I have two tables. Products P1 and Manufacturers M1. I want to see if the manufacturer_name is in the P1.title and update the P1.manufacturer_id with the M1.manufacturer_id.
UPDATE products P1
set P1.manufacturer_id=manufacturers.manufacturer_id
WHERE P1.title LIKE manufacturers.manufacturer_name;
I am getting Error "#1054 - Unknown column 'manufacturers.manufacturer_name' in 'where clause' "
Also, what is the correct syntax for WHERE P1.title LIKE %M1.manufacturer_name%?
Thank you.
You didn't post much about table structure, or the relationship between manufacturer and products, so the below is my best guess: please review and test it thoroughly. I'd prefer to write this using a JOIN, but without knowing what the foreign keys are, I'm not willing to take the chance on duplication ...
UPDATE P1
SET P1.Manufacturer_ID =
(
SELECT TOP 1 Manufacturer_ID
FROM Manufacturers
WHERE P1.Title LIKE '%' + manufacturer_name + '%'
)
FROM Products P1
Related
Newcommer to Django here.
I'm currently trying to fetch some data from my model with a query that need would need a GROUP BY in SQL.
Here is my simplified model:
class Message(models.Model):
mmsi = models.CharField(max_length=16)
time = models.DateTimeField()
point = models.PointField(geography=True)
I'm basically trying to get the last Message from every distinct mmsi number.
In SQL that would translates like this for example:
select a.* from core_message a
inner join
(select mmsi, max(time) as time from core_message group by mmsi) b
on a.mmsi=b.mmsi and a.time=b.time;
After some tries, I managed to have something working similarly with Django ORM:
>>> mf=Message.objects.values('mmsi').annotate(Max('time'))
>>> Message.objects.filter(mmsi__in=mf.values('mmsi'),time__in=mf.values('time__max'))
That works, but I find my Django solution quite clumsy. Not sure it's the proper way to do it.
Looking at the underlying query this looks like this :
>>> print(Message.objects.filter(mmsi__in=mf.values('mmsi'),time__in=mf.values('time__max')).query)
SELECT "core_message"."id", "core_message"."mmsi", "core_message"."time", "core_message"."point"::bytea FROM "core_message" WHERE ("core_message"."mmsi" IN (SELECT U0."mmsi" FROM "core_message" U0 GROUP BY U0."mmsi") AND "core_message"."time" IN (SELECT MAX(U0."time") AS "time__max" FROM "core_message" U0 GROUP BY U0."mmsi"))
I'd appreciate if you could propose a better solution for this problem.
Thanks !
You only need something like this:
Message.objects.all().distinct('mmsi').values('mmsi', 'time').order_by('mmsi','-id')
or like this:
Message.objects.all().values('mmsi').annotate(date_last=Max('time'))
Note: the last is translate by Django in this sql query:
SELECT "message"."mmsi", MAX("message"."time") AS "date_last" FROM "message" GROUP BY "message"."mmsi", "message"."time" ORDER BY "message"."time" DESC
Using the answers and comments, I managed to solve this using a subquery or a simple distinct order by.
Simple distinct order by solution inspired by #Oriphiel answer:
Message.objects.distinct('mmsi').order_by('mmsi','-time')
The underlying SQL query looks like this :
SELECT DISTINCT ON ("core_message"."mmsi") "core_message"."id", "core_message"."mmsi", "core_message"."time", "core_message"."point"::bytea
FROM "core_message"
ORDER BY "core_message"."mmsi" ASC, "core_message"."time" DESC
Simple and straightforward.
Subquery solution inspired by #DanielRoseman comment:
time_order=Message.objects.filter(mmsi=OuterRef('mmsi')).order_by('-time')
Message.objects.filter(id__in=Subquery(time_order.values('id')[:1]))
The underlying SQL query looks like this :
SELECT "core_message"."id", "core_message"."mmsi", "core_message"."time", "core_message"."point"::bytea
FROM "core_message"
WHERE "core_message"."id" IN
(SELECT U0."id" FROM "core_message" U0 WHERE U0."mmsi" = ("core_message"."mmsi") ORDER BY U0."time" DESC LIMIT 1)
A tad more complex but it gives more flexibility. If I wanted to get first five messages for every MMSI, I'd just need to change the LIMIT value. In Django, it would look like this :
Message.objects.filter(id__in=Subquery(time_order.values('id')[:5]))
I am using PowerBI for a forecasting report. One of the things i need is to identify all areas for a point to point service. For example, metro ethernet can run from a specific area to another one. when the user filters it needs to search from Side_A and Side_B. Both Side_A and Side_B are coming from the same view.
