I'm trying to modify a regex so it will allow an empty value or alphanumeric only.
I currently have this, but it only validates the alphanumeric
if (ruletype eq "alphanumeric") {
bMatch = true;
variables.fieldName = listGetAt(arguments.rules[nRow],2,",");
if (structKeyExists(arguments.form, "#variables.fieldName#")){
if (NOT RefindNoCase("[[:alnum:]]",arguments.form[variables.fieldName])) {
lstError = listAppend(lstError,nRow,",");
}
} else {
lstError = listAppend(lstError,nRow,",");
}
}
I tried converting to rematch to find the empty value, but that also accepts the value 1234^%^&& which contains special characters. I'm not sure how to fix that.
Do I understand correctly, from the value you mention, that arguments.form[variables.fieldName] is a comma-delimited list? If so, then what is to be matched is each list-item.(Incidentally, the # in sdkfk364563!##$% has to be delimited).
A possible answer is then:
if (structKeyExists(arguments.form, variables.fieldName)){
// Assuming arguments.form[variables.fieldName] is a comma-delimited list
fieldNameArray=listToArray(arguments.form[variables.fieldName], ',', true);
for (fieldValue in fieldNameArray) {
fieldValue=trim(fieldValue);
if (fieldValue eq "" or REfindNoCase("^[a-zA-Z0-9]*$",fieldValue) eq 0) {
lstError = listAppend(lstError,nRow);
}
}
}
[[:alnum:]] is POSIX syntax, which may not be supported. Use the universal ASCII syntax, [a-zA-Z0-9]. Also modify your code to account for the presence of an integer and to rule out any possible space character.
if (structKeyExists(arguments.form, variables.fieldName)){
if (REfindNoCase("^[a-zA-Z0-9]*$",trim(arguments.form[variables.fieldName])) eq 0) {
lstError = listAppend(lstError,nRow);
}
}
Related
I'm trying to evaluate a string against a set list of parameters with RegExp in Flutter. For example, the string must contain at least:
One capital letter
One lowercase letter
One number from 0-9
One special character, such as $ or !
This is basically for a password entry field of an application. I have set things up, firstly using validateStructure as follows:
abstract class PasswordValidator {
bool validateStructure(String value);
}
Then, I have used the RegExp function as follows:
class PasswordValidatorSpecial implements PasswordValidator {
bool validateStructure(String value) {
String pattern =
r'^(?=.*?[A-Z])(?=.*?[a-z])(?=.*?[0-9])(?=.*?[!##\$&*~£]).{8,}$';
RegExp regEx = new RegExp(pattern);
return regEx.hasMatch(value);
}
}
This does work well, in a sense that when I pass a string/password through it, it does tell me if at least one of the criteria is not met. However, what I would like to do is for the output to be more specific, telling me which of those criteria isn't met.
For example, if the password were to have everything but a number (from 0-9) I would want to be able to get the output to specifically say that a number is missing, but everything else is present.
How would I adapt my code to be able to do that? I thought perhaps by using conditional 'if' statement, although I don't know how that would work. Thanks!
That's right, you can use RegExr to check your RegExp, separate each part and use them separately to have a custom error. Also instead of return a bool value, you can return a String value, such as the following function:
String validateStructure(String value) {
String patternUpperCaseCharacters = r'^(?=.*?[A-Z])';
String patternLowerCaseCharacters = r'^(?=.*?[a-z])';
String patternNumbers = r'^(?=.*?[0-9])';
String patternSpecialCharacters = r'^(?=.*?[!##\$&*~£])';
RegExp regEx = new RegExp(patternUpperCaseCharacters);
if (regEx.hasMatch(value)) {
regEx = new RegExp(patternLowerCaseCharacters);
if (regEx.hasMatch(value)) {
return "More errors";
} else {
return "You need at least one lowercase letter";
}
} else {
return "You need at least one capital letter";
}
}
I have a couple of quick questions regarding using regex to validate some fields in a form. But I seem to be having some problems.
