Jmeter Regular Expression To Extract A Number Having Varying Boundaries - regex

I need to extract one number from a Jmeter response using regular expression extractor as part of correlation.
Scenario is:
<span>Abc456ABC</span>
If I use <span>(.*?)</span>, then I will get "Abc456ABC".
If I use <span>Abc(.*?)ABC</span>, then I will get "456".
But the left and right boundary can vary.The input can be like:
Abcdef789ABCgh
I need only the number[In last case it is "789"]. Please suggest the suitable regular expression extractor.
Thanks In Advance..


<span>.*?([0-9]+).*?</span>
You can simply use this.See demo.
https://regex101.com/r/uE6jQ1/11


You can use the following:
<span>\D+(\d+)\D+</span>
See RegEX DEMO


you can use <span>([\w]+)(\d+)([\w+])</span>, It'll surely work
But use $2$ as template in regular expression extractor
([\w]+):it will capture all words and
(\d+): will take care of digits for you

Related

Regular Exprssion in JMeter

I have the following in my response body:
aBB1="N|1234A1234|blahblahblah"
I want to take only 1234A1234 using Regular Expression Extractor in jmeter.
Would you kindly provide me a suitable regex, please? Thanks in advance.

You can use aBB1="N\|([0-9A-Z]*)\|blahblahblah"
It extracts combination of digits from 0-9 and alpabets from A-Z
You can use regex101.com to test your regular expressions
More info :
JMeter Extraction using regular expressions

You can use ...
aBB1="N|(.+?)|blahblahblah"
This will extract 1234A1234
You can skip blahblahblah as well, but you need to make sure this aBB1="N|.....| pattern should never change, this will extract value between pipes(||) which is 1234A1234 in this case
aBB1="N|(.+?)|
See Jmeter Reference Here

Regex: Extract string between two strings

This is the issue I face
The String
nt/sign-in?wa=wsignin1.0&wtre
The Need
From that string I need to extract the following
wsignin1.0
The Attempts
So far I have tried the following Regex
wa=(.*?)(?=&amp)
This returns:
wa=wsignin1.0
The "wa=" is not supposed to be there

Perhaps with a look behind?
(?<=wa\=)(.+)(?=\&wtre)
wsignin1.0

JMeter uses Perl5-style regular expressions therefore the regex you are looking for might be as simple as:
wa=(.+?)&wtre
Demo:
Use $1$ as "Template" in your Regular Expresssion Extractor.
See How to Debug your Apache JMeter Script for more details on JMeter tests troubleshooting.

=([\w.]++)
will capture it in the first capture group. Otherwise I think #jivan has a good idea with the lookbehind. A little tweak too it:
(?<==)[\w.]++

Put this in your Regular Expression extractor:
nt/sign-in?wa=([a-zA-Z0-9\.]*)&wtre
I hope this help you.

Can someone tell me the regular expression for this?

I am working with regular expressions, I need to create an expression for validating strings against the following scenario:
Solution.<word1|word2|word3>.<word4|word5>.anyword.(any word containing proj in it)
I tried
Solution.\b(word1|word2|word3)\b.\b(word4|word5)\b.(.*).\b(.*proj)\b
But this allows strings like Solution.word1.word4.blabla.blabla.csproj, meaning it allows anything before the proj because of the .*.
Can someone help me with this??

Looks like you need this regex:
Solution\.(word1|word2|word3)\.(word4|word5)\.([^.]+)\..*?\bproj\b
RegEx Demo

You might want to try (need to escape the . and allow capturing group to have chars except .):
Solution\.\b(word1|word2|word3)\b\.\b(word4|word5)\b\.([^\.]*)\.\b([^\.]*proj)\b

It's hard to consider the actual strings you want to allow without more clarification.
You can try the following regular expression.
Solution\.word[123]\.word[45]\.\w+\.\w*proj\b

Regular Expression for recognizing files with following patterns az.4.0.0.119.tgz

I am trying to find a regular expression that will recognize files with the pattern as az.4.0.0.119.tgz. I have tried the regular expression below:
([a-z]+)[.][0-9]{0,3}[.][0-9]{0,3}[.][0-9]{0,3}[.]tgz
But, no luck. Can anyone please point me in the right direction.
Regards,
Shreyas

Better to use a simple regex like this:
^([a-z]+)\.(?:[0-9]+\.)+tgz$

You just forgot one number part:
([a-z]+)[.][0-9]{0,3}[.][0-9]{0,3}[.][0-9]{0,3}[.][0-9]{0,3}[.]tgz
or
([a-z]+)[.]([0-9]{0,3}[.]){4}tgz
Depending on where and how you use the regex, you might want to surround it in ^...$.

Your pattern has 4 chiffers group, your regexp only 3.

Regular Expressions with conditions

I have a string that looks like:
this is a string [[and]] it is [[awesome|amazing]]
I have the following regular expression so far:
(?<mygroup>(?<=\[\[).+?(?=\]\]))
I am basically trying to capture everything inside the brackets. However, I need to add another condition that says: If the matched result contains a pipe delimiter then only return the word to the right of the pipe delimiter. If there is no pipe then just return everything inside the brackets.
The parsing result I am looking for given the example above should look like:
and
amazing
Any input is appreciated.

(?<mygroup>(?<=\[\[)([^|\]]*|)?([^|]+?)(?=\]\]))

You could use this regex:
(?<=\[\[[^\]]*?)(?!\w+\|)\w+(?=\]\])
it matches both and and amazing words in your test example. You could check it out, I created a test app on Ideone.

From the regex info page:
The tremendous power and expressivity
of modern regular expressions can
seduce the gullible — or the foolhardy
— into trying to use regexes on every
string‐related task they come across.
My advice: Just grab what is between the brackets and parse it after.
Regular expressions are not the answer to everything. May those who follow after you be spared from deciphering the regex you come up with.