Apologies in advance for the confusing title. My issue is as follows, I have the following text in about 600 files:
$_REQUEST['FOO']
I would like to replace it with the following:
$this->input->post('FOO')
To clarify, I am matching against the following:
$_REQUEST any number of A-Za-z\d followed by a ]
and replacing it with:
$this->input->post( the alphanumeric word from above followed by a )
Or in general:
Anchor token TEXT TO KEEP end anchor token
This differs from standard find/replace as I want to retain text inside of two word boundaries.
Is this functionality present in any text editors (Eclipse,np++,etc). Or am I going to need to write some type of program to parse these 600 files to make the replacement?
s/\$__REQUEST\[(.*?)]/$this->input->post(\1)/
The .*? will match everything from [ to the first ] rather than the last although it's unlikely that it will matter in this case.
By the way the PHP superglobal is $_REQUEST rather than $__REQUEST
You can do this in Notepad++ using regular expressions. Replace
\$_REQUEST\['([^']*)'\]
with
$this->input->post('$1')
If you ever have double-quotes too, you can do use a more complex expression to handle both cases, though I'm not sure Notepad++ supports backreferences; replace
\$_REQUEST\[(['"])(.*?)\1\]
with
$this->input->post($1$2$1)
Note that I've reverted to using #ExplosionPills' suggested (.*?) here—it may be better, actually.
Related
I use Notepad++,
i need to search and replace entire word that contain a specific keyword.
Ex: someting HELP.blablabla.blabla someting
i would like to search entire text for words that contain the keyword "HELP" untill the first space OR the first comma.
In this case: HELP.blablabla.blabla
thanks a lot
Go to the search panel, check the regex checkbox on the bottom and try: (HELP)([^ ,]*)
Note: There are a space character after the ^
This regex means: Search for the entire word HELP (HELP) followed by anything that it isn't an space or an comma [^ ,] the ^ inside the brackets is a denial
Edit:
You can use just HELP[^ ,]* the parenthesis is just to create capturing groups if you need to use the specific groups to replace later. As pointed by #alphabravo
You say search and replace an entire word but if it were that simple then I wonder why a regular search and replace isn't sufficient. So I'm reading between the lines and assuming you want to match on full lines of text.
I think I've used npp enough to get the syntax right. I don't remember any eccentricities that would apply. Is the comma/space optional?
^[^, ]*HELP[^, ]*[, ]
I'm kinda thinking this one might be good enough:
^[^, ]*HELP
I am searching through a 1.5 million line Premiere Pro project for any text that matches one of my audio filters and is set to mono.
Text that I am searching for begins with the <ChannelType> tag and ends with the <FilterMatchName>Tags. So it would looks like this
<ChannelType>0</ChannelType>
<FrameRate>5292000</FrameRate>
</AudioComponent>
<FilterPreset>0</FilterPreset>
<OpaqueData Encoding="base64" Checksum="53060659">AAAAAD8L8lo+AUr+Pac1NjwTmoUAAAAAP0uQDD37nIg9ui6MPjwU5j+AAAA+C/JaAAAAAD8qqqsAAAAAP4AAAD92L8w9py8FAAAAAHNvZnQgY29tcHJlc3Npb24AIiBkZWZhdWx0PSIwIiBzdGVwPSIxIiBtaW49IjAiIG1heD0iMSIvPgoJICA8Zmw=</OpaqueData>
<FilterIndex>-1</FilterIndex>
<FilterMatchName>1094998321 Dynamics1</FilterMatchName>
If I were in a Word doc, I would just do a find as
<ChannelType>0</ChannelType>*<FilterMatchName>1094998321 Dynamics1</FilterMatchName>
I am terrible with Regex. I was hoping someone could help me out. Everything I have tried either doesn't match anything, or matches EVERYTHING in the document. I am using Notepad++.
Since you are working in Notepad++, you have access to PCRE regular expressions. This one will get all the text between <ChannelType> and </FilterMatchName>
(?s)<ChannelType>.*?</FilterMatchName>
the (?s) allows the . to match newline characters
After matching <ChannelType>, the .*? lazily matches all characters up to...
the closing </FilterMatchName>, which we match.
Let me know if you have any questions. :)
What type of regular expressions are you using (which language/library)?
Basically you can use .* instead of * in regular expressions. IF your text is long though, it's better to use a Reluctant quantifier[1] if your re implementation allows it.
This is a good site with comparison of different re implementations and tutorials:
http://www.regular-expressions.info
[1] http://docs.oracle.com/javase/tutorial/essential/regex/quant.html
I got a string like this:
PREFIX-('STRING WITH SPACES TO REPLACE')
and i need this:
PREFIX-('STRING_WITH_SPACES_TO_REPLACE')
I'm using Notepad++ for the Regex Search and Replace, but i'm shure every other Editor capable of regex replacements can do it to.
