Simple regex to match "word" or "word/" [closed] - regex

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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks


You should try:
^word\/?$
See this demo

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Extracting a word between two parenthesis regex [closed]

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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks

re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]

Regex exclude &# [closed]

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How to determine that string doesn't contain both symbols &# together using regular expression ?

You can use a negative lookahead:
/^(?!.*&#)(.*)/m
Demo

Remove hastag/pound/octothorpe from string in R [closed]

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I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks

I have triedgsub("^#",'',iii), and it works

Regex to capture a number from an URL [closed]

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can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx

\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26

I need a REGEX to validate a password field [closed]

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The password must have between 6-15 character and cannot allow the & and %.

/^[^&%]{6,15}$/