so here is the code
$userNameReg = "[a-zA-Z0-9_]+";
$passwordReg = "([a-zA-Z]*)([A-Z]+)([0-9]+)";
$emailReg = "[a-zA-Z0-9_]#[a-zA-Z]\.[a-zA-Z]{2,3}";
if ($onLoad !=1)
{
#controlValue = ($userName, $password, $phoneNumber, $email);
#regex = ($userNameReg, $passwordReg, "phoneNumber", $emailReg);
#validated;
for ($i=0; $i<4; $i++)
{
$retVal= validatecontrols ($controlValue[$i], $regex[$i]);
if ($retVal)
{
$count++;
}
if (!$retVal)
{
$validated[$i]="*"
}
}
sub validatecontrols
{
$ctrlVal = shift();
$regexVal = shift();
if ($ctrlVal =~ /$regexVal/)
{
return 1;
}
if ($ctrlVal !~ /$regexVal/)
{
return 0;
}
}
}
So what happens is that it still validates special characters, and I can't understand why. It does throw a flag if I enter a single special character but if its part of a word in the middle, beginning or end it validates.
Also please disregard the phone number part, because I haven't gotten to that part yet. I still have to create a regex that validates the phone number, digits only, first digit greater than 2.
Thank you all in advance for your help and insight.
Cheers
My guess is that you're missing start/end anchors. So [a-zA-Z0-9_]+ should be ^[a-zA-Z0-9_]+$. This way pattern will only match full string.
Also I strongly recommend you to enable use strict;. It can save you from a lot of mistype errors. Just add following to the beginning of the script:
use strict;
use warnings;
This will force perl to only allow defined variables. In most case you'll need to add my to first use of your variables (for example my $ctrlVal).
In validatecontrols you don't need second if statement. You can just return false like this:
sub validatecontrols
{
my $ctrlVal = shift();
my $regexVal = shift();
if ($ctrlVal =~ /$regexVal/)
{
return 1;
}
return 0;
}
How to check if string contains at least one character? I want to eliminate strings where are only special characters, so I've decided that the easiest way is to check if there is at least one character or digit, so I've created [a-zA-Z0-9]{1,} and [a-zA-Z0-9]+ but none of these work.
boost::regex noSpecialCharacters("[a-zA-Z0-9]+");
boost::regex noSpecialCharacters2("[a-zA-Z0-9]{1,}");
string tab[SIZE] = {"father", "apple is red"};
for (int i = 0; i < SIZE; i++) {
if (!boost::regex_match(tab[i], noSpecialCharacters)) {
puts("This is it!");
} else {
puts("or not");
}
if (!boost::regex_match(tab[i], noSpecialCharacters2)) {
puts("This is it!");
} else {
puts("or not");
}
}
for "apple is red" the answer is correct but for "father" it doesn't work.
apple is red won't match because, as per here (my bold):
Note that the result is true only if the expression matches the whole of the input sequence.
That means the spaces make it invalid. It then goes on to say (again, my bold):
If you want to search for an expression somewhere within the sequence then use regex_search.
If all you're looking for is one valid character somewhere in there, you can just use regex_match() with ".*[a-zA-Z0-9].*" or regex_search() with "[a-zA-Z0-9]".
I have a regex call that I need help with.
I haven't posted my regex, because it is not relevant here.
What I want to be able to do is, during the Replace, I also want to modify the ${test} portion by doing a Html.Encode on the entire text that is effecting the regex.
Basically, wrap the entire text that is within the range of the regex with the bold tag, but also Html.Encode the text inbetween the bold tag.
RegexOptions regexOptions = RegexOptions.Compiled | RegexOptions.IgnoreCase;
text = Regex.Replace(text, regexBold, #"<b>${text}</b>", regexOptions);
There is an incredibly easy way of doing this (in .net). Its called a MatchEvaluator and it lets you do all sorts of cool find and replace. Essentially you just feed the Regex.Replace method the method name of a method that returns a string and takes in a Match object as its only parameter. Do whatever makes sense for your particular match (html encode) and the string you return will replace the entire text of the match in the input string.
Example: Lets say you wanted to find all the places where there are two numbers being added (in text) and you want to replace the expression with the actual number. You can't do that with a strict regex approach, but you can when you throw in a MatchEvaluator it becomes easy.
public void Stuff()
{
string pattern = #"(?<firstNumber>\d+)\s*(?<operator>[*+-/])\s*(?<secondNumber>\d+)";
string input = "something something 123 + 456 blah blah 100 - 55";
string output = Regex.Replace(input, pattern, MatchMath);
//output will be "something something 579 blah blah 45"
}
private static string MatchMath(Match match)
{
try
{
double first = double.Parse(match.Groups["firstNumber"].Value);
double second = double.Parse(match.Groups["secondNumber"].Value);
switch (match.Groups["operator"].Value)
{
case "*":
return (first * second).ToString();
case "+":
return (first + second).ToString();
case "-":
return (first - second).ToString();
case "/":
return (first / second).ToString();
}
}
catch { }
return "NaN";
}
Find out more at http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.matchevaluator.aspx
Don't use Regex.Replace in this case... use..
foreach(Match in Regex.Matches(...))