Basically I need the Dax query to do something similar to:
SELECT * FROM tbl where side_a = 'Ex' or side_b = 'Ex'
The DAX equivalent of this query would look something like this:
FILTER(tbl, tbl[side_a] = "Ex" || tbl[side_b] = "Ex")
In the query below I perform a join on a the Rep table with the Customer to exclude Reps that do not have any customers assigned.
let
...
merge_customer = Table.NestedJoin(
select_columns,{"RepCode"},
Customer,{"CustomerRepCode"},
"Customer",
JoinKind.Inner
),
remove_join_column = Table.RemoveColumns(
merge_customer,
{"Customer"}
)
in
remove_join_column
Because it is an inner join I don't need the resulting Customer column. I then delete that column.
Is there a way to shorten this? I have tried excluding the new column name Customer or passing in null and it only generates an error.
I appreciate this may just not be possible due to the language being quite young but thought I may have missed something in the docs.
Table.Join might do what you want, or after the result of Table.NestedJoin you can add a custom column that calls Table.RemoveColumns on the table column. That would probably look like this (didn't verify the code works):
Table.AddCustomColumn(merge_customer, "InnerColumnRemoved", each Table.RemoveColumns([RepCode], {"Customer"}))
And then you would remove the RepCode column
I have two tables I would like to call, but I am not sure if it is possible to combine them into one query or I have to some how call 2 different queries.
Basically I have 2 tables:
1) item_table: name/id etc. + category ID
2) category_table: categoryID, categoryName, categoryParentID.
The parent categories are also inside the same table with their own name.
I would like to call on my details from item_table, as well as getting the name of the category, as well as the NAME of the parent category.
I know how to get the item_table data, plus the categoryName through an INNER JOIN. But can I use the same query to get the categoryParent's name?
If not, what would be the mist efficient way to do it? The rest of the code is in C++.
SELECT item_table.item_name, c1.name AS CatName, c2.name AS ParentCatName
FROM item_table join category_table c1 on item_table.categoryID=c1.categoryID
LEFT OUTER JOIN category_table c2 ON c2.categoryID = c1.categoryParentID
SQL Fiddle: here
class Log:
project = ForeignKey(Project)
msg = CharField(...)
date = DateField(...)
I want to select the four most recent Log entries where each Log entry must have a unique project foreign key. I've tries the solutions on google search but none of them works and the django documentation isn't that very good for lookup..
I tried stuff like:
Log.objects.all().distinct('project')[:4]
Log.objects.values('project').distinct()[:4]
Log.objects.values_list('project').distinct('project')[:4]
But this either return nothing or Log entries of the same project..
Any help would be appreciated!
Queries don't work like that - either in Django's ORM or in the underlying SQL. If you want to get unique IDs, you can only query for the ID. So you'll need to do two queries to get the actual Log entries. Something like:
id_list = Log.objects.order_by('-date').values_list('project_id').distinct()[:4]
entries = Log.objects.filter(id__in=id_list)
Actually, you can get the project_ids in SQL. Assuming that you want the unique project ids for the four projects with the latest log entries, the SQL would look like this:
SELECT project_id, max(log.date) as max_date
FROM logs
GROUP BY project_id
ORDER BY max_date DESC LIMIT 4;
Now, you actually want all of the log information. In PostgreSQL 8.4 and later you can use windowing functions, but that doesn't work on other versions/databases, so I'll do it the more complex way:
SELECT logs.*
FROM logs JOIN (
SELECT project_id, max(log.date) as max_date
FROM logs
GROUP BY project_id
ORDER BY max_date DESC LIMIT 4 ) as latest
ON logs.project_id = latest.project_id
AND logs.date = latest.max_date;
Now, if you have access to windowing functions, it's a bit neater (I think anyway), and certainly faster to execute:
SELECT * FROM (
SELECT logs.field1, logs.field2, logs.field3, logs.date
rank() over ( partition by project_id
order by "date" DESC ) as dateorder
FROM logs ) as logsort
WHERE dateorder = 1
ORDER BY logs.date DESC LIMIT 1;
OK, maybe it's not easier to understand, but take my word for it, it runs worlds faster on a large database.
I'm not entirely sure how that translates to object syntax, though, or even if it does. Also, if you wanted to get other project data, you'd need to join against the projects table.
I know this is an old post, but in Django 2.0, I think you could just use:
Log.objects.values('project').distinct().order_by('project')[:4]
You need two querysets. The good thing is it still results in a single trip to the database (though there is a subquery involved).
latest_ids_per_project = Log.objects.values_list(
'project').annotate(latest=Max('date')).order_by(
'-latest').values_list('project')
log_objects = Log.objects.filter(
id__in=latest_ids_per_project[:4]).order_by('-date')
This looks a bit convoluted, but it actually results in a surprisingly compact query:
SELECT "log"."id",
"log"."project_id",
"log"."msg"
"log"."date"
FROM "log"
WHERE "log"."id" IN
(SELECT U0."id"
FROM "log" U0
GROUP BY U0."project_id"
ORDER BY MAX(U0."date") DESC
LIMIT 4)
ORDER BY "log"."date" DESC