Regex expression to replace string with * [closed] - regex

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I need to convert string like this to
ABC_464_aDE.hmi_2df
to ABC464aDE.* that is want to remove all _ and add * at the end after dot. And my project requirement is to do this using regex. Please help to sort this out.
Thanks

If you are using C# the you can use this code
txt=Regex.Replace(txt.Replace("_",""), #"\.\w+", "");

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Extracting a word between two parenthesis regex [closed]

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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]

I need a regex for the following combination [closed]

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mission_id: a498094578a
mission_id: a493453456
mission_id: 498343454a
mission_id: 34534535345
From the above 4 mission_id's I need your help in writing a regex pattern which covers all the four mission_id but need to select only the numbers.
So one the first one - need to exempt 'a' and only the numbers.
mission_id:\s*\w?(\d*)\w?
That should work; maybe add any flags you need for parsing multiline text or whatever.
www.regexr.com is a great resource for trying out RegExps

Remove anything before first hypen [closed]

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I have Data like this
0266-VN22.5P-AC
0292-VN22.6P-BC
0300-VN22.7P-CC
0316-VN22.8P-DC
I want to remove everything before first hypen and result should look like this
VN22.5P-AC
VN22.6P-BC
VN22.7P-CC
VN22.8P-DC
Any help would be much appreciated.
Try:
gsub("^[^\\-]+\\-", "", "0266-VN22.5P-AC")
Non-greedy search. The question mark is the magic:
sub(".*?-", "", x)
#[1] "VN22.5P-AC" "VN22.6P-BC" "VN22.7P-CC" "VN22.8P-DC"

Regular Expression for set of double number with semi-colon delimeted [closed]

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Today I attemped several time to build regular expression to validate a set of double number with semi-colon delimeted following example data below:
Should match:
123.1234567890
123.1234567890;123.1234567890;123.1234567890
Should not match:
123.1234567890;
123.1234567890;123.1234567890;123.1234567890;
If you have any idea, Could you please help me ?
Thank you very much
You can try this:
(\d+\.\d+;)*\d+\.\d+(?![\d;])
to match the whole 123.1234567890;123.1234567890;123.1234567890
\d+\.\d+(?![\d;])
to match just the last.

Regex Expression Required [closed]

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i am new to this regex thing, how can we build regex expression for following thig
input==>[User:1490474408:michaelayliffe]
output should be ==>1490474408
input will be anything like below:
1.[User:1490474408:michaelayliffe]
2.[User:12345:dfhdfhdf]
3.[User:56789:utyutyutyu]
Output should be middle value.
Please reply.
(?<=\[User:)[^:]+
Using lookbehind should work for you.
/\d+/g
It is find digits those are middle of your string