c][eu][e]SD9UQNT8[/e]
[c][eu][e]E6BK6IGO[/e]
second set:
[u]7ubju2jvioks[u2]_261
[u]89j408tah1lz[u2]_262
[u]j673xnd49tq0[u2]_263
[u]dv73osmh1wzu[u2]_264
[u]twz3u4yiaeqr[u2]_265
[u]cuhtg6r71kud[u2]_266
[u]yts0ktvt9a3r[u2]_267
now I want to the second set to by places after each of the first set like this:
[c][eu][e]I37ANKCB[/e][u]7ubju2jvioks[u2]_261
[c][eu][e]OIL8ZEPW[/e][u]89j408tah1lz[u2]_262
[c][eu][e]4OOEL75O[/e][u]j673xnd49tq0[u2]_263
[c][eu][e]PPNW5FN4[/e][u]dv73osmh1wzu[u2]_264
[c][eu][e]E2BXCWUO[/e][u]twz3u4yiaeqr[u2]_265
[c][eu][e]SD9UQNT8[/e][u]cuhtg6r71kud[u2]_266
[c][eu][e]E6BK6IGO[/e][u]yts0ktvt9a3r[u2]_267
any suggestions?
You can mark the second block in column mode using ALT and the left mouse button. Then just copy paste it at the end of the first row.
No need/Not possible using regex.
I would solve this via a simple script written in Python or Ruby or something equally quick. This works, for example:
import os
path = os.path.dirname(__file__)
with open(os.path.join(path, 'file1')) as file1:
with open(os.path.join(path, 'file2')) as file2:
lines = zip(file1.readlines(), file2.readlines())
print ''.join([a.rstrip() + b for a, b in lines])
Running it gives the correct result:
> python join.py
[c][eu][e]I37ANKCB[/e][u]7ubju2jvioks[u2]_261
[c][eu][e]OIL8ZEPW[/e][u]89j408tah1lz[u2]_262
[c][eu][e]4OOEL75O[/e][u]j673xnd49tq0[u2]_263
[c][eu][e]PPNW5FN4[/e][u]dv73osmh1wzu[u2]_264
[c][eu][e]E2BXCWUO[/e][u]twz3u4yiaeqr[u2]_265
[c][eu][e]SD9UQNT8[/e][u]cuhtg6r71kud[u2]_266
[c][eu][e]E6BK6IGO[/e][u]yts0ktvt9a3r[u2]_267
Customize to suit your needs.