Hi I am trying to get the playlist ID of a youtube url. The code below is not solid since the id 'PLcfQmtiAG0X-fmM85dPlql5wfYbmFumzQ' will not be extracted properly. It only returns 'PLcfQmtiAG0X'. Can someone help me?
var reg = new RegExp("[&?]list=([a-z0-9_]+)","i");
var url = 'https://www.youtube.com/playlist?list=PLcfQmtiAG0X-fmM85dPlql5wfYbmFumzQ';
var match = reg.exec(url);
return match[1];
I do a fair amount of regex work with URLs. Usually you'll want to use a parser but sometimes that is not an option. So to gather params I like to use a negative character class like this
/[&?]list=([^&]+)/i
The [&?] will mean that you won't match &split=123 since it has to start with a & or ?
The [^&]+ is the real magic, it means capture all the non & which is the value you are going for. If you want to play around, this site is pretty good:
https://regex101.com/
Related
I want to filter a string from the URLs in Google Analytics. This can be done using the Views > Filter > Exclude using RegEx, but I have been unable to get it to work.
An outline of how these filters are set up, can be found here, however, I can not work out how to isolate the string using RegEx. I believe it will need to be one filter per URL type.
The URLs follow this format:
/software/11F372288FA/pagename
/software/13F412C5FA/pagename/summary
/software/XIL1P0BFXCKM81/pagename2
I need to exclude this part of the URL:
/11F372288FA/
So that the URL data (e.g. Session time) is recorded against:
/software/pagename
/software/pagename/summary
/software/pagename2
I have worked out that I can isolate the string using thing following RegEx
^\/validate\/(..........)\/accounts\/summary$
It is not very elegant and would require a filter for every URL type.
Thanks for the help!
I'm not certain if this will work in your exact case but instead of using regex for this it might be easier to just create a new string from the start to the end of "software" and append everything from pagename to the end. In Java this might look something like:
String newString = oldString.substring(0, 9) + oldString.substring(oldString.indexOf("pagename"));
Take note though that this will only work if the "software" at the start is always the same length and you are actually only excluding things between "software" and "pagename".
I have already implemented angular multi-select Dropdown. Now I want it to search using RegEx. Like if I have qwertyuiop, and if I wrote w*i than it should suggest me all the entries who contains 'W' and 'I' in the same string.
Do you want to know the whole thing, like how to bind the input of an input field, read the input, create an RegEx out of it, and then use the RegEx as a filter to the list you are showing in your dropdown ?
Or only the RegEx part?
For the part with RegEx:
You should take a look at the Javascript Defintion of RegEx (for example at Mozilla Developer Network ). It has a quite nice functionality.
let input:string = // the value the user typed, like w*i
const regEx = new RegExp(input)
let myDropdownList:string[] = // the list of strings i want to filter
let filteredDropdownList = myDropdownList.forEach((value:string)=>{
return regEx.test(value)
})
What happens here?
You are creating a regular Expressen with new RegExp(someString).
You can optimize it with RegEx flags.
Later you test a string with myRegEx.test(theString). It will return true if the regEx founds at least one match in the string.
I hope this helps you a bit.
warm regards.
I'm trying to create a custom filter in Google Analytic to remove the query parts of the url which I don't want to see. The url has the following structure
[domain]/?p=899:2000:15018702722302::NO:::
I would like to create a regex which skips the first 12 characters (that is until:/?p=899:2000), and what ever is going to be after that replace it with nothing.
So I made this one: https://regex101.com/r/Xgbfqz/1 (which could be simplified to .{0,12}) , but I actually would like to skip those and only let the regex match whatever is going to be after that, so that I'll be able to tell in Google Analytics to replace it with "".
The part in the url that is always the same is
?p=[3numbers]:[0-4numbers]
Thank you
Your regular expression:
\/\?p=\d{3}\:\d{0,4}(.*)
Tested in Golang RegEx 2 and RegEx101
It search for /p=###:[optional:####] and capture the rest of the right side string.
(extra) JavaScript:
paragraf='[domain]/?p=899:2000:15018702722302::NO:::'
var regex= /\/\?p=\d{3}\:\d{0,4}(.*)/;
var match = regex.exec(paragraf);
alert('The rest of the right side of the string: ' + match[1]);
Easily use "[domain]/?p=899:2000:15018702722302::NO:::".substr(12)
You can try this:
/\?p\=\d{3}:\d{0,4}
Which matches just this: ?p=[3numbers]:[0-4numbers]
Not sure about replacing though.
https://regex101.com/r/Xgbfqz/1
On our website we occasionally experience an error where dynamic links aren't building correctly.
URLs like this
https://www.test.url.edu/collections/&edan_fq[]=p.edanmdm.indexedstructured.object_type:%22Financial+records%22&edan_fq[]=p.edanmdm.descriptivenonrepeating.record_id:item_*
Should actually be this:
https://www.test.url.edu/collections/search?edan_fq[]=p.edanmdm.indexedstructured.object_type:%22Financial+records%22&edan_fq[]=p.edanmdm.descriptivenonrepeating.record_id:item_*
We want to create a regular expression to redirect
/collections/&edan_fq[]=
to
/collections/search?edan_fq[]=
But everything after "edan_fq[]=" can change dynamically--there are thousands of permutations of the string after that point.
Does anyone know how this would be done?
If you use \& without Global Flag in Regex it will give first match. I've used JavaScript, please check this.
var data = "https://www.test.url.edu/collections/&edan_fq[]=p.edanmdm.indexedstructured.object_type:%22Financial+records%22&edan_fq[]=p.edanmdm.descriptivenonrepeating.record_id:item_*";
var regex = /\&/
data = data.replace(regex,"search?");
console.log(data);
Please check Substitution example in Regex101.
In my JSP I have receive some data which is coming from database my data is for example something like this :
Google is the greatest search engine ever http://www.google.com
what I wanna do is so simple: I want to make this link wrap in anchor tag using JSTL something like:
Google is the greatest search engine ever http://www.google.com
that's all !
take note that the urls are not constant, I mean I'm not sure what that be exactly & I just mentioned google here for the example.
Follow this SO question to create a replaceAll function for JSTL and then use the following pattern to replace the url to html link:
String pattern = "(http:[A-z0-9./~%]+)";
String str = "Google is the http://www.test.com greatest search engine ever http://www.google.com";
String replaced = str.replaceAll(pattern, "<a href='$1'>$1</a>");