I've got this string:
{"success":true,"lowest_price":"1,49€","volume":"1,132","median_price":"1,49€"}
Now I want the value for median_price being displayed in a cell. HHow can I achive this with Regex?
With regex101.com I've came to this solution:
(?<=median_price":")\d{0,4},\d{2}€
But this one does not seem to be working in LibreOffice calc.
I'd advise to discard the Euro-symbol at first since you'd probably want to retrieve a value to calculate with, a numeric value. Therefor try:
Formula in B1:
=--REGEX(A1;".*median_price"":""(\d+(?:,\d+)?)€.*";"$1")
The double unary will transform the result from the 1st capture group into a number. I then went ahead and formatted the cell to display currency (Ctrl+Shift+4).
Note: I went with a slightly different regular pattern. But go with whatever works for your data I supppose.
I am working with a messy manually maintained "database" that has a column containing a string with name,value pairs. I am trying to parse the entire column with regexp to pull out the values. The column is huge (>100,000 entries). As a proxy for my actual data, let's use this code:
line1={'''thing1'': ''-583'', ''thing2'': ''245'', ''thing3'': ''246'', ''morestuff'':, '''''};
line2={'''thing1'': ''617'', ''thing2'': ''239'', ''morestuff'':, '''''};
line3={'''thing1'': ''unexpected_string(with)parens5'', ''thing2'': 245, ''thing3'':''246'', ''morestuff'':, '''''};
mycell=vertcat(line1,line2,line3);
This captures the general issues encountered in the database. I want to extract what thing1, thing2, and thing3 are in each line using cellfun to output a scalar cell array. They should normally be 3 digit numbers, but sometimes they have an unexpected form. Sometimes thing3 is completely missing, without the name even showing up in the line. Sometimes there are minor formatting inconsistencies, like single quotes missing around the value, spaces missing, or dashes showing up in front of the three digit value. I have managed to handle all of these, except for the case where thing3 is completely missing.
My general approach has been to use expressions like this:
expr1='(?<=thing1''):\s?''?-?([\w\d().]*?)''?,';
expr2='(?<=thing2''):\s?''?-?([\w\d().]*?)''?,';
expr3='(?<=thing3''):\s?''?-?([\w\d().]*?)''?,';
This looks behind for thingX' and then tries to match : followed by zero or one spaces, followed by 0 or 1 single quote, followed by zero or one dash, followed by any combination of letters, numbers, parentheses, or periods (this is defined as the token), using a lazy match, until zero or one single quote is encountered, followed by a comma. I call regexp as regexp(___,'tokens','once') to return the matching token.
The problem is that when there is no match, regexp returns an empty array. This prevents me from using, say,
out=cellfun(#(x) regexp(x,expr3,'tokens','once'),mycell);
unless I call it with 'UniformOutput',false. The problem with that is twofold. First, I need to then manually find the rows where there was no match. For example, I can do this:
emptyout=cellfun(#(x) isempty(x),out);
emptyID=find(emptyout);
backfill=cell(length(emptyID),1);
[backfill{:}]=deal('Unknown');
out(emptyID)=backfill;
In this example, emptyID has a length of 1 so this code is overkill. But I believe this is the correct way to generalize for when it is longer. This code will change every empty cell array in out with the string Unknown. But this leads to the second problem. I've now got a 'messy' cell array of non-scalar values. I cannot, for example, check unique(out) as a result.
Pardon the long-windedness but I wanted to give a clear example of the problem. Now my actual question is in a few parts:
Is there a way to accomplish what I'm trying to do without using 'UniformOutput',false? For example, is there a way to have regexp pass a custom string if there is no match (e.g. pass 'Unknown' if there is no match)? I can think of one 'cheat', which would be to use the | operator in the expression, and if the first token is not matched, look for something that is ALWAYS found. I would then still need to double back through the output and change every instance of that result to 'Unknown'.
If I take the 'UniformOutput',false approach, how can I recover a scalar cell array at the end to easily manipulate it (e.g. pass it through unique)? I will admit I'm not 100% clear on scalar vs nonscalar cell arrays.
If there is some overall different approach that I'm not thinking of, I'm also open to it.
Tangential to the main question, I also tried using a single expression to run regexp using 3 tokens to pull out the values of thing1, thing2, and thing3 in one pass. This seems to require 'UniformOutput',false even when there are no empty results from regexp. I'm not sure how to get a scalar cell array using this approach (e.g. an Nx1 cell array where each cell is a 3x1 cell).
