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What is the a regular expression to only allow whole numbers from 1 through 99? (including both 1 and 99)
Try this:
^[1-9][0-9]?$
The ? means that the previous token is optional.
The ^ and $ are anchors for the start and end of the string respectively.
Surely you mean
[1-9][0-9]?
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I have read How to "inverse match" with regex? and i would like to know if i can apply it to a non-content regex. In particular i'm talking about: ^[A-z0-9+\/]{44}$
I tried https://regex101.com/r/NmOs7Z/1 but it does not work
I didn't get exactly what you really, but from my understanding you want to match the two lines in your demo
So what i did :
^(?![a-zA-Z0-9+\/]{44}).*$
Demo
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How to determine that string doesn't contain both symbols &# together using regular expression ?
You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo
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i am new to this regex thing, how can we build regex expression for following thig
input==>[User:1490474408:michaelayliffe]
output should be ==>1490474408
input will be anything like below:
1.[User:1490474408:michaelayliffe]
2.[User:12345:dfhdfhdf]
3.[User:56789:utyutyutyu]
Output should be middle value.
Please reply.
(?<=\[User:)[^:]+
Using lookbehind should work for you.
/\d+/g
It is find digits those are middle of your string
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I want to pass values those are not equal zero (0). What is the best performing regex pattern for this ?
[^0]+
Means: Any character besides zero must occur at least once
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In Perl, I would like to determine if a given string is valid, the rule is to check if values exist between commas.
e.g. abc,abc is a valid case, but abc, or abc,,abc are not.
m/^\s*,|,\s*,|,\s*$/
matches all invalid combinations, assuming whitespace does not count as "values".