I was wondering if it was possible to convert a current date format to an ISO_8601 format using XSLT.
In the XML the date currently is set to:
<end_date>
<![CDATA[ 2015-10-14 23:59:59 ]]>
In your example,
<xsl:value-of select="translate(normalize-space(end_date), ' ', 'T')"/>
will return:
2015-10-14T23:59:59
This is a valid ISO 8601 representation of date and local time.
If you are sure that the given value is in UTC (although I don't see any such indication in your input) , and you want to indicate this in the result, you could do:
<xsl:value-of select="concat(translate(normalize-space(end_date), ' ', 'T'), 'Z')"/>
to return:
2015-10-14T23:59:59Z
Here is a XSLT that does the work :
<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:i="http://schemas.datacontract.org/2004/07/Uanet>"
>
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="end_date">
<!--copy current node-->
<xsl:copy>
<xsl:apply-templates select="text()" />
</xsl:copy>
</xsl:template>
<!--
input : 2015-10-14 23:59:59
output : 2015-10-14T23:59:59Z
-->
<xsl:template match="text()">
<xsl:variable name="trimmed" select="." />
<xsl:value-of select="substring($trimmed,0,12)" />
<xsl:text>T</xsl:text>
<xsl:value-of select="substring($trimmed,13,8)" />
<xsl:text>Z</xsl:text>
</xsl:template>
</xsl:stylesheet>
Related
Is it possible to sort nodes as follows:
Example XML
<record>
<id>0</id>
<sku>0</sku>
<name>Title</name>
<prop>456</prop>
<number>99</number>
</record>
If I apply this template
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="record/*">
<xsl:param select="." name="value"/>
<div>
<xsl:value-of select="concat(local-name(), ' - ', $value)"/>
</div>
</xsl:template>
</xsl:stylesheet>
Ouput:
<div>id - 0</div>
<div>sku - 0</div>
<div>name - Title</div>
<div>prop - 456</div>
<div>number - 99</div>
However, I would like all 0 values to be outputted last, as so:
<div>name - Title</div>
<div>prop - 456</div>
<div>number - 99</div>
<div>id - 0</div>
<div>sku - 0</div>
Is this possible by applying a sort to the <xsl:apply-templates/>?
There is an easy way of achieving this with XSLT-1.0. Just use a predicate on xsl:apply-templates checking if the content is zero:
<xsl:template match="record/*">
<div>
<xsl:value-of select="concat(local-name(), ' - ', .)"/>
</div>
</xsl:template>
<xsl:template match="/record">
<xsl:apply-templates select="*[normalize-space(.) != '0']" />
<xsl:apply-templates select="*[normalize-space(.) = '0']" />
</xsl:template>
This does not sort the output, but groups it the way you want it. The xsl:param is unnecessary.
As far as I see your question, the issue is not any sort at all.
You even didn't write what is the specific value, which you mentioned
it the title. It is rather an arbitrary sequence of child elements of record.
Try the following script, performing just that:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="record">
<xsl:copy>
<xsl:apply-templates select="name, prop, number, id, sku"/>
</xsl:copy>
</xsl:template>
<xsl:template match="record/*">
<div><xsl:value-of select="concat(local-name(), ' - ', .)"/></div>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy><xsl:apply-templates select="#*|node()"/></xsl:copy>
</xsl:template>
</xsl:transform>
I used XSLT 2.0, because initially you did't specify the XSLT version.
Could you move on to version 2.0? As you can see, it allows to write quite
an elegent solution (impossible in version 1.0).
I also changed your template matching record/*. You actually don't
need any param. It is enough to use . - the value of the current
element.
Edit
Another possibility is that you want the following sort:
First, elements with non-numeric value (in your case, only name),
maybe without any sort.
Then elements with numeric value, sorted descending on this value.
If this is the case, then change the template matching record to the
following:
<xsl:template match="record">
<xsl:copy>
<xsl:apply-templates select="*[not(. castable as xs:integer)]"/>
<xsl:apply-templates select="*[. castable as xs:integer]">
<xsl:sort select="." order="descending" data-type="number"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
And add:
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
to transform tag.
But I still can't see anything, which can be called the specific value.
I have an source schema with a node forenames (containing forename + ' ' + middlename), which I need to separate out the middle name in the destination schema so this goes out to OtherNames.
