How to “inverse match” with regex without content? [closed] - regex

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I have read How to "inverse match" with regex? and i would like to know if i can apply it to a non-content regex. In particular i'm talking about: ^[A-z0-9+\/]{44}$
I tried https://regex101.com/r/NmOs7Z/1 but it does not work

I didn't get exactly what you really, but from my understanding you want to match the two lines in your demo
So what i did :
^(?![a-zA-Z0-9+\/]{44}).*$
Demo

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Simple regex to match "word" or "word/" [closed]

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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks
You should try:
^word\/?$
See this demo

Extracting a word between two parenthesis regex [closed]

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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]

I need a regex for the following combination [closed]

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mission_id: a498094578a
mission_id: a493453456
mission_id: 498343454a
mission_id: 34534535345
From the above 4 mission_id's I need your help in writing a regex pattern which covers all the four mission_id but need to select only the numbers.
So one the first one - need to exempt 'a' and only the numbers.
mission_id:\s*\w?(\d*)\w?
That should work; maybe add any flags you need for parsing multiline text or whatever.
www.regexr.com is a great resource for trying out RegExps

Regex exclude &# [closed]

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How to determine that string doesn't contain both symbols &# together using regular expression ?
You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo

Regex Expression Required [closed]

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i am new to this regex thing, how can we build regex expression for following thig
input==>[User:1490474408:michaelayliffe]
output should be ==>1490474408
input will be anything like below:
1.[User:1490474408:michaelayliffe]
2.[User:12345:dfhdfhdf]
3.[User:56789:utyutyutyu]
Output should be middle value.
Please reply.
(?<=\[User:)[^:]+
Using lookbehind should work for you.
/\d+/g
It is find digits those are middle of your string