I'm using:
PREFIX-\('(.*)(\s)(.*)'\)
for search and
PREFIX-('\1_\3')
for replace
but that replaces only one space from the string.
The regex search feature in Notepad++ is very, very weak. The only way I can see to do this in NPP is to manually select the part of the text you want to work on, then do a standard find/replace with the In selection box checked.
Alternatively, you can run the document through an external script, or you can get a better editor. EditPad Pro has the best regex support I've ever seen in an editor. It's not free, but it's worth paying for. In EPP all I had to do was this:
search: ((?:PREFIX-\('|\G)[^\s']+)\s+
replace: $1_
EDIT: \G matches the position where the previous match ended, or the beginning of the input if there was no previous match. In other words, the first time you apply the regex, \G acts like \A. You can prevent that by adding a negative lookahead, like so:
((?:PREFIX-\('|(?!\A)\G)[^\s']+)\s+
If you want to prevent a match at the very beginning of the text no matter what it starts with, you can move the lookahead outside the group:
(?!\A)((?:PREFIX-\('|\G)[^\s']+)\s+
And, just in case you were wondering, a lookbehind will work just as well as a lookahead:
((?:PREFIX-\('|(?<!\A)\G)[^\s']+)\s+
You have to keep matching from the beggining of the string untill you can match no more.
find /(PREFIX-\('[^\s']*)\s([^']*'\))/
replace $1_$2
like: while (/(PREFIX-\('[^\s']*)\s([^']*'\))/$1_$2/) {}
How about using Replace all for about 20 times? Or until you're sure no string contains more spaces
Due to nature of regex, it's not possible to do this in one step by normal regular expression.
But if I be in your place, I do such replaces in several steps:
find such patterns and mark them with special character
(Like replacing STRING WITH SPACES TO REPLACE with #STRING WITH SPACES TO REPLACE#
Replace #([^#\s]*)\s to #\1_ server times.
Remove markers!
I studied a little the regex tool in Notepad++ because I didn't know their possibilities.
I conclude that they aren't powerful enough to do what you want.
Your are obliged to learn and use a programming language having a real regex capability. There are a number of them. Personnaly, I use Python. It would take 1 mn to do what you want with it
You'd have to run the replace several times for each space but this regex will work
/(?<=PREFIX-\(')([^\s]+)\s+/g
Replace with
\1_ or $1_
See it working at http://refiddle.com/10z
I just stumbled on a case where I had to remove quotes surrounding a specific regex pattern in a file, and the immediate conclusion I came to was to use vim's search and replace util and just escape each special character in the original and replacement patterns.
This worked (after a little tinkering), but it left me wondering if there is a better way to do these sorts of things.
The original regex (quoted): '/^\//' to be replaced with /^\//
And the search/replace pattern I used:
s/'\/\^\\\/\/'/\/\^\\\/\//g
Thanks!
You can use almost any character as the regex delimiter. This will save you from having to escape forward slashes. You can also use groups to extract the regex and avoid re-typing it. For example, try this:
:s#'\(\\^\\//\)'#\1#
I do not know if this will work for your case, because the example you listed and the regex you gave do not match up. (The regex you listed will match '/^\//', not '\^\//'. Mine will match the latter. Adjust as necessary.)
Could you avoid using regex entirely by using a nice simple string search and replace?
Please check whether this works for you - define the line number before this substitute-expression or place the cursor onto it:
:s:'\(.*\)':\1:
I used vim 7.1 for this. Of course, you can visually mark an area before (onto which this expression shall be executed (use "v" or "V" and move the cursor accordingly)).
I have some text like this:
dagGeneralCodes$_ctl1$_ctl0
Some text
dagGeneralCodes$_ctl2$_ctl0
Some text
dagGeneralCodes$_ctl3$_ctl0
Some text
dagGeneralCodes$_ctl4$_ctl0
Some text
I want to create a regular expression that extracts the last occurrence of dagGeneralCodes$_ctl[number]$_ctl0 from the text above.
the result should be: dagGeneralCodes$_ctl4$_ctl0
Thanks in advance
Wael
This should do it:
.*(dagGeneralCodes\$_ctl\d\$_ctl0)
The .* at the front is greedy so initially it will grab the entire input string. It will then backtrack until it finds the last occurrence of the text you want.
Alternatively you can just find all the matches and keep the last one, which is what I'd suggest.
Also, specific advice will probably need to be given depending on what language you're doing this in. In Java, for example, you will need to use DOTALL mode to . matches newlines because ordinarily it doesn't. Other languages call this multiline mode. Javascript has a slightly different workaround for this and so on.
You can use:
[\d\D]*(dagGeneralCodes\$_ctl\d+\$_ctl0)
I'm using [\d\D] instead of . to make it match new-line as well. The * is used in a greedy way so that it will consume all but the last occurrence of dagGeneralCodes$_ctl[number]$_ctl0.
I really like using this Regular Expression Cheatsheet; it's free, a single page, and printed, fits on my cube wall.