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can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx
\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26
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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks
You should try:
^word\/?$
See this demo
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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
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I need a regular expression that will find:
F.01,
F1.01,
F9.99,
F10.01,
And any decimal to the second place in between.
You can use this pattern
F\d+\.\d\d$
for most of the platforms it should work
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I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks
I have triedgsub("^#",'',iii), and it works
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How does the following make differences in Perl regex syntax?
if /\d+/
if /[\d]+/
if /(\d+)/
They all the same, except the third creates a capture group.
See perlre