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The password must have between 6-15 character and cannot allow the & and %.
/^[^&%]{6,15}$/
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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks
You should try:
^word\/?$
See this demo
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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
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I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks
I have triedgsub("^#",'',iii), and it works
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Ok, so it's late on a Wed night and this is for no good reason. But I'd like to see one in any dialect, if it exists, just to be impressed.
[Rr][eE3][gG][uU][Ll][aA4][rR]\s[Ee3][xX][pP][rR][eE3][Ss5]{2}[iI1][Oo0][nN][sS5]
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Any one has BK-Tree implementation in C++.,