I am using the ABAP statement READ REPORT and I want to use FIND ALL OCCURRENCES OF REGEX. Let's say for example I want to search for SELECT but when I do FIND ALL OCCURRENCES OF REGEX 'SELECT', the return table gets lines that have SELECT-OPTIONS, SELECTION-SCREEN and SELECT.
How do I use regex to get only those lines with SELECT, discarding the other 2 possible matches in the example above?
Just go for `SELECT `
Note the extra space and the use of grave quotes (grave quotes so that the trailing space is considered). This simple solution is feasible because it's highly unlikely that there's a new line right after SELECT.
Your requirement is so simple that you don't need to use a regular expression.
http://sapignite.com/regex-in-abap/
OR
Download a PDF from this Link
http://www.google.co.in/url?sa=t&rct=j&q=how%20do%20i%20use%20regex%20in%20abap%20to%20search%20for%20a%20specific%20string%3F&source=web&cd=1&ved=0CCMQFjAA&url=http%3A%2F%2Fwww.sdn.sap.com%2Firj%2Fscn%2Findex%3Frid%3D%2Flibrary%2Fuuid%2F902ce392-dfce-2d10-4ba9-b4f777843182%26overridelayout%3Dtrue&ei=AsFxT9bJNdDqrQfdoe3hDQ&usg=AFQjCNHTHvQXYtYosCLPwj98Za-LMJbo7w&cad=rja
use
\bselect\b
\b stands for word boundary. It will not match aselect or selected
look at a good regex reference at mozila.org and try your regex at regexpal
There is a very cool playground for testing regular expressions: Run Report DEMO_REGEX_TOY with SE38 or SE80.
Related
I have a project that demands extracting data from XML files (values inside the <Number>... </Number> tag), however, in my regular expression, I haven't been able to extract lines that had multiple data separated by a newline, see the below example:
As you can see above, I couldn't replicate the multiple lines detection by my regular expression.
If you are using a script somewhere, your first plan should be to use a XML parser. Almost every language has one and it should be far more accurate compared to using regex. However, if you just want to use regex to search for strings inside npp, then you can use \s+ to capture multiple new lines:
<Number>(\d+\s)+<\/Number>
https://regex101.com/r/MwvBxz/1
I'm not sure I fully understand what you are trying to do so if this doesn't do it then let me know what you are going for.
You can use this find+replace combo to remove everything which is not a digit in between the <Number> tag:
Find:
.*?<Number>(.*?)<\/Number>.*
Replace:
$1
finally i was able to find the right regular expression, I'll leave it below if anyone needs it:
<Type>\d</Type>\n<Number>(\d+\n)+(\d+</Number>)
Explanation:
\d: Shortcut for digits, same as [1-9]
\n: Newline.
+: Find the previous element 1 to many times.
Have a good day everybody,
After giving it some more thought I decided to write a second answer.
You can make use of look arounds:
(?<=<Number>)[\d\s]+(?=<\/Number>)
https://regex101.com/r/FiaTKD/1
I am searching through a 1.5 million line Premiere Pro project for any text that matches one of my audio filters and is set to mono.
Text that I am searching for begins with the <ChannelType> tag and ends with the <FilterMatchName>Tags. So it would looks like this
<ChannelType>0</ChannelType>
<FrameRate>5292000</FrameRate>
</AudioComponent>
<FilterPreset>0</FilterPreset>
<OpaqueData Encoding="base64" Checksum="53060659">AAAAAD8L8lo+AUr+Pac1NjwTmoUAAAAAP0uQDD37nIg9ui6MPjwU5j+AAAA+C/JaAAAAAD8qqqsAAAAAP4AAAD92L8w9py8FAAAAAHNvZnQgY29tcHJlc3Npb24AIiBkZWZhdWx0PSIwIiBzdGVwPSIxIiBtaW49IjAiIG1heD0iMSIvPgoJICA8Zmw=</OpaqueData>
<FilterIndex>-1</FilterIndex>
<FilterMatchName>1094998321 Dynamics1</FilterMatchName>
If I were in a Word doc, I would just do a find as
<ChannelType>0</ChannelType>*<FilterMatchName>1094998321 Dynamics1</FilterMatchName>
I am terrible with Regex. I was hoping someone could help me out. Everything I have tried either doesn't match anything, or matches EVERYTHING in the document. I am using Notepad++.
Since you are working in Notepad++, you have access to PCRE regular expressions. This one will get all the text between <ChannelType> and </FilterMatchName>
(?s)<ChannelType>.*?</FilterMatchName>
the (?s) allows the . to match newline characters
After matching <ChannelType>, the .*? lazily matches all characters up to...
the closing </FilterMatchName>, which we match.
Let me know if you have any questions. :)
What type of regular expressions are you using (which language/library)?
Basically you can use .* instead of * in regular expressions. IF your text is long though, it's better to use a Reluctant quantifier[1] if your re implementation allows it.
