I have a field where a user can search in. The user selects an option, then that is posted to a view and returns him with the Filtered results on a new page.
Im not sure how I would paginate this because the data this must be displayed is filtered by the previous post?
To paginate the first one is fine, cause tou have the post and know what to return to the page. But what about page 2 etc? then the post is gone?
Use hidden HTML input fields to keep track values posted from previous post
Related
I am trying to use HTTP_REFERER to create a link to the previous page. However, let's say I have a 'page1' that calls the 'page2' get method. It will show a form at the 'page2' where I can do a post request. When I post on the 'page2', the HTTP_REFERER is referencing the same page (page2), therefore I can't to back to the 'page1'. Is there anything I can do to go back to the 'page1'?
You will need to add a hidden next field to your form . This will capture the previous page by making use of the HTTP_REFERER. After your post request you can then perform a redirect to the page you were on before the form page.
Edit:
More information can also be found here.
Right now. I have a search function in my page to search for item id. When I click search, I will render the same page with the result items and show item. And in other pages where I also display the item id, I want to add a link to the id to go to the same page where I search for that id.
Example: id: 123, I want the same page when:
1. search '123' in my search page(my search only accept exact match)
2. In other pages, click '123', go to the search page with results
How should I achieve this, I have tried many ways which don't wok.
You need to make use of the GET method that HTML forms provide. When you perform a search from the first page, you must make sure that you are doing so using the GET method in the form. This will append the form data into the URL.
E.g. If you have a 'name' field in your form which has 'John' inputted. The submission of this form will compose a URL like so:
http://someurl.com/?name=John
This can then be accessed using the Django request object:
name = request.GET['name']
You've probably done something similar already for displaying your search results. So, all you need to do is create a link in your second page that redirects to the search page with GET request variables appended.
E.g.
<a href="{% url 'search_page' %}?searchterm=232> Item 232 </a>
I originally followed this tutorial (https://django-haystack.readthedocs.org/en/latest/tutorial.html), and have so far been able to highlight my query within my returned results. However, I want to highlight this same query when visiting the next page that I load with a separate template. Is there any way to save/access this query so that I can highlight the same results within this other template?
Whenever I try and include a statement like this, I get an error, which I'm thinking is because I'm not trying to access the query properly.
{% highlight section.body with query html_tag "span" css_class "highlighted" %}
You have to send to the next page, the information that you use to highlight the results in the first page. You can use the request.session to store the data and call it in the next page, or you can send the sqs by the url to the next page.
If you want to know how to manage the search query set, and how to edit that kind of stuff, I recommend you to read the views.py forms.py and the elasticsearch_backend in the haystack folder at: "/usr/local/lib/python2.7/dist-packages/haystack"
This is the url for the documentation of Django Session: Django Session
This is the url for the documentation to pass parameters trhough url: URL dispatcher
I have a form with 6-7 fields. After user input, my webapp searches for those fields in a database and displays the results.
Now the issue is, that the URL ends up having all the form field names and their values in it.
result/?name=lorem&class=arc&course=ipsum
Now with the form having 7-8 fields the url ends up looking ugly.
Is there a Django technique to 'hide' these from the URL? Quotes around hide because I'd be okay with a completely different way to pass the objects to my database from the form as well.
Use a POST request. Here's the django docs on forms and a specific example using POST>. HTML-wise, all you need to do is change the method on the form tag.
I do not recommend to use POST requests for search. If you'll use GET it will be easer for user, he can just bookmark a link and save search or share search results with friends.
I have a form. Once the form is filled I don't want the user to change anything in the form.
But the user can see the values. Meaning all the fields are non editable. I can do this by using instance method but this does not help in foreignkey.
Depends on what you mean "once the form is filled".
If it's an html form post, just render a new html page with simple text and values of the submitted form.
If the post-back was an ajax call, you can change the CSS-styling of the elements for example and disable the submit button or erase the whole and substitute the values that you get back from ajax request.
There is no "editable=False" property on html input elements btw.
you can use readonlyAdmin