I currently have the following xslt template:
<xsl:template name="StringSplit">
<xsl:param name="valFirstnames" />
<xsl:choose>
<xsl:when test="contains($valFirstnames, ' ')">
<xsl:call-template name="StringSplit">
<xsl:with-param name="valFirstnames" select="substring-after($valFirstnames, ' ')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<OtherFirstNames><xsl:value-of select="$valFirstnames" /></OtherFirstNames>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Current output for this xslt template is writing out the Middlename twice rather than once:
<OtherFirstName>Middlename</OtherFirstName>
<OtherFirstName>Middlename</OtherFirstName>
Expected:
<OtherFirstName>Middlename</OtherFirstName>
Sample Input
<Data>
<SubjectName>
<forenames>first middle</forenames>
</SubjectName>
<SubjectPartner>
<forenames>first middle</forenames>
<Otherforenames>first middle</Otherforenames>
</SubjectPartner>
<etc./>
</Data>
Sample Output
<Data>
<SubjectName>
<firstname>first</firstname>
<OtherFirstName>middle</OtherFirstname>
</SubjectName>
<SubjectPartner>
<firstname>first</firstname>
<OtherFirstName>middle</OtherFirstName>
<OtherFirstName>middle</OtherFirstName>
</SubjectPartner>
<etc./>
</Data>
I'm looking at correcting the current xslt and updating to incorporate other partner elements that have the same child elements forenames.
Your examples do not make much sense to me. I am guessing you want to do something like:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="forenames">
<firstname><xsl:value-of select="substring-before(concat(., ' '), ' ')"/></firstname>
<xsl:if test="contains(., ' ')">
<OtherFirstName><xsl:value-of select="substring-after(., ' ')"/></OtherFirstName>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Note that this assumes a person has at most two forenames. When applied to the following test input:
<Data>
<SubjectName>
<forenames>Alan Benjamin</forenames>
<surname>Adams</surname>
</SubjectName>
<SubjectPartner>
<forenames>Cecily Diana</forenames>
<surname>Crown</surname>
</SubjectPartner>
<Single>
<forenames>Eve</forenames>
<surname>Evans</surname>
</Single>
<Triple>
<forenames>Frank George Herbert</forenames>
<surname>Forrester</surname>
</Triple>
</Data>
the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<Data>
<SubjectName>
<firstname>Alan</firstname>
<OtherFirstName>Benjamin</OtherFirstName>
<surname>Adams</surname>
</SubjectName>
<SubjectPartner>
<firstname>Cecily</firstname>
<OtherFirstName>Diana</OtherFirstName>
<surname>Crown</surname>
</SubjectPartner>
<Single>
<firstname>Eve</firstname>
<surname>Evans</surname>
</Single>
<Triple>
<firstname>Frank</firstname>
<OtherFirstName>George Herbert</OtherFirstName>
<surname>Forrester</surname>
</Triple>
</Data>
I have tag in xml which value sometimes -ve number and sometimes +ve number and I want to show the -ve(e.g -10) number as (10) I mean with bracket using xslt1.0.
Could you please help me?
I am using below template but it is not working.
<xsl:call-template name="fmtNumber">
<xsl:with-param name="amt" select="retailer:Amount" />
</xsl:call-template>
<xsl:template name="fmtNumber">
<xsl:param name="amt" />
<xsl:value-of
select="format-number($amt, ' $###,##0 ;($###,##0)')" />
</xsl:template>
it is showing the result in csv file as $(10) but, I want (10), I mean without dollar sumbol.
do:
<xsl:value-of select="format-number($amt, '###,##0;(###,##0)')"/>
Please run the following stylesheet (with any XML source) on your processor and post the resulting code.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:variable name="num" select="-123" />
<xsl:template match="/">
<result>
<version><xsl:value-of select="system-property('xsl:version')"/></version>
<vendor><xsl:value-of select="system-property('xsl:vendor')"/></vendor>
<test><xsl:value-of select="format-number($num, '#,##0;(#,##0)')"/></test>
</result>
</xsl:template>
</xsl:stylesheet>
I would like to know how to replace the string with the abbreviations.
My XML looks like below
<concept reltype="CONTAINS" name="Left Ventricular Major Axis Diastolic Dimension, 4-chamber view" type="NUM">
<code meaning="Left Ventricular Major Axis Diastolic Dimension, 4-chamber view" value="18074-5" schema="LN" />
<measurement value="5.7585187646">
<code value="cm" schema="UCUM" />
</measurement>
<content>
<concept reltype="HAS ACQ CONTEXT" name="Image Mode" type="CODE">
<code meaning="Image Mode" value="G-0373" schema="SRT" />
<code meaning="2D mode" value="G-03A2" schema="SRT" />
</concept>
</content>
</concept>
and I am selecting some value from the xml like,
<xsl:value-of select="concept/measurement/code/#value"/>
Now what I want is, I have to replace cm with centimeter. I have so many words like this. I would like to have a xml for abbreviations and replace from them.
I saw one similar example here.
Using a Map in XSL for expanding abbreviations
But it replaces node text, but I have text as attribute. Also, it would be better for me If I can find and replace when I select text using xsl:valueof select instead of having a separate xsl:template. Please help. I am new to xslt.
