ifstream get line change output from char to string - c++

C++ ifstream get line change getline output from char to string
I got a text file.. so i read it and i do something like
char data[50];
readFile.open(filename.c_str());
while(readFile.good())
{
readFile.getline(data,50,',');
cout << data << endl;
}
My question is instead of creating a char with size 50 by the variable name data, can i get the getline to a string instead something like
string myData;
readFile.getline(myData,',');
My text file is something like this
Line2D, [3,2]
Line3D, [7,2,3]
I tried and the compiler say..
no matching function for getline(std::string&,char)
so is it possible to still break by delimiter, assign value to a string instead of a char.
Updates:
Using
while (std::getline(readFile, line))
{
std::cout << line << std::endl;
}
IT read line by line, but i wanna break the string into several delimiter, originally if using char i will specify the delimiter as the 3rd element which is
readFile.getline(data,50,',');
how do i do with string if i break /explode with delimiter comma , the one above. in line by line

Use std::getline():
std::string line;
while (std::getline(readFile, line, ','))
{
std::cout << line << std::endl;
}
Always check the result of read operations immediately otherwise the code will attempt to process the result of a failed read, as is the case with the posted code.
Though it is possible to specify a different delimiter in getline() it could mistakenly process two invalid lines as a single valid line. Recommend retrieving each line in full and then split the line. A useful utility for splitting lines is boost::split().

Related

Deleting from a certain point in a file to the end of the line?

I'm having some trouble with detecting two '//' as a char and then deleting from the first '/' till the end of the line (im guessing /n comes into use here).
{
ifstream infile;
char comment = '//';
infile.open("test3.cpp");
if (!infile)
{
cout << "Can't open input file\n";
exit(1);
}
char line;
while (!infile.eof())
{
infile.get(line);
if (line == comment)
{
cout << "found it" << endl;
}
}
return 0;
}
In the test3.cpp file there are three comments, so 3 lots of '//'. But I can't detect the double slash and can only detect a single / which will affect other parts of the c++ file as I only want to delete from the beginning of a comment to the end of the line?
I'm having some trouble with detecting two '//' as a char
That's because // is not a character. It is a sequence of two characters. A sequence of characters is known as a string. You can make string literals with double quotation marks: "//".
A simple solution is to compare the current input character from the stream to the first character of the string "//" which is '/'. If it matches, then compare the next character from the stream with the second character in the string that is searched for. If you find two '/' in a row, you have your match. Or you could be smart and read the entire line into a std::string and use the member functions to find it.
Also:
while (!infile.eof())
{
infile.get(line);
// using line without testing eof- and badbit
This piece of code is wrong. You test for eofbit before reading the stream and process the input.
And your choice of name for the line variable is a bit confusing since it doesn't contain the entire. line but just one character.

Missing line of data using Getline with Ifstream

Ok so this is killing me at the moment cause its such a simple part of my program that just doesn't want to work. I'm reading data from a textfile to use in a GA.
The first getline() works perfectly, but the second one doesn't want to write any data into my string. When i cout the string it doesn't show anything.
Here is the code:
ifstream inFile;
inFile.open(fname.c_str());
char pop[20], mut[20];
inFile.getline(pop,20);
cout << pop;
inFile.getline(mut,20);
cout << mut; //this outputs nothing
Thanks for any help in advance.
A sample form my file:
there is no line between them mutation is the line straight after population
Population size: 30
Mutation: 20
Your file's first line is 20 characters long (19+new line) but pop[20] can only contain 19 (because the last one is reserved for the null terminator '\0').
When istream::getline stops because it has extracted 20-1 characters, it doesn't discard the new line delimiter (because it was never read). So the next getline just reads the end of the first line, discarding the new line.
That's why you get nothing in the second string.
Your problem is that the length of your input line exceeds the length of the buffer which must hold it.
The solution is to not use character arrays. This is C++, use std::string!
std::ifstream inFile;
inFile.open(fname.c_str());
std::string pop;
std::getline(inFile, pop);
cout << pop << "\n";
std::string mut;
std::getline(inFile, mut);
cout << mut << "\n";
I think you need to find out what the problem is. Add error checking code to your getline calls, refactor the (simple) code into a (simple) function, with a (simple) unittest. Possibly, your second line is longer than the assumed 20 characters (null-term included!).
For an idea of what I mean, take a look at this snippet.
try something like
while (getline(in,line,'\n')){
//do something with line
}
or try something like
string text;
string temp;
ifstream file;
file.open ("test_text.txt");
while (!file.eof())
{
getline (file, temp);
text.append (temp); // Added this line
}

Why does getline return empty lines if none exist

I have a file containing the following lines:
5556
0 bla.dxf
1 blub.dxf
2 buzz.dxf
The numbers and text are seperated by a singular tab each, there is no whitespace character after 5556. The following code is used for parsing.
int main(int, char**){
std::ifstream file("test.bld");
std::string buildingName;
file >> buildingName;
std::cout << buildingName << std::endl;
std::string buf;
while(getline(file, buf)) {
if(buf.empty()){std::cout << "String was empty"<<std::endl;}
else std::cout << buf << std::endl;
}
return 0;
}
When I parse the file I get an empty line although there obviously is none.
The output reads as follows:
5556
String was empty
0 bla.dxf
1 blub.dxf
2 buzz.dxf
This is only a minimal example. The whole file and the parser is more complex and I would very much like to use direct parsing for the first element and getline for the rest. What am I misunderstanding about line parsing with getline and how do I avoid getting empty lines?
operator>>(istream, string) reads up to but not including the first whitespace character after the extracted token.
To skip the rest of the line after extracting a token, you can either use
std::cin >> std::ws;
(if you know that there is only a newline remaining), or
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
to skip to the end of the line regardless.
I'm assuming because
file >> buildingName;
doesn't move the cursor to the next line, but leaves it at the end of the current line. So when you call getline, you'll read an empty string and then move to the next.

