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How does the following make differences in Perl regex syntax?
if /\d+/
if /[\d]+/
if /(\d+)/
They all the same, except the third creates a capture group.
See perlre
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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
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I need a regular expression that will find:
F.01,
F1.01,
F9.99,
F10.01,
And any decimal to the second place in between.
You can use this pattern
F\d+\.\d\d$
for most of the platforms it should work
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How to determine that string doesn't contain both symbols &# together using regular expression ?
You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo
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Today I attemped several time to build regular expression to validate a set of double number with semi-colon delimeted following example data below:
Should match:
123.1234567890
123.1234567890;123.1234567890;123.1234567890
Should not match:
123.1234567890;
123.1234567890;123.1234567890;123.1234567890;
If you have any idea, Could you please help me ?
Thank you very much
You can try this:
(\d+\.\d+;)*\d+\.\d+(?![\d;])
to match the whole 123.1234567890;123.1234567890;123.1234567890
\d+\.\d+(?![\d;])
to match just the last.
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can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx
\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26