At the end of the day, I want to build a table using these results:
mytable=table(out1,out2,out3);
Edit: Using celldisp sheds some light on the problem:
celldisp(out)
out{1}{1} =
246
out{2} =
Unknown
out{3}{1} =
246
I assume that I need to change the structure of out so that the contents of out{1}{1} and out{3}{1} are instead just out{1} and out{3}. But I'm not sure how to accomplish this if I need 'UniformOutput',false.
Note: I've not used MATLAB and this doesn't answer the "efficient" aspect, but...
How about forcing there to always be a match?
Just thinking about you really wanting a match to skip this problem, how about an empty match?
Looking on the MATLAB help page here I can see a 'emptymatch' option, perhaps this is something to try.
E.g.
the_thing_i_want_to_find|
Match "the_thing_i_want_to_find" or an empty match, note the | character.
In capture group it might look like this:
(the_thing_i_want_to_find|)
As a workaround, I have found that using regexprep can be used to find entries where thing3 is missing. For example:
replace='$1 ''thing3'': ''Unknown'', ''morestuff''';
missingexpr='(?<=thing2'':\s?)(''?-?[\w\d().]*?''?,) ''morestuff''';
regexprep(mycell{2},missingexpr,replace)
ans =
''thing1': '617', 'thing2': '239', 'thing3': 'Unknown', 'morestuff':, '''
Applying it to the entire array:
fixedcell=cellfun(#(x) regexprep(x,missingexpr,replace),mycell);
out=cellfun(#(x) regexp(x,expr3,'tokens','once'),fixedcell,'UniformOutput',false);
This feels a little roundabout, but it works.
cellfun can be replaced with a plain old for loop. Your code will either be equally fast, or maybe even faster. cellfun is implemented with a loop anyway, there is no advantage of using it other than fewer lines of code. In your explicit loop, you can then check the output of regexp, and build your output array any way you like.
I have a decently sized spreadsheet of about 6 thousand entries and I am trying to match two columns to make sure they match up using vlookup and that is working fine but I have about 400 or so entries that don't have a match and looking through a few and just using control-f to see if they were somewhere with a different naming convention I found the a matching cell for several of the entries that supposedly don't have a match, any clue why this might be? I checked the length of the values in the cell to see if there was white spacing I was missing but they matched in length and the values in the cell are the exact same. This is the vlookup setup I am using
=VLOOKUP(A1,$B$1:$B$6074,1,0). The CSV is here if anyone wanted to see it. I am not saying they are all wrong but I looked at about 10 or so and they all had matches so I am a bit lost on this.
I'm trying to write a REGEXMATCH formula for Sheets that will analyze all of the text in a cell and then write a given keyword into another cell.
I've figured out how to do this for a single keyword: for example,
=IF(REGEXMATCH(F3, "czech"),"CZ",IF(REGEXMATCH(F3, "african"),"AF",IF(REGEXMATCH(F3, "mykonos"),"MK")))
What I'm having trouble with though is writing one of these values only if two or more terms are matched in the reference cell.
If I were trying to match one of two words, I realize I could use | as in:
=IF(REGEXMATCH(F3, "czech|coin"),"CZC"
etc
But in this instance I only want to produce CZC if the previous cell contains BOTH czech AND coin.
Can someone help me with this?
try like this:
=IF((REGEXMATCH(F3, "czech"))*(REGEXMATCH(F3, "coin")), "CZC", )
multiplication stands for AND
I want to check if specific cell contain only numbers.
I know I should use RegExMatch but I get an error.
This is what I wrote : =if(RegExMatch(H2,[0-9]),"a","b")
I want it to say : write 'a' if H2 contains only numbers, 'b' otherwise.
Thank you
Try this:
=IF(ISNUMBER(H2,"A","B"))
or
=if(isna(REGEXEXTRACT(text(H2,"#"),"\d+")),"b","a")
One reason your match isn't working also - is that it in interpreting your numbers as text. the is number function is a bit more consistent, but if you really need to use regex, then you can see in the second formula where im making sure the that source text is matching against a string.
Your formula is right, simple you forget the double quotes at regexmatch function's regular_expression .
This is the right formula: =if(RegExMatch(B20,"[0-9]"),"a","b")
=REGEXREPLACE(“text”,”regex”,”replacement”)
It spits out the entire content but with the regular expression matched content replaced. =REGEXREPLACE(A2,[0-9],"a")
=REGEXREPLACE(A2,![0-9],"b")//not sure about not sign.
will fill a cell with the same text as A2, but with the 0-9 becoming an a!