Reading from a file, only reads text untill it gets to empty space

I managed to successfully read the text in a file but it only reads until it hits an empty space, for example the text: "Hi, this is a test", cout's as: "Hi,".
Removing the "," made no difference.
I think I need to add something similar to "inFil.ignore(1000,'\n');" to the following bit of code:
inFil>>text;
inFil.ignore(1000,'\n');
cout<<"The file cointains the following: "<<text<<endl;
I would prefer not to change to getline(inFil, variabel); because that would force me to redo a program that is essentially working.
Thank you for any help, this seems like a very small and easily fixed problem but I cant seem to find a solution.
std::ifstream file("file.txt");
if(!file) throw std::exception("Could not open file.txt for reading!");
std::string line;
//read until the first \n is found, essentially reading line by line unti file ends
while(std::getline(file, line))
{
//do something line by line
std::cout << "Line : " << line << "\n";
}
This will help you read the file. I don't know what you are trying to achieve since your code is not complete but the above code is commonly used to read files in c++.
You've been using formatted extraction to extract a single string, once: this means a single word.
If you want a string containing the entire file contents:
std::fstream fs("/path/to/file");
std::string all_of_the_file(
(std::istreambuf_iterator<char>(filestream)),
std::istreambuf_iterator<char>()
);

Tokenization of a text file with frequency and line occurrence. Using C++

once again I ask for help. I haven't coded anything for sometime!
Now I have a text file filled with random gibberish. I already have a basic idea on how I will count the number of occurrences per word.
What really stumps me is how I will determine what line the word is in. Gut instinct tells me to look for the newline character at the end of each line. However I have to do this while going through the text file the first time right? Since if I do it afterwords it will do no good.
I already am getting the words via the following code:
vector<string> words;
string currentWord;
while(!inputFile.eof())
{
inputFile >> currentWord;
words.push_back(currentWord);
}
This is for a text file with no set structure. Using the above code gives me a nice little(big) vector of words, but it doesn't give me the line they occur in.
Would I have to get the entire line, then process it into words to make this possible?
Use a std::map<std::string, int> to count the word occurrences -- the int is the number of times it exists.
If you need like by line input, use std::getline(std::istream&, std::string&), like this:
std::vector<std::string> lines;
std::ifstream file(...) //Fill in accordingly.
std::string currentLine;
while(std::getline(file, currentLine))
lines.push_back(currentLine);
You can split a line apart by putting it into an std::istringstream first and then using operator>>. (Alternately, you could cobble up some sort of splitter using std::find and other algorithmic primitaves)
EDIT: This is the same thing as in #dash-tom-bang's answer, but modified to be correct with respect to error handing:
vector<string> words;
int currentLine = 1; // or 0, however you wish to count...
string line;
while (getline(inputFile, line))
{
istringstream inputString(line);
string word;
while (inputString >> word)
words.push_back(pair(word, currentLine));
}
Short and sweet.
vector< map< string, size_t > > line_word_counts;
string line, word;
while ( getline( cin, line ) ) {
line_word_counts.push_back();
map< string, size_t > &word_counts = line_word_counts.back();
istringstream line_is( line );
while ( is >> word ) ++ word_counts[ word ];
}
cout << "'Hello' appears on line 5 " << line_word_counts[5-1]["Hello"]
<< " times\n";
You're going to have to abandon reading into strings, because operator >>(istream&, string&) discards white space and the contents of the white space (== '\n' or != '\n', that is the question...) is what will give you line numbers.
This is where OOP can save the day. You need to write a class to act as a "front end" for reading from the file. Its job will be to buffer data from the file, and return words one at a time to the caller.
Internally, the class needs to read data from the file a block (say, 4096 bytes) at a time. Then a string GetWord() (yes, returning by value here is good) method will:
First, read any white space characters, taking care to increment the object's lineNumber member every time it hits a \n.
Then read non-whitespace characters, putting them into the string object you'll be returning.
If it runs out of stuff to read, read the next block and continue.
If the you hit the end of file, the string you have is the whole word (which may be empty) and should be returned.
If the function returns an empty string, that tells the caller that the end of file has been reached. (Files usually end with whitespace characters, so reading whitespace characters cannot imply that there will be a word later on.)
Then you can call this method at the same place in your code as your cin >> line and the rest of the code doesn't need to know the details of your block buffering.
An alternative approach is to read things a line at a time, but all the read functions that would work for you require you to create a fixed-size buffer to read into beforehand, and if the line is longer than that buffer, you have to deal with it somehow. It could get more complicated than the class I described.