{
//do your stuff here
}
Heres an implementation of this I've used to pick out special replace strings from content and localize them.
protected string FindAndTranslateIn(string content)
{
return Regex.Replace(content, #"\{\^(.+?);(.+?)?}", new MatchEvaluator(TranslateHandler), RegexOptions.IgnoreCase);
}
public string TranslateHandler(Match m)
{
if (m.Success)
{
string key = m.Groups[1].Value;
key = FindAndTranslateIn(key);
string def = string.Empty;
if (m.Groups.Count > 2)
{
def = m.Groups[2].Value;
if(def.Length > 1)
{
def = FindAndTranslateIn(def);
}
}
if (group == null)
{
return Translate(key, def);
}
else
{
return Translate(key, group, def);
}
}
return string.Empty;
}
From the match evaluator delegate you return everything you want replaced, so where I have returns you would have bold tags and an encode call, mine also supports recursion, so a little over complicated for your needs, but you can just pare down the example for your needs.
This is equivalent to doing an iteration over the collection of matches and doing parts of the replace methods job. It just saves you some code, and you get to use a fancy shmancy delegate.
If you do a Regex.Match, the resulting match objects group at the 0th index, is the subset of the intput that matched the regex.
you can use this to stitch in the bold tags and encode it there.
Can you fill in the code inside {} to add the bold tag, and encode the text?
I'm confused as to how to apply the changes to the entire text block AND replace the section in the text variable at the end.
What's the easiest way to do an "instring" type function with a regex? For example, how could I reject a whole string because of the presence of a single character such as :? For example:
this - okay
there:is - not okay because of :
More practically, how can I match the following string:
//foo/bar/baz[1]/ns:foo2/#attr/text()
For any node test on the xpath that doesn't include a namespace?
(/)?(/)([^:/]+)
Will match the node tests but includes the namespace prefix which makes it faulty.
I'm still not sure whether you just wanted to detect if the Xpath contains a namespace, or whether you want to remove the references to the namespace. So here's some sample code (in C#) that does both.
class Program
{
static void Main(string[] args)
{
string withNamespace = #"//foo/ns2:bar/baz[1]/ns:foo2/#attr/text()";
string withoutNamespace = #"//foo/bar/baz[1]/foo2/#attr/text()";
ShowStuff(withNamespace);
ShowStuff(withoutNamespace);
}
static void ShowStuff(string input)
{
Console.WriteLine("'{0}' does {1}contain namespaces", input, ContainsNamespace(input) ? "" : "not ");
Console.WriteLine("'{0}' without namespaces is '{1}'", input, StripNamespaces(input));
}
static bool ContainsNamespace(string input)
{
// a namspace must start with a character, but can have characters and numbers
// from that point on.
return Regex.IsMatch(input, #"/?\w[\w\d]+:\w[\w\d]+/?");
}
static string StripNamespaces(string input)
{
return Regex.Replace(input, #"(/?)\w[\w\d]+:(\w[\w\d]+)(/?)", "$1$2$3");
}
}
Hope that helps! Good luck.
Match on :? I think the question isn't clear enough, because the answer is so obvious:
if(Regex.Match(":", input)) // reject
You might want \w which is a "word" character. From javadocs, it is defined as [a-zA-Z_0-9], so if you don't want underscores either, that may not work....
I dont know regex syntax very well but could you not do:
[any alpha numeric]\*:[any alphanumeric]\*
I think something like that should work no?
Yeah, my question was not very clear. Here's a solution but rather than a single pass with a regex, I use a split and perform iteration. It works as well but isn't as elegant:
string xpath = "//foo/bar/baz[1]/ns:foo2/#attr/text()";
string[] nodetests = xpath.Split( new char[] { '/' } );
for (int i = 0; i < nodetests.Length; i++)
{
if (nodetests[i].Length > 0 && Regex.IsMatch( nodetests[i], #"^(\w|\[|\])+$" ))
{
// does not have a ":", we can manipulate it.
}
}
xpath = String.Join( "/", nodetests );