I want search request on the List<Food> that I got. I have used a query method like this:
_foodList.where((food) => food.name == userInputValue).toList();
however, the search asked me to search with complete text and the right capitalization of the text.
how if I want to process a compilation of "dish", then all the names of foods that have the word "dish" will display in List?
Lower-case or upper-case all strings before comparison and use contains() instead of ==:
_foodList.where((food) => food.name.toLowerCase().contains(userInputValue.toLowerCase()).toList();
If values can be null you need to add additional checks.
Related
I am struggling on creating a formula with Power Bi that would split a single rows value into a list of values that i want.
So I have a column that is called ID and it has values such as:
"ID001122, ID223344" or "IRRELEVANT TEXT ID112233, MORE IRRELEVANT;ID223344 TEXT"
What is important is to save the ID and 6 numbers after it. The first example would turn into a list like this: {"ID001122","ID223344"}. The second example would look exactly the same but it would just parse all the irrelevant text from between.
I was looking for some type of an loop formula where you could use the text find function to find ID starting point and use middle function to extract 8 characters from the start but I had no progress in finding such. I tried making lists from comma separator but I noticed that not all rows had commas to separate IDs.
The end results would be that the original value is on one column next to the list of parsed values which then could be expanded to new rows.
ID Parsed ID
"Random ID123456, Text;ID23456" List {"ID123456","ID23456"}
Any of you have former experience?
Hey I found the answer by myself using a good article similar to my problem.
Here is my solution without any further text parsing which i can do later on.
each let
PosList = Text.PositionOf([ID],"ID",Occurrence.All),
List = List.Transform(PosList, (x) => Text.Middle([ID],x,8))
in List
For example this would result "(ID343137,ID352973) ID358388" into {ID343137,ID352973,ID358388}
Ended up being easier than I thought. Suppose the solution relied again on the lists!
I have an angular app using the mongodb sdk for js.
I would like to suggest some words on a input field for the user from my words collection, so I did:
getSuggestions(term: string) {
var regex = new stitch.BSON.BSONRegExp('^' +term , 'i');
return from(this.words.find({ 'Noun': { $regex: regex } }).execute());
}
The problem is that if the user type for example Bie, the query returns a lot of documents but the most accurated are the last ones, for example Bier, first it returns the bigger words, like Bieberbach'sche Vermutung. How can I deal to return the closests documents first?
A regular-expression is probably not enough to do what you are intending to do here. They can only do what they're meant to do – match a string. They might be used to give you a candidate entry to present to the user, but can't judge or weigh them. You're going to have to devise that logic yourself.
I have got a list of different names. I have a script that prints out the names from the list.
req=urllib2.Request('http://some.api.com/')
req.add_header('AUTHORIZATION', 'Token token=hash')
response = urllib2.urlopen(req).read()
json_content = json.loads(response)
for name in json_content:
print name['name']
Output:
Thomas001
Thomas002
Alice001
Ben001
Thomas120
I need to find the max number that comes with the name Thomas. Is there a simple way to to apply regexp for all the elements that contain "Thomas" and then apply max(list) to them? The only way that I have came up with is to go through each element in the list, match regexp for Thomas, then strip the letters and put the remaining numbers to a new list, but this seems pretty bulky.
You don't need regular expressions, and you don't need sorting. As you said, max() is fine. To be safe in case the list contains names like "Thomasson123", you can use:
names = ((x['name'][:6], x['name'][6:]) for x in json_content)
max(int(b) for a, b in names if a == 'Thomas' and b.isdigit())
The first assignment creates a generator expression, so there will be only one pass over the sequence to find the maximum.
You don't need to go for regex. Just store the results in a list and then apply sorted function on that.
>>> l = ['Thomas001',
'homas002',
'Alice001',
'Ben001',
'Thomas120']
>>> [i for i in sorted(l) if i.startswith('Thomas')][-1]
'Thomas120'
I just started using Neo4j server 2.0.1. I am having trouble with the writing a cypher script to change one of the nodes property to something based one of its already defined properties.
So if I created these node's:
CREATE (:Post {uname:'user1', content:'Bought a new pair of pants today', kw:''}),
(:Post {uname:'user2', content:'Catching up on Futurama', kw:''}),
(:Post {uname:'user3', content:'The last episode of Game of Thrones was awesome', kw:''})
I want the script to look at the content property and pick out the word "Bought" and set the kw property to that using a regular expression to pick out word(s) larger then five characters. So, user2's post kw would be "Catching, Futurama" and user3's post kw would be "episode, Thrones, awesome".
Any help would be greatly appreciated.
You could do something like this:
MATCH (p:Post { uname:'user1' })
WHERE p.content =~ "Bought .+"
SET p.kw=filter(w in split(p.content," ") WHERE length(w) > 5)
if you want to do that for all posts, which might not be the fastest operation:
MATCH (p:Post)
WHERE p.content =~ "Bought .+"
SET p.kw=filter(w in split(p.content," ") WHERE length(w) > 5)
split splits a string into a collection of parts, in this case words separated by space
filter filters a collection by a condition behind WHERE, only the elements that fulfill the condition are kept
Probably you'd rather want to create nodes for those keywords and link the post to the keyword nodes.
I'm trying to match values of a list to a regex pattern. If the particular value within the list matches, I'll append it to a different list of dicts. If the above mentioned value does not match, I want to remove the value from the list.
import subprocess
def list_installed():
rawlist = subprocess.check_output(['yum', 'list', 'installed']).splitlines()
#print rawlist
for each_item in rawlist:
if "[\w86]" or \
"noarch" in each_item:
print each_item #additional stuff here to append list of dicts
#i haven't done the appending part yet
#the list of dict's will be returned at end of this funct
else:
remove(each_item)
list_installed()
The end goal is to eventually be able to do something similar to:
nifty_module.tellme(installed_packages[3]['version'])
nifty_module.dosomething(installed_packages[6])
Note to gnu/linux users going wtf:
This will eventually grow into a larger sysadmin frontend.
Despite the lack of an actual question in your post, I'll make a couple of comments.
You have a problem here:
if "[\w86]" or "noarch" in each_item:
It's not interpreted the way you think of it and it always evaluates to True. You probably need
if "[\w86]" in each_item or "noarch" in each_item:
Also, I'm not sure what you are doing, but in case you expect that Python will do regex matching here: it won't. If you need that, look at re module.
remove(each_item)
I don't know how it's implemented, but it probably won't work if you expect it to remove the element from rawlist: remove won't be able to actually access the list defined inside list_installed. I'd advise to use rawlist.remove(each_item) instead, but not in this case, because you are iterating over rawlist. You need to re-think the procedure a little (create another list and append needed elements to it instead of removing, for example).