This is a good site with comparison of different re implementations and tutorials:
http://www.regular-expressions.info
[1] http://docs.oracle.com/javase/tutorial/essential/regex/quant.html
I have a large text file which contains many timestamps. The timestamps look like this: 2013/11/14 06:52:38AM. I need to remove the last two characters (am/pm/AM/PM) from each of these. The problem is that a simple find and replace of "AM" may remove text from other parts of the file (which contains a lot of other text).
I have done a find using the regular expression (:\d\d[ap]m), which in the above example would track down the last bit of the timestamp: :38AM. I now need to replace this with :38, but I don't know how this is done (allowing for any combination of two digits after the colon).
Any help would be much appreciated.
EDIT: What I needed was to replace (:\d\d)[ap]m with \1
Make (:\d\d[ap]m) into (:\d\d)[ap]m and use $1 not \1
Go to Search > Replace menu (shortcut CTRL+H) and do the following:
Find what:
[0-9]{2}\K[AP]M
Replace:
[leave empty]
Select radio button "Regular Expression"
Then press Replace All
You can test it at regex101.
Note: the use of [0-9] is generally better than \d (read why), and avoiding to use a capture group $1 with the use of \K is considered better. It's definitely not important in your case, but it is good to know :)
I got a string like this:
PREFIX-('STRING WITH SPACES TO REPLACE')
and i need this:
PREFIX-('STRING_WITH_SPACES_TO_REPLACE')
I'm using Notepad++ for the Regex Search and Replace, but i'm shure every other Editor capable of regex replacements can do it to.
I'm using:
PREFIX-\('(.*)(\s)(.*)'\)
for search and
PREFIX-('\1_\3')
for replace
but that replaces only one space from the string.
The regex search feature in Notepad++ is very, very weak. The only way I can see to do this in NPP is to manually select the part of the text you want to work on, then do a standard find/replace with the In selection box checked.
Alternatively, you can run the document through an external script, or you can get a better editor. EditPad Pro has the best regex support I've ever seen in an editor. It's not free, but it's worth paying for. In EPP all I had to do was this:
search: ((?:PREFIX-\('|\G)[^\s']+)\s+
replace: $1_
EDIT: \G matches the position where the previous match ended, or the beginning of the input if there was no previous match. In other words, the first time you apply the regex, \G acts like \A. You can prevent that by adding a negative lookahead, like so:
((?:PREFIX-\('|(?!\A)\G)[^\s']+)\s+
If you want to prevent a match at the very beginning of the text no matter what it starts with, you can move the lookahead outside the group:
(?!\A)((?:PREFIX-\('|\G)[^\s']+)\s+
And, just in case you were wondering, a lookbehind will work just as well as a lookahead:
((?:PREFIX-\('|(?<!\A)\G)[^\s']+)\s+
You have to keep matching from the beggining of the string untill you can match no more.
find /(PREFIX-\('[^\s']*)\s([^']*'\))/
replace $1_$2
like: while (/(PREFIX-\('[^\s']*)\s([^']*'\))/$1_$2/) {}
How about using Replace all for about 20 times? Or until you're sure no string contains more spaces
Due to nature of regex, it's not possible to do this in one step by normal regular expression.
But if I be in your place, I do such replaces in several steps:
find such patterns and mark them with special character
(Like replacing STRING WITH SPACES TO REPLACE with #STRING WITH SPACES TO REPLACE#
Replace #([^#\s]*)\s to #\1_ server times.
Remove markers!
I studied a little the regex tool in Notepad++ because I didn't know their possibilities.
I conclude that they aren't powerful enough to do what you want.
Your are obliged to learn and use a programming language having a real regex capability. There are a number of them. Personnaly, I use Python. It would take 1 mn to do what you want with it
You'd have to run the replace several times for each space but this regex will work
/(?<=PREFIX-\(')([^\s]+)\s+/g
Replace with
\1_ or $1_
See it working at http://refiddle.com/10z
I have some text like this:
dagGeneralCodes$_ctl1$_ctl0
Some text
dagGeneralCodes$_ctl2$_ctl0
Some text
dagGeneralCodes$_ctl3$_ctl0
Some text
dagGeneralCodes$_ctl4$_ctl0
Some text
I want to create a regular expression that extracts the last occurrence of dagGeneralCodes$_ctl[number]$_ctl0 from the text above.
the result should be: dagGeneralCodes$_ctl4$_ctl0
Thanks in advance
Wael
This should do it:
.*(dagGeneralCodes\$_ctl\d\$_ctl0)
The .* at the front is greedy so initially it will grab the entire input string. It will then backtrack until it finds the last occurrence of the text you want.
Alternatively you can just find all the matches and keep the last one, which is what I'd suggest.
Also, specific advice will probably need to be given depending on what language you're doing this in. In Java, for example, you will need to use DOTALL mode to . matches newlines because ordinarily it doesn't. Other languages call this multiline mode. Javascript has a slightly different workaround for this and so on.
You can use:
[\d\D]*(dagGeneralCodes\$_ctl\d+\$_ctl0)
I'm using [\d\D] instead of . to make it match new-line as well. The * is used in a greedy way so that it will consume all but the last occurrence of dagGeneralCodes$_ctl[number]$_ctl0.
I really like using this Regular Expression Cheatsheet; it's free, a single page, and printed, fits on my cube wall.