A SOAP webservice is been exposed by a system. I have got a wsdl file of the webservice. Im able to send request and get response from soap ui. I want to duplicate this wsdl SOAP webservice in my camel routes deployed in servicemix, thereby making my ESB expose a similar webservice as the system's webservice. THis way many systems access this webservice to contact the system.
How do i duplicate a webservice using wsdl file of the system??
To duplicate webservice, exposed by a system, you can use http proxy route, based on jetty:
<route id="ServiceProxy">
<from uri="jetty:http://0.0.0.0:8186/service/?disableStreamCache=true&matchOnUriPrefix=true&continuationTimeout=900000&httpClient.timeout=120000"/>
<to uri="jetty:http://{{app-server.host}}:{{app-server.http.port}}/service/?bridgeEndpoint=true&throwExceptionOnFailure=false&continuationTimeout=120000&httpClient.timeout=900000"/>
</route>
You can write the same route on JavaDSL.
Found solution - Concept is cxf-proxying
Having a wsdl of the system, create a similar wsdl with the Endpoints defined according to the localhost and port number.
Save the wsdl in your local project,
provide the path to wsdl in pom, for converting wsdl to java by mentioning in the cxf-codegen-plugin.
create cxf consumer bean with details of local wsdl file
<cxf:cxfEndpoint id="consumerProxy" address="http://remote:port/service/"
serviceClass="com.remote.service.RemoteService" endpointName="c:RemoteService"
serviceName="c:RemoteService" xmlns:c="http://remote/namespace/">
<cxf:properties>
<entry key="dataFormat" value="MESSAGE" />
</cxf:properties>
</cxf:cxfEndpoint>
create cxf producer bean with details of remote wsdl file
<cxf:cxfEndpoint id="producerRemote" address="http://localhost:9001/service/"
serviceClass="com.remote.service.RemoteService" endpointName="c:RemoteService"
serviceName="c:RemoteService" xmlns:c="http://remote/namespace/">
<cxf:properties>
<entry key="dataFormat" value="MESSAGE" />
</cxf:properties>
</cxf:cxfEndpoint>
The proxy routes can be like below
from(cxfEndpoint("consumerProxy"))
.to(cxfEndpoint("producerRemote"));
Sending a request to localhost will be consumed by cxf endpoint - consumerProxy and sent to the cxf endpoint - producerRemote.
The response is sent back the reverse way.
Related
I need to expose soap service on jboss fuse server. What I am tring to do is replicate an existing developed soap service.
Existing Browser URL:
http://ip:8027/Services/Interface/WebServices/TestService.serviceagent?wsdl
Existing Endpoint URL:
http://ip:3456//Services/Interface/WebServices/Service.serviceagent/ChangeCustomerBasicEndpoint1
According to my understanding the above Browser URL can be accessed in browser and WSDL can be viewed.
Similarly we can use this Browser URL in SOAP-UI to get the WSDL and the Endpoint URL is where the request is sent to - right ?
I am able to expose the soap service, by using following code
<?xml version="1.0" encoding="UTF-8"?>
<blueprint xmlns="http://www.osgi.org/xmlns/blueprint/v1.0.0"
xmlns:cxf="http://camel.apache.org/schema/blueprint/cxf"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.osgi.org/xmlns/blueprint/v1.0.0 ">
<cxf:cxfEndpoint
address="http://ip:8027/Services/Interface/WebServices/TestService.serviceagent?wsdl"
id="testEndpoint" serviceClass="pk.com.test.app.TestService">
<cxf:properties>
<entry key="publishedEndpointUrl"
value="http://ip:3456//Services/Interface/WebServices/Service.serviceagent/ChangeCustomerBasicEndpoint1"/>
</cxf:properties>
</cxf:cxfEndpoint>
Every thing is working fine, to the point when I sent the request from SOAP-UI. I get connection refused
because my publishedEndpointUrl has different port and url.
Any help on how to handle this ?
The publishedEndpointUrl will always override the cxf:cxfEndpoint address attribute.
And the wsdl address would be publishedEndpointUrl + "?wsdl"
I have tried to configure Spring MVC in two way SSL using Spring Ws to connect to third party but due to the lack of documentation I have decided to integrate my Spring MVC 4 Application with Web Service Consumer .I am a beginner in Web Service consumption.I would like to know how to configure my Spring MVC 4 application with web service consumer with annotation based configuration to achieve a Two way SSl communication with Third party and also encrypt my soap messages before it is sent to the https server ?If any links or sample code would be helpful.
Also if the WSDL is located in a a https link how do I generate the classes?
This question is huge. There is no a trivial solution
I can provide the steps and guide to the manual
1)Resolve CXF dependencies to include libraries in your project
Use maven, ivy or download. You need jax-ws and related
http://cxf.apache.org/docs/using-cxf-with-maven.html
2) Generate a Java client with wsdl2java to your wsdl
For example
wsdl2java -p com.mycompany.greeting Greeting.wsdl
http://cxf.apache.org/docs/wsdl-to-java.html
3) Create the jax-ws programmatically
wdsl2java have done the work for you
http://cxf.apache.org/docs/how-do-i-develop-a-client.html#HowdoIdevelopaclient?-JAX-WSProxy
HelloService service = new HelloService();
Hello helloClient = service.getHelloHttpPort();
String result = helloClient .sayHi("Joe");
Note: It is also possible configure with spring
4) Configure the authentication with client certificate
This is the hard step
http://cxf.apache.org/docs/client-http-transport-including-ssl-support.html#ClientHTTPTransport(includingSSLsupport)-ConfiguringSSLSupport
Define a conduit file with the reference to your certificate. This is an example
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:http-conf="http://cxf.apache.org/transports/http/configuration"
xmlns:sec="http://cxf.apache.org/configuration/security"
xsi:schemaLocation="http://cxf.apache.org/transports/http/configuration
http://cxf.apache.org/schemas/configuration/http-conf.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd">
<http-conf:conduit name="*.http-conduit">
<http-conf:tlsClientParameters disableCNCheck="true" secureSocketProtocol="TLS">
<sec:keyManagers keyPassword="password" >
<sec:keyStore type="pkcs12" password="password"
file="yourcertificate.p12" />
</sec:keyManagers> </http-conf:tlsClientParameters>
<http-conf:client Connection="Keep-Alive" MaxRetransmits="1" AllowChunking="false" />
</http-conf:conduit>
</beans>
If you prefer to do programmaticaly you can do
Client client = ClientProxy.getClient(helloClient);
HTTPConduit http = (HTTPConduit) client.getConduit();
//set the parameters in a similar way to file
Hello!
I'm trying to learn some Apache Camel and Apache CXF and of course I've ran into some problems.
What I'm trying to do:
Send timed SOAP messages from ESB to some web service, wait for the reponse from the web service and process it. I'm using Apache ServiceMix!.
What I've done:
Implemented a WSDL file with two operations PingOutput (what I'm sending) and PingInput (what I want to receive from the WS).
Implemented a CXF Endpoint (http://127.0.0.1:8090/ping_ws is a WS mocked with SoapUI):
<cxf:cxfEndpoint address="http://127.0.0.1:8090/ping_ws"
id="Ping_Mocked_WS" wsdlURL="ping.wsdl">
<cxf:properties>
<entry key="dataFormat" value="PAYLOAD" />
</cxf:properties>
</cxf:cxfEndpoint>
Implemented a Camel route:
<camelContext xmlns="http://camel.apache.org/schema/spring" streamCache="true">
<route id="ping-ws">
<from uri="timer://ping_timer?fixedRate=true&period=10000"/>
<bean ref="PingBean" method="createPingRequest" />
<to uri="cxf:bean:Ping_Mocked_WS"/>
<bean ref="PingBean" method="processPingResponse" />
</route>
</camelContext>
What I do not understand:
Why the <bean ref="PingBean" method="processPingResponse" /> gets the correct response from SoapUI (the PingOutput operation defined in WSDL)?
Is this the correct way to achieve my goal? And by this way I mean with one single route?
The codes work correctly, I might have some typos here, please do not mind them.
Thanks!
Ad 1)
Likely because the type defined in the method signature of the processPingResponse method. Camel uses bean parameter binding, and based on the type, it uses its type converter to convert to the given type.
And as the payload is a SOAP response in XML it can use JAXB to convert from XML to the type from the method signature.
To do so it uses camel-jaxb which ServiceMix comes with out of the box.
Ad2)
The route works. What it is you want to do differently?
I am trying to creating web service using wsdl first approach and CXF. I am able to generate java file from wsdl and deploy the war file to tomcat server. However, I don't see any soapaction in the generated file. How do I identify the end point url for this web service?
thanks,
Usually in CXF you use Spring configuration to configure endpoint, as described in JAX-WS Configuration. Usually address is relative, e.g.
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jaxws="http://cxf.apache.org/jaxws"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd">
<jaxws:endpoint id="classImpl"
implementor="org.apache.cxf.jaxws.service.Hello"
address="/helloService"/>
</beans>
Address is local to you web app context root.
Assuming that name of you web application is SomeWebApp and the server is available at localhost:8080 then web service should be published at http://localhost:8080/SomeWebApp/helloService. You can test it retrieving WSDL at: http://localhost:8080/SomeWebApp/helloService?wsdl. This URL can be used to create SOAP UI project (the tool that I really recommend for exploring and testing SOAP services).
If you don't use Spring to configure endpoint or you still can't access web service please provide more details about your configuration.
I have a webservice configured like this.
<jaxws:endpoint
id="helloWorld"
xmlns:hello="http://service.test.com/"
serviceName="hello:MyServiceImplService"
endpointName="hello:MyServiceImplPort" address="jms://"
implementor="com.test.service.MyServiceImpl" >
<jaxws:features>
<bean class="org.apache.cxf.feature.LoggingFeature" />
<bean class="org.apache.cxf.transport.jms.JMSConfigFeature">
<property name="jmsConfig" ref="jmsConfig"/>
</bean>
</jaxws:features>
</jaxws:endpoint>`
I want to have the cxf generate the wsdl for me. when the service is http, I can access the wsdl from a url like this http://localhost:8080/server/hello?wsdl, after I change the transport to jms, how do I access the wsdl? what's the jms message I need to send to get the wsdl. or I have to write the wsdl first and expose it through a regular http request. I am asking this because the client need to know the wsdl to get all the type and binding information to generate class. client should already know how to connect the queue.
You can use commandline java2ws tool (see http://cxf.apache.org/docs/java-to-ws.html) passing it your implementation class. There is also a sample invocation from Ant script. It will generate WSDL which your client can use to generate client code.