I have created XSLT v "1.1". For abbreviations I have created XML file as you have mentioned:
Abbreviation.xml:
<Abbreviations>
<Abbreviation>
<Short>cm</Short>
<Full>centimeter</Full>
</Abbreviation>
<Abbreviation>
<Short>m</Short>
<Full>meter</Full>
</Abbreviation>
</Abbreviations>
XSLT:
<xsl:stylesheet version="1.1" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml" />
<xsl:param name="AbbreviationDoc" select="document('Abbreviation.xml')"/>
<xsl:template match="/">
<xsl:call-template name="Convert">
<xsl:with-param name="present" select="concept/measurement/code/#value"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="Convert">
<xsl:param name="present"/>
<xsl:choose>
<xsl:when test="$AbbreviationDoc/Abbreviations/Abbreviation[Short = $present]">
<xsl:value-of select="$AbbreviationDoc/Abbreviations/Abbreviation[Short = $present]/Full"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$present"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
INPUT:
as you have given <xsl:value-of select="concept/measurement/code/#value"/>
OUTPUT:
centimeter
You just need to enhance this Abbreviation.xml to keep short and full value of abbreviation and call 'Convert' template with passing current value to get desired output.
Here a little shorter version:
- with abbreviations in xslt file
- make use of apply-templates with mode to make usage shorter.
But with xslt 1.0 node-set extension is required.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
extension-element-prefixes="exsl">
<xsl:output method="xml" indent="yes"/>
<xsl:variable name="abbreviations_txt">
<abbreviation abbrev="cm" >centimeter</abbreviation>
<abbreviation abbrev="m" >meter</abbreviation>
</xsl:variable>
<xsl:variable name="abbreviations" select="exsl:node-set($abbreviations_txt)" />
<xsl:template match="/">
<xsl:apply-templates select="concept/measurement/code/#value" mode="abbrev_to_text"/>
</xsl:template>
<xsl:template match="* | #*" mode="abbrev_to_text">
<xsl:variable name="abbrev" select="." />
<xsl:variable name="long_text" select="$abbreviations//abbreviation[#abbrev = $abbrev]/text()" />
<xsl:value-of select="$long_text"/>
<xsl:if test="not ($long_text)">
<xsl:value-of select="$abbrev"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
<choice>
I want to select the first element in <choice> whose name matches the name of any element in <choices>.
If name(node-set) returned a list of names instead of only the name of the first node, I could use
select="choice/*[name() = name(choices/*)][1]"
But it doesn't (at least not in 1.0), so instead I join the names together in a string and use contains():
<xsl:variable name="choices.str">
<xsl:for-each select="choices/*">
<xsl:text> </xsl:text><xsl:value-of select="concat(name(),' ')"/>
</xsl:for-each>
</xsl:variable>
<xsl:apply-templates select="choice/*[contains($choices.str,name())][1]"/>
and get what I want:
Red, the value of <corr>
Is there a more straightforward way?
I. Use this XPath 2.0 one-liner:
/*/choice/*[name() = /*/choices/*/name()][1]
When this XPath expression is evaluated against the following XML document (the provided one, but corrected to become a well-formed XML document):
<t>
<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
</choice>
</t>
the correct element is selected:
<corr>Red</corr>
II. XSLT 1.0 (no keys!):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="vNames">
<xsl:for-each select="/*/choices/*">
<xsl:value-of select="concat(' ', name(), ' ')"/>
</xsl:for-each>
</xsl:variable>
<xsl:template match="/">
<xsl:copy-of select=
"/*/choice/*
[contains($vNames, concat(' ', name(), ' '))]
[1]"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the same XML document (above), again the correct element is selected (and copied to the output):
<corr>Red</corr>
III. Using keys:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kChoiceByName" match="choice/*"
use="boolean(/*/choices/*[name()=name(current())])"/>
<xsl:template match="/">
<xsl:copy-of select="/*/choice/*[key('kChoiceByName', true())][1]"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied against the same XML document (above), the same correct result is produced:
<corr>Red</corr>
It is recommended to the reader to try to understand how this all "works" :)
You can use the key() function like this...
When this input document...
<t>
<choices>
<sic />
<corr />
<reg />
<orig />
</choices>
<choice>
<corr>Red</corr>
<sic>Blue</sic>
</choice>
</t>
...is supplied as input to this XSLT 1.0 style-sheet...
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:key name="kChoices" match="choices/*" use="name()" />
<xsl:template match="/">
<xsl:variable name="first-choice" select="(*/choice/*[key('kChoices',name())])[1]" />
<xsl:value-of select="$first-choice" />
<xsl:text>, the value of <</xsl:text>
<xsl:value-of select="name( $first-choice)" />
<xsl:text>></xsl:text>
</xsl:template>
</xsl:stylesheet>
...this output text is produced...
Red, the value of <corr>
XSLT 2.0 Aside
In XSLT 2.0, you would be able to use the following alternatives for the computation of the $first-choice variable...
Option 1:
(*/choice/*[for $c in . return ../../choices/*[name()=name($c)]])[1]
Option 2:
(*/choice/*[some $c in ../../choices/* satisfies name($c)=name()])[1]