Using the text replaced in the replace text - regex

Question

I'm using the version 7.3.3 of Notepad++.
I have this list of numbers to 1.000.000.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
I want to add XML tags to these numbers like this:
<SerialNumber>
<SN>1</SN>
</SerialNumber>
<SerialNumber>
<SN>2</SN>
</SerialNumber>
<SerialNumber>
<SN>3</SN>
</SerialNumber>
<SerialNumber>
<SN>4</SN>
</SerialNumber>
So I need a regular expression to find a number ended with a \n\r, and use the number I've found with the regular expression in the text that I'm going to add.
Do you know to do that in Notepad++?
I have tried with \d{*} but it is not a valid regular expression.

Answer 1

Open the "Replace" menu (Search > Replace...).
And set like that :
- Find what: (\d+)[(\r)?\n]
- Replace with : <SerialNumber>\r\n <SN>$1</SN>\r\n</SerialNumber>
- Check : Search mode -> Regular expression
Then press Replace All. To even match the last number, add an empty line at the end of your file.
I hope it helps.

Answer 2

if we take your [1.... n] numbers in string called strData then :
var nums = strData.split("\r\n").map(function(item) {
return parseInt(item, 10);
});
var strXmlOut = nums.map(function(n) {
return "<SerialNumber><SN>" + n + "</SN></SerialNumber>";
}).join("\r\n");
and the one call version would be :
var xmlOut = strData.split("\r\n")
.map(function(item) {return parseInt(item, 10);})
.map(function(n) {return "<SerialNumber><SN>" + n + "</SN></SerialNumber>";})
.join("\r\n");