How can let a C++11 thread run several different functions? - c++

Question

I am learning the new multi-threading techniques in C++11. Almost all the tutorials I read on the web is teaching how to launch a new thread(or several threads) executing a function, how to join (or detach) the thread(or threads) later and how to avoid racing conditions using mutex, etc.
But I don't see any of them showing how to make a thread execute several functions at different parts of the program. The question is, with C++11 threads, is it possible to achieve the following? If so, how? (Giving an example will be great).
void func1(std::vector<int> & data1){ ... }
void func2(std::vector<int> & data2){ ... }
// main function version I
int main(){
std::vector<int> data1;
// prepare data1 for func1;
std::thread t1(func1, std::ref(data1));
std::vector<int> data2;
// prepare data2 for func2;
if (func1 in t1 is done){
t1(func2, std::ref(data2));
}
t1.join();
return 0;
}
And further, what if I want to put the the above main function body into a loop, as following. Is it possible? If so, how?
//main function version II
int main(){
std::vector<int> bigdata1;
std::vector<int> bigdata2;
std::thread t1; // Can I do this without telling t1 the function
// to be executed?
for(int i=0; i<10; ++i){
// main thread prepare small chunk smalldata1 from bigdata1 for func1;
if(t1 is ready to execute a function){t1(func1, std::ref(smalldata1));}
// main thread do other stuff, and prepare small chunk smalldata2 from bigdata2 for func2;
if (func1 in t1 is done){
t1(func2, std::ref(smalldata2));
}
}
t1.join();
return 0;
}

Answer 1

Reference from cplusplus.com:
default constructor constructs a thread object that does not represent any thread of execution.
Therefore std::thread t simply doesn't define an executable thread. A thread function has to be provided when creating the thread and it cannot be set afterwards.
For your main function version I, you will have to create two threads. Something as the following:
int main(){
std::vector<int> data1;
// prepare data1 for func1;
std::thread t1(func1, std::ref(data1));
std::vector<int> data2;
// prepare data2 for func2;
t1.join(); // this is how you wait till func1 is done
// you will have to create a new thread here for func2
std::thread t2(func2, std::ref(data2));
t2.join(); // wait for thread2 (func2) to end
return 0;
}
Similarly, you can put them in a loop and it is alright which will give you main function version II.

Answer 2

C++11 threading are primitives intended to allow you to write real libraries. They are not easy to use. You should wrap them.
Something like:
struct tasks {
std::mutex m;
std::condition_variable v;
std::vector<std::packaged_task<void>> work;
std::vector<std::future<void>> finished;
void operator()(){
while(true){
std::packaged_task<void> f;
{
std::unique_lock<std::mutex> l(m);
if (work.empty()){
v.wait(l,[&]{return !work.empty();});
}
f = std::move(work.front());
work.pop_front();
}
if (!f.valid()) return;
f();
}
}
std::future<void> do(std::function<void()> f){
std::packaged_task<void> p(f);
auto r=p.get_future();
{
std::unique_lock<std::mutex> l(m);
work.push_back(std::move(p));
v.notify_one();
}
return r;
}
void start(){
finished.push_back(std::async(std::launch_policy::async,
std::ref(*this)));
}
~tasks(){
std::unique_lock<std::mutex> l(m);
for(auto&&unused:finished){
work.push_back({});
}
v.notify_all();
}
};
use looks like:
int main(){
tasks t;
t.start();
t.do([]({std::cout<<"hello ";});
t.do([]({std::cout<<"world\n";});
}
if you want to know when a task is done, check the future do returns.
Written on phone, not compiled, probably full of typos and errors, but a place to start.
Does not support abort early. Easy to write abaondon which empties work.
Supports multiple consumers (workwe threads) I suspect. On compliant system, at dtor will wait for all threads to finish the queued jobs. Not on MSVC2013 tho.