Extracting a word between two parenthesis regex [closed] - regex

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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks


re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]

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Simple regex to match "word" or "word/" [closed]

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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks

You should try:
^word\/?$
See this demo

How to “inverse match” with regex without content? [closed]

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I have read How to "inverse match" with regex? and i would like to know if i can apply it to a non-content regex. In particular i'm talking about: ^[A-z0-9+\/]{44}$
I tried https://regex101.com/r/NmOs7Z/1 but it does not work

I didn't get exactly what you really, but from my understanding you want to match the two lines in your demo
So what i did :
^(?![a-zA-Z0-9+\/]{44}).*$
Demo

Regex exclude &# [closed]

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How to determine that string doesn't contain both symbols &# together using regular expression ?

You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo

Remove hastag/pound/octothorpe from string in R [closed]

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I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks

I have triedgsub("^#",'',iii), and it works

Regex to capture a number from an URL [closed]

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can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx

\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26