I have this string: "{ts '2015-03-02 12:00:00'}"(variables.fl_dt) and I am trying to convert it using date format:
#DateFormat("#variables.fl_dt#", "yyyy.MM.dd 'at' HH:nn:ss")#
Everything is ok except the minutes: 2015.03.02 at 12:nn:00
On Adobe's website "nn" is for minutes but it seems that is not working here. Any ideas?
DateFormat does not have time pattern. Requested result can be obtained using DateFormat and TimeFormat functions.
<cfset result = DateFormat(variables.fl_dt, "yyyy.MM.dd") & " at " &
TimeFormat(variables.fl_dt, "HH:nn:ss") />
Look at Adam's comment. dateTimeFormat() will give you what you need.
#DateTimeFormat(variables.fl_dt, "yyyy.MM.dd 'at' HH:nn:ss")#
displays
2015.03.02 at 06:03:10
Related
I have two dates in cells
A1=05.11.2021 18:16
B1=05.11.2021 20:16
I need to find difference in hours between two dates. Result should be (B1-A1)=2 I can't find an answer on the Internet, I ask for help.
use:
=TEXT((DATE(
REGEXEXTRACT(B1, "\d{4}"),
REGEXEXTRACT(B1, "\.(\d+)\."),
REGEXEXTRACT(B1, "^\d+"))+INDEX(SPLIT(B1, " "),,2))-(DATE(
REGEXEXTRACT(A1, "\d{4}"),
REGEXEXTRACT(A1, "\.(\d+)\."),
REGEXEXTRACT(A1, "^\d+"))+INDEX(SPLIT(A1, " "),,2)), "[h]")
arrayformula:
=INDEX(IFNA(TEXT((DATE(
REGEXEXTRACT(B1:B, "\d{4}"),
REGEXEXTRACT(B1:B, "\.(\d+)\."),
REGEXEXTRACT(B1:B, "^\d+"))+INDEX(SPLIT(B1:B, " "),,2))-(DATE(
REGEXEXTRACT(A1:A, "\d{4}"),
REGEXEXTRACT(A1:A, "\.(\d+)\."),
REGEXEXTRACT(A1:A, "^\d+"))+INDEX(SPLIT(A1:A, " "),,2)), "[h]")))
shorter:
=INDEX(IFERROR(1/(1/(TEXT(
REGEXREPLACE(B1:B, "(\d+).(\d+).(\d{4})", "$2/$1/$3")-
REGEXREPLACE(A1:A, "(\d+).(\d+).(\d{4})", "$2/$1/$3"), "[h]")))))
EDIT:
As what #basic mentioned in the above comment, you can format the cell where your output goes or use text with h for hour difference and [h] for the whole duration in hours (got from Cooper's answer). See usage and difference below:
Text:
=text(B1-A1, "h")
or
=text(B1-A1, "[h]")
Update:
Make sure your Date Times uses proper delimiters. / and - are acceptable (e.g. 5/11/2021 18:16:00 or 5-11-2021 18:16:00). (This depends entirely on your locale.)
If you want to show it having . as delimiter, just use a custom Date Time format and use . as its delimiter.
Using custom format:
Actual value vs Display value:
If you don't want to do any changes to the date time and want to have it as text, then replace them using regexreplace before using them in text.
RegexReplace:
=text(REGEXREPLACE(B1, "\.", "/") - REGEXREPLACE(A1, "\.", "/"), "h")
or
=text(REGEXREPLACE(B1, "\.", "/") - REGEXREPLACE(A1, "\.", "/"), "[h]")
I want to display friendly format date just like whatsapp and telegram do. For example, for today's date it shows "today" and yesterday date it shows "yesterday". But I don't want to show three days before as "3 days ago". It should be the regular date like this "Sun, 7 Jul 2019".
I don't have any custom to the current code because it still uses the example from the repo. But I tried to change the format but none of that works.
What does your code look like? You'd have to do some logic like
if (daysAgo > -2) {
return <FormattedRelativeTime numeric="auto" unit="day" value={daysAgo} />
}
return <FormattedDate weekday="short" day="numeric" month="short" year="numeric" value={ts} />
Is there a way to get the current date in ballerina?
As I was browsing through some code examples I came across the syntax to get the current time. Shown below is how to get the current date in Ballerina:
Note: first you have to import the time package given below for this to work.
import ballerina/time;
Then put the following lines of code:
time: Time currentTime = time:[currentTime][2]();
string customTimeString = currentTime.format("dd-MM-yyyy");
This will give the following output:
08-07-2018
This is work for ballerina 0.991 and 1.0 first you have to import the time package
Then it will give the current date if you want to get in a format it will included the code
import ballerina/time;
To get current time
time:Time time = time:currentTime();
string standardTimeString = time:toString(time);
io:println("Current system time in ISO format: ", standardTimeString);
To format the time
string|error customTimeString = time:format(time, "yyyy-MM-dd-E");
if (customTimeString is string) {
io:println("Current system time in custom format: ", customTimeString);
}
y -Years
M -months
d -date
E -day
h -hour
m -Minuit
s -seconds
For Swan Lake Update 3 they seem to have removed the time:currentTime() function.
It seems they have replaced it with time:utcNow().
According to the ballerina documentation,
"The time:Utc is the tuple representation of the UTC. The UTC represents the number of seconds from a specified epoch. Here, the epoch is the UNIX epoch of 1970-01-01T00:00:00Z."
So you can convert this above tuple representation to RFC 3339 timestamp by using,
time:Utc currTime = time:utcNow();
string date = time:utcToString(currTime);
io:println(date);
Then you will get a result like below,
2023-01-14T17:04:15.639510400Z
Using ballerina time library you can convert to other different representations as well.
I have a very specific C++ project, and I use a NetBeans.
Reason for it is because we need to have a specific timestamps, and I found NetBeans templates a great tool for inserting an automatic header with all the relevant stuff.
I manage set everything up nicely, but I can't figure out how to set up the time format in the header template.
Currently it shows this:
Created on April 6, 2017, 2:18 PM
But since I work in Central Europe, I need a 24h hour format so I could have something like
Created on 06.04.2017. at 14:18
I found on how to change a date format here, but it doesn't work for times for some reason.
I even tried with using FreeMaker's template language reference, so I created a variable time that looks like this:
<#assign dateTime = .now>
<#assign time = dateTime?time>
${time?iso("Europe/Zagreb")}
But it still didn't change anything.
Now my template looks like this:
// -*- C++ -*-
<#assign licenseFirst = "/*">
<#assign licensePrefix = " * ">
<#assign licenseLast = " */">
<#assign aDateTime = .now>
<#assign time = aDateTime?time>
<#include "${project.licensePath}">
/*
* File: ${NAME}.${EXTENSION}
* Author: ${user}
*
* Created on ${DATE} at ${time?iso("Europe/Zagreb")}
*/
#ifndef ${GUARD_NAME}
#define ${GUARD_NAME}
#endif /* ${GUARD_NAME} */
Is this possible to be changed at all, and how?
Any help is appreciated.
In your question you link a resource (THANKS for that!!!) suggesting the following for dates:
${date?date?string("dd.MM.yyyy")}
I tried the same for time and it works well:
${time?time?string("HH.mm.ss")}
BTW I also tried producing some errors and got some nice error messages stating what NB expects and what it gets pretty clearly:
${date?time?string("hh.mm.ss")}
${time?date?string("hh.mm.ss")}
${time?datetime?string("hh.mm.ss")}
${date?datetime?string("hh.mm.ss")}
produced:
Error: on line 20, column 6 in Templates/Classes/Class.java
The string doesn't match the expected date/time format. The string to parse was: "11-Jan-2018". The expected format was: "HH:mm:ss".
Error: on line 21, column 6 in Templates/Classes/Class.java
The string doesn't match the expected date/time format. The string to parse was: "13:40:27". The expected format was: "dd-MMM-yyyy".
Error: on line 22, column 6 in Templates/Classes/Class.java
The string doesn't match the expected date/time format. The string to parse was: "13:40:27". The expected format was: "dd-MMM-yyyy HH:mm:ss".
Error: on line 23, column 6 in Templates/Classes/Class.java
The string doesn't match the expected date/time format. The string to parse was: "11-Jan-2018". The expected format was: "dd-MMM-yyyy HH:mm:ss".
Is there any way I can easily check if a string conforms to the SortableDateTimePattern ("s"), or do I need to write a regular expression?
I've got a form where users can input a copyright date (as a string), and these are the allowed formats:
Year: YYYY (eg 1997)
Year and month: YYYY-MM (eg 1997-07)
Complete date: YYYY-MM-DD (eg 1997-07-16)
Complete date plus hours and minutes: YYYY-MM-DDThh:mmTZD (eg 1997-07-16T19:20+01:00)
Complete date plus hours, minutes and seconds: YYYY-MM-DDThh:mm:ssTZD (eg 1997-07-16T19:20:30+01:00)
Complete date plus hours, minutes, seconds and a decimal fraction of a second
YYYY-MM-DDThh:mm:ss.sTZD (eg 1997-07-16T19:20:30.45+01:00)
I don't have much experience of writing regular expressions so if there's an easier way of doing it I'd be very grateful!
Not thoroughly tested and hence not foolproof, but the following seems to work:
var regex:RegExp = /(?<=\s|^)\d{4}(-\d{2}(-\d{2}(T\d{2}:\d{2}(:\d{2}(\.\d{2})?)?\+\d{2}:\d{2})?)?)?(?=\s|$)/g;
var test:String = "23 1997 1998-07 1995-07s 1937-04-16 " +
"1970-0716 1993-07-16T19:20+01:01 1979-07-16T19:20+0100 " +
"2997-07-16T19:20:30+01:08 3997-07-16T19:20:30.45+01:00";
var result:Object
while(result = regex.exec(test))
trace(result[0]);
Traced output:
1997
1998-07
1937-04-16
1993-07-16T19:20+01:01
2997-07-16T19:20:30+01:08
3997-07-16T19:20:30.45+01:00
I am using ActionScript here, but the regex should work in most flavors. When implementing it in your language, note that the first and last / are delimiters and the last g stands for global.
I'd split the input field into many (one for year, month, day etc.).
You can use Javscript to advance from one field to the next once full (i.e. once four characters are in the year box, move focus to month) for smoother entry.
You can then validate each field independently and finally construct the complete date string.