Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 9 years ago.
Improve this question
Ok, so it's late on a Wed night and this is for no good reason. But I'd like to see one in any dialect, if it exists, just to be impressed.
[Rr][eE3][gG][uU][Ll][aA4][rR]\s[Ee3][xX][pP][rR][eE3][Ss5]{2}[iI1][Oo0][nN][sS5]
Related
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 3 days ago.
Improve this question
I have been trying with ^(word?(\/))$ but no success
There is no need to consider quotation marks
You should try:
^word\/?$
See this demo
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
I am trying to extract word General using Pyspark regex from the following string:
:52.089;emailI_Pm|T(General)|20000;ml2736
How can I do it?
Thanks
re.match(r".*\((.*)\).*", ":52.089;emailI_Pm|T(General)|20000;ml2736")[1]
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 3 years ago.
Improve this question
I need a regular expression that will find:
F.01,
F1.01,
F9.99,
F10.01,
And any decimal to the second place in between.
You can use this pattern
F\d+\.\d\d$
for most of the platforms it should work
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I have a string which has a hastag/pound/octothorpe in it, and want it removed using a regex expression.
e.g.
iii <- '#lkdjljf, lkdflsdkf'
i would like a gsub(regex_bit_here,'',iii)
to remove the hastag/pound/octothorpe
Thanks
I have triedgsub("^#",'',iii), and it works
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 7 years ago.
Improve this question
can someone please show me to how to capture the number (23456) in this URL using Regex.
http://www.examplweb.com/data/23456/my-test-45-check-out.aspx
\b\d+(?=\/[^\/]*$)
Try this.See demo.
https://regex101.com/r/eS7gD7/26