How to test for null string in node xslt - xslt

Question

Original source of xml
<SubdivisionType>
<ID>null</ID>
<Name>null</Name>
<Parent i:nil="true"/>
</SubdivisionType>
String 'null' is generated by E4X. I have to check if SubdivisionType/ID contains another value then 'null' then skip all SubdivisionType tag.
Here is how i do
<xsl:if test="SubdivisionType/ID[text()!=null]" >
...
</xsl:if>
I can't understand how xlst(saxon) treats string 'null'.

Answer 1

I don't know saxon specifically, but as far as I'm aware, that isn't a "null string"... it's a string with the value "null".
I would try changing...
text()!=null
to...
text()!='null'
so that it reads...
<xsl:if test="SubdivisionType/ID[text()!='null']">

Answer 2

#Simar,
if we conside below as the xml
<?xml version="1.0" encoding="utf-8"?>
<xml>
<SubdivisionType>
<ID>null</ID>
<Name>null</Name>
<Parent nil="true"/>
</SubdivisionType>
<SubdivisionType>
<ID>asd</ID>
<Name>null</Name>
<Parent nil="true"/>
</SubdivisionType>
</xml>
XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" `xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match = "SubdivisionType[ID = 'null']" />
</xsl:stylesheet>
OUTPUT :
<?xml version="1.0" encoding="UTF-8"?>
<xml>
<SubdivisionType>
<ID>asd</ID>
<Name>null</Name>
<Parent nil="true"/>
</SubdivisionType>
</xml>