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I have Data like this
0266-VN22.5P-AC
0292-VN22.6P-BC
0300-VN22.7P-CC
0316-VN22.8P-DC
I want to remove everything before first hypen and result should look like this
VN22.5P-AC
VN22.6P-BC
VN22.7P-CC
VN22.8P-DC
Any help would be much appreciated.
Try:
gsub("^[^\\-]+\\-", "", "0266-VN22.5P-AC")
Non-greedy search. The question mark is the magic:
sub(".*?-", "", x)
#[1] "VN22.5P-AC" "VN22.6P-BC" "VN22.7P-CC" "VN22.8P-DC"
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I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks
You should try:
^word\/?$
See this demo
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I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
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I need to convert string like this to
ABC_464_aDE.hmi_2df
to ABC464aDE.* that is want to remove all _ and add * at the end after dot. And my project requirement is to do this using regex. Please help to sort this out.
Thanks
If you are using C# the you can use this code
txt=Regex.Replace(txt.Replace("_",""), #"\.\w+", "");
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I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks
I have triedgsub("^#",'',iii), and it works
